When you mix solutions of Lead ( II ) , Nitrate and Potassium Iodide

(i) What is the colour of the precipitate form ? Name then compound involved. (ii) Write the balanced chemical equation for the reaction. (iii) What type of chemical reaction has taken place and why ?

When the solutions of lead nitrate and potassium iodide are mixed together, then

(1) a yellow precipitate of potassium iodide is formed.

(2) The balanced chemical reaction for the said reaction is shown as follows

 Pb(NO3)2 + 2KI ---------> 2KNO3 + PbI2 (↓)

(3) The chemical reaction of this type is termed as a double displacement reaction as the two involved compounds have exchanged their respective ions. For example, the Pb+2 ion was associated with the NO3- ion before the reaction. After the reaction, it forms a compound with the I- ion. Similarly, the potassium ion, which was earlier associated with the I- ion is associated with the NO3- ion after the reaction.

@ Suril and Medha, very good attempt. Keep it up!!!!

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 the precipitate wiill be yellow color

double displacement

because potassium is more ractive than lead

  • -9

the formula of lead iodide is PbI2 and that of potassium nitrate is KNO3.

reaction is as follows-

Pb(NO3) + KI =KNO3 + PbI2

yes the precipitate is yellow in colour...

double displacement reaction

because when they are mixed,they exchange their ions...

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