which is cheaper :40%HCl at the rate of 50 paise per kg or 80%sulphuric acid at the rate of 25 paise per kg to completely neutralize 7 kg of caustic potash?
Reaction of HCl with NaOH and H2SO4:
HCl + KOH → KCl + H2O
36.5 56
H2SO4 + 2KOH → K2SO4 + 2H2O
98 56 x 2
It can be seen that
56 g of KOH is neutralized by 36.5 g of HCl
Therefore,
7000 g of KOH will be neutralized by 36.5/56 x 7000 = 4562.5 g = 4.56 Kg HCl
So price of 4.56 Kg HCl = 4.56 x 50 paise = 228 paise
And
56 x 2 = 112 g of KOH is neutralized by 98 g of H2SO4
Therefore,
7000 g of KOH will be neutralized by 98/112 X 7000 = 6125 g = 6.12 Kg of H2SO4
So price of 6.1 Kg H2SO4= 6.1 x 25 paise = 152.5 paise
Thus, H2SO4 is cheaper.