Which of the following complexes will have 4 isomers
a) [Co(en)(NH₃)₂Cl₂]Cl
b) [Co(PPh₃)₂(NH₃)₂Cl₂]Cl
c) [Co(en)₃]Cl₃
d) [Co(en)₂Cl₂]Br
is there any method to calculate them without checking all the structures ... some sort of shortcut ?

Question

Which of the following complexes will have 4 isomers
a) [Co(en)(NH3)2Cl2]Cl
b)
[Co(PPh3)2(NH3)2Cl2]Cl

c) [Co(en)3]Cl3
d) [Co(en)2Cl​2]Br
is there any method to calculate them without checking all the
structures some sort of shortcut ?

Vartika Jain · Accepted Answer

Dear Student,

No, there is no shortcut to check the number of isomers
(a) will have four different types of isomers
<img alt="" src=
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style="width: 274px; height: 216px;">

Which of the following complexes will have 4 isomers a) [Co(en)(NH3)2Cl2]Cl b) [Co(PPh3)2(NH3)2Cl2]Cl c) [Co(en)3]Cl3 d) [Co(en)2Cl​2]Br is there any method to calculate them without checking all the structures ... some sort of shortcut ?

Which of the following complexes will have 4 isomers
a) [Co(en)(NH₃)₂Cl₂]Cl
b) [Co(PPh₃)₂(NH₃)₂Cl₂]Cl
c) [Co(en)₃]Cl₃
d) [Co(en)₂Cl₂]Br
is there any method to calculate them without checking all the structures ... some sort of shortcut ?