# Which of the following equations has the sum of it's roots as 3 ?(a) 2x2 - 3x + 6 = 0(b) -x2 + 3x-3 = 0(c) rt2x2 - 2/rt2 x +1 = 0(d) 3x2 - 3x + 3 = 0

Sum of the roots of the equation is given by .

Thus, the sum of the roots of the equation  is given by

The sum of the roots of the equation is given by

The sum of the roots of the equation is given by

The sum of the roots of the equation is given by

Therefore, only in option (b), that is for the equation , the sum of the roots is given by 3.

Hence option (b) is the correct answer.

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We know that the sum of the roots of an equation = -b/a

In option (b)

a= -1, b= 3

Sum of the roots = -(3)/-1 = 3 Which is what we wanted.

In the rest of the equations -b/a is not equal to 3.

Cheers Parita.

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