Which of the following shows the correct order of paramagnetism?
- N > Al > O > Ca
- N > O > Al > Ca
- O > N > Al > Ca
- O > N > Ca > Al
Aslso provide the reason.....
Dear Student
Greater the number of unpaired electrons greater will be the amount of paramagnetism.
(i) Electronic configuration nitrogen will be 1s22s22p3 which means it has 3 unpaired electron.
(ii) Electronic configuration aluminium will be 3s23p1 which means it has 1 unpaired electron.
(iii)Electronic configuration oxygen will be 2s22p4 which means it has 2 unpaired electron.
(iv) Electronic configuration calcium will be 4s2 which means it has 0 unpaired electron.
Hence the correct ans is 2
Greater the number of unpaired electrons greater will be the amount of paramagnetism.
(i) Electronic configuration nitrogen will be 1s22s22p3 which means it has 3 unpaired electron.
(ii) Electronic configuration aluminium will be 3s23p1 which means it has 1 unpaired electron.
(iii)Electronic configuration oxygen will be 2s22p4 which means it has 2 unpaired electron.
(iv) Electronic configuration calcium will be 4s2 which means it has 0 unpaired electron.
Hence the correct ans is 2