which term of an AP 3,15,27,39............ will 132 more than its 54^{th} term

a = 3

d = 15 - 3 = 12

an = a + (n-1)d

a_{54 }+ 132 _{ }= 32 + 53 * 12 + 132

= 32 + 636 + 132 = 800

a_{n} = 800

800 = 32 + (n-1) 12

768 = (n-1)12

n-1 =738 / 12 = 64

n = 64 + 1 = 65

therefore , 65th term is 132 more than 54th term