Which term of AP:121,117,113,......., is its first negative term?

 a=121, d=-4, let an=0

an=a+(n-1)d

0=121+(n-1)(-4)

-121=-4n+4

-125=-4n

n=31.25

since n has to be a whole no., therefore, the ans is 32 ( the no. next to 31.25)

hence the 32nd term is the first negative term

  • 97

dis s easy ryt..............

  • -24
a = 125
d = -4

n. = first negative term
an = -3

an = a + (n - 1)d
-3 = 125 + (n - 1)(-4)
-3. = 125 -4n + 4
-3. = 129 - 4n
4n = 129 + 3
4n = 132
n = 132 4
n = 33
  • -16
weruil,mnb
  • -20
thnxx guys. Day after tommorow is my exam and u guys help a lot
 
  • -16
an<0
a+(n-1)d<0
121+(n-1)(-4)<0
121-4n+4<0
125-4n<0
125<4n
125/4=n
31.2=n
n=32

 
  • 26
magia
  • -17
i don't know the answer
  • -23
Yut
  • -20
negative term so a=(n-1)d is <0 process
  • -3
an
  • -4
What are you looking for?