Which term of the sequence 8-6i,7-4i,6-2i,...... is (i) purely real (ii) purely imaginary?

REAL PART=0

8,7,6...

an=a+(n-1)d

0=8+(n-1)(-1)

8-n+1=0

n=9

9th term will be purely imaginary.

im part=0

6,4,2...

an=6 + (n-1)(-2)

6-2n+2=0

2n=8

n=4

4th term is purely real.

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sequence of imaginary part, 6i, 4i, 2i, ...

to make the term real we must have, Im(part) = 0i = 0

since, 6i, 4i, 2i, ... forms an APwith a = 6i and c.d = -2i

so taking, tn = 0 = a+(n-1)d

0 = 6i + (n - 1 ) (-2i)

n = -6i/-2i + 1 = 3 +1 = 4

hence the real term is the 4rth term..ans

semilerly, imaginary term = tn=a + (n-1)d

0=8+(n-1)(-1)

8-n+1=0

n=9

hence, imginary term =9th term.

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