Whst weight of kmno4 will be required yo prepare 250ml of its N/10solution.weight of kmno4 is 31.6 g

dear student,

equivalent weight of kMno4 = 31.6g
normality of solution (N) = 1/10
volume of solution (v) = 250 ml

w = NEV/1000 = w = 1/10 * 31.6*250/1000 = 0.79 g


regards