Why fluoride ion is the weakest reducing agent..?
Hi Sushma,
Please find below the solution to the asked query:
Stronger is the reducing agent the weaker will be its corresponding oxidizing agent. Hence, as fluorine gas is a strong oxidizing agent and its corresponding F- is a weak reducing agent. As we know that, in order to be good reducing agent it need to efficiently oxidise itself. But the flouride ion is found to be difficult to oxidise. It is due to the small size of the fluoride ion, which brings the positive and negative ions very close to each other and therefore strongly attracted to each other, and this gives them comparatively high lattice enthalpy.
Hope this information will clear your doubts about Electrochemistry.
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Please find below the solution to the asked query:
Stronger is the reducing agent the weaker will be its corresponding oxidizing agent. Hence, as fluorine gas is a strong oxidizing agent and its corresponding F- is a weak reducing agent. As we know that, in order to be good reducing agent it need to efficiently oxidise itself. But the flouride ion is found to be difficult to oxidise. It is due to the small size of the fluoride ion, which brings the positive and negative ions very close to each other and therefore strongly attracted to each other, and this gives them comparatively high lattice enthalpy.
Hope this information will clear your doubts about Electrochemistry.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Best Wishes !