why is Ionic radius of Sb and Bi are very less when compared to the ionic radius of N,P and As ?
Hi Divyansh,
Please find below the solution to the asked query:
Ionic radius increases on going downwards in any group. In group 15, the last elements Sb and Bi have ionic radii lesser than the rest of its elements i.e N,P and As. This is because Sb and Bi have completely filled d and f sub-shells which have least shielding effect. Thus they do not guard the valence electrons to a greater extent due to which the valence electrons feel almost whole nuclear charge. This results into attraction of valence electrons towards nucleus and hence size decreases.
Hope this information will clear your doubts about why Ionic radius of Sb and Bi are very less when compared to the ionic radius of N,P and As /
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
Ionic radius increases on going downwards in any group. In group 15, the last elements Sb and Bi have ionic radii lesser than the rest of its elements i.e N,P and As. This is because Sb and Bi have completely filled d and f sub-shells which have least shielding effect. Thus they do not guard the valence electrons to a greater extent due to which the valence electrons feel almost whole nuclear charge. This results into attraction of valence electrons towards nucleus and hence size decreases.
Hope this information will clear your doubts about why Ionic radius of Sb and Bi are very less when compared to the ionic radius of N,P and As /
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards