will it will be correct if in 16a2 âˆ 25b2 + 60bc âˆ 36c2, we do it this - Maths - Factorisation

Question

will it will be correct if in 16a
2 âˆ’
25b 2 +
60bc âˆ’ 36c
2 , we do it this way
->
(4a) 2
- (25b 2 - 60bc + 36c 2
)
(4a)2 - {(5b)2 - 2(30)(bc)+
36c2)
4(a)2 - {(5b)2 - 2
(30)(bc)+(6c)2 }
(4a)2 - (5b - 6c)2

Rayya Halim · Accepted Answer

yes it is correct in this way
(4a) 2
- (25b 2 - 60bc + 36c 2
)
=(4a)2 - {(5b)2 - 2(30)(bc)+
36c2)
=4(a)2 - {(5b)2 - 2
(30)(bc)+(6c)2 }
=(4a)2 - (5b - 6c)2
and the last step will
be
= ( 4a - 5b + 6c )( 4a + 5b - 6c)

will it will be correct if in 16a 2 − 25b 2 + 60bc − 36c 2 , we do it this way -> (4a) 2 - (25b 2 - 60bc + 36c 2 ) (4a)2 - {(5b)2 - 2(30)(bc)+ 36c2) 4(a)2 - {(5b)2 - 2 (30)(bc)+(6c)2 } (4a)2 - (5b - 6c)2

will it will be correct if in 16a ² − 25b ² + 60bc − 36c ² , we do it this way ->

(4a) ² - (25b²- 60bc + 36c ²)

(4a)²- {(5b)² - 2(30)(bc)+ 36c²)

4(a)² - {(5b)² - 2 (30)(bc)+(6c)² }

(4a)² - (5b - 6c)²