Will the reaction I2 + H2S -> 2HI + S proceed spontaneously at 298K. dGfH for HI is 1.8kJ/mol and H2S is 38.3kJ/mol

Dear Student
 When delta G is negative then reaction proceed.
In the above case delta G = G of product - G of reactant
Here G of product = 1.8 KJ/mol
And G of reactant = 38.3 KJ/mol
​So delta G = (1.8 - 38.3) KJ/mol = 36.5 KJ/mol
As delta G is negative so above reaction proceeds spontaneously.


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