without expanding, prove that :- (row wise) |(cosec2​ θ  cot2 θ  1) (cot2 θ  cosec2  θ  -1) (42 40 2)| = 0

Dear Student,We have,Let  = cosec2θcot2θ1cot2θcosec2θ-142402Apply, C1C1-C2-C3 = cosec2θ-cot2θ-1cot2θ1cot2θ-cosec2θ+1cosec2θ-142-40-2402Now, 1+cot2θ=cosec2θ=cosec2θ-cosec2θcot2θ1cosec2θ-cosec2θcosec2θ-10402=0cot2θ10cosec2θ-10402We know that, If all the elements of any particular row or any particular column are zero then the value of the determinant is also zero.As coloumn 1 consists of only zero.Therefore, =0.Regards
 

  • 10
What are you looking for?