Without expanding, show that the given determinant is equal to 0:

Dear Student,

the given matrix is a skew symmetric matrix since, leading diagonal elements are 0.
A'=-Adet(A')=det(-A)det(A')=(-1)ndet(A) [since det(A')=det(A)det(A)=(-1)ndet(A)therefore if n is odd, then det(A)=0the order of given determinant is 3×3n = 3, det(A)=(-1)3det(A)det(A)=-det(A)2det(A)=0det(A)=0thus given det(A) =0

Regards!

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