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Without expanding the determinants show that :

42 1 6

28 7 4

14 3 2

=0

⇒ Δ = 7 × 0   (If any two rows(or columns) of a square matrix are identical, then its determinant is zero)

⇒ Δ = 0

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all the elements in column one can be written as the multiple of 7 so it becomes 

7( 6) , 7(4) , 7(2) so  now 7 can be taken outside as common frm column 1 

Now C1 and C3 becomes identical ....and hence determinant becomes ZERO :

 hope it helps :) 

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can be written as        7(6)  1  6  .

                                      7(4)   7  4 

                                      7(2)  3  2    take 7 common .now c1 c2 r identical

therefore ans is zero

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