Work function WA for a photoelectric material A is 2 eV WB for another photoelectric material B is - Chemistry - Atomic Structure

Question

Work function WA for a photoelectric material A is 2 eV & WB
for another photoelectric material B is 4 eV If the photons of
energy EA strike with surface of A the ejected photoelectrons have
minimum de-Broglie length Lambda-A and photons of energy EB strike
the surface of B, the ejected photoelectrons have minimum
de-Broglie wavelength Lambda-B Where EB=(EA+0 5) eV and
Lambda-B=2(Lambda-A), VA and VB are respective stopping potentials
then which of the following is not correct (A) EA=4 ev (B) EA=4 5
eV (C) VA=2 Volts (D) VB=0 5 Volts

Yasodharan · Accepted Answer

Dear Student,

From the question statement and given options EB = (EA + 0 5)eV =
4+0 5 = 4 5 eV hence Option (B) is incorrect as it is mentioned as
EA = 4 5eV

Regards