Work function WA for a photoelectric material A is 2 eV & WB for another photoelectric material B is 4 eV. If the photons of energy EA strike with surface of A the ejected photoelectrons have minimum de-Broglie length Lambda-A and photons of energy EB strike the surface of B, the ejected photoelectrons have minimum de-Broglie wavelength Lambda-B. Where EB=(EA+0.5) eV and Lambda-B=2(Lambda-A), VA and VB are respective stopping potentials then which of the following is not correct (A) EA=4 ev (B) EA=4.5 eV (C) VA=2 Volts (D) VB=0.5 Volts

Dear Student,

From the question statement and given options EB = (EA + 0.5)eV = 4+0.5 = 4.5 eV hence Option (B) is incorrect as it is mentioned as EA = 4.5eV

Regards.

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