Write 7 4-digit numbers, which are divisible by 3, using the digits 4,5,9 & 0 only once.
The given digits are 4, 5, 9, 0.
We know that a number is divisible by 3 if the sum of the digits of the number is divisible by 3.
We see that 4 + 5 + 9 + 0 = 18 which is divisible by 5.
Hence, the numbers can be formed by using the digits 4, 5, 9, 0 as :
(1) 4590
(2) 4509
(3) 4950
(4) 4905
(5) 4059
(6) 4095
(7) 9540
(8) 9045 etc.