write in a+ib form √-4(√-9 + 3)+√-49(i3+√3)-√-36(2-√-121)+√5i5

Dear Student,
We have,-4-9+3+-49i3+3--362--121+5i5As, we know that -1=i2, then;we can write it as,4i29i2+3+49i2i3+3-36i22-121i2+5i52i3i+3+7i-i+3-6i2-11i+5i   As, i3=-i and i5=i2×i2×i=i6i2+6i-7i2+73i-12i+66i2+5i6i2+-7i2+66i2+6i+73i-12i+5i-6+7-66-6i+73i+5i-65+73+5-6i

Regards.

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