write the 5th and 8th terms of an A.P whose 10th term is 43 and common difference is 4.
We are given.
a10 = 43
or
a + 9d = 43 ( d is common difference here)
a + 9 (4) = 43 ( d = 4)
a = 43-36
a = 7
Now,
a5 = a + 4d
a5 = 7 + 4(4)
a5 = 23
Similarly,
a8 = a + 7d
a8 = 7 + 7(4)
a8 = 35
a10 = 43
or
a + 9d = 43 ( d is common difference here)
a + 9 (4) = 43 ( d = 4)
a = 43-36
a = 7
Now,
a5 = a + 4d
a5 = 7 + 4(4)
a5 = 23
Similarly,
a8 = a + 7d
a8 = 7 + 7(4)
a8 = 35