x^2 + 4kx + (k^2 - k + 2) = 0
solve for k when the equation has equal roots i.e. D=0

Question

x^2 + 4kx + (k^2 - k + 2) = 0
solve for k when the equation has equal roots i e D=0

Atul Shaw · Accepted Answer

Dear student,x2+4kx+(k2-k+2)=0Here, a=1; b=4k; c=k2-k+2D=b2-4ac=04k2-4×1×(k2-k+2)=04k2-k2+k-2=03k2+k-2=03k2+3k-2k-2=03k(k+1)-2(k+1)=0(3k-2)(k+1)=0k=-1 and 23Regards

x^2 + 4kx + (k^2 - k + 2) = 0 solve for k when the equation has equal roots i.e. D=0

x^2 + 4kx + (k^2 - k + 2) = 0
solve for k when the equation has equal roots i.e. D=0