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[x-40],[x-20] and [x+2-10] ARE THE ANGLES OF A TRIANGLE FIND THE ANGLES AND THE VALUE OF X

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Sum of angles of a triangle is 180°

the angles are (x-40) , (x-20) and (x/2 - 10).

Sum = (x-40) + (x-20) + (x/2 - 10) = 180
⇒ 5x/2 - 70 = 180
⇒ 5x/2 = 180+70 = 250
⇒ x = 250×2/5 
⇒ x = 100

Angles are:
x-40 = 100 - 40 = 60
x - 20 = 100 - 20 = 80
x/2 - 10 = 100/2 - 10 = 40
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SUM OF ANGLES OF A TRIANGLE IS 180 DEGREE.
THE ANGLES ARE (X-40)+(X-20) AND (X/2-10)=180 DEGREE
=>5x/2-70=180
=>5x/2=180+70=250
=>X=250*2/5
=>X=100


ANGLES ARE
X-40=100-40=60
X-20=100-20=80
X/2-10=100/2-10=40


IN PLACE OF (X+2-10),IT WILL BE X/2-10.

PLEASE CHECK IT AGAIN..
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