x=asint and y= a( cost +log tant/2) Find d2y/dx2 Share with your friends Share 12 Mayank answered this x = a sin t⇒dxdt = a cos tNow, y = a cos t + log tan t/2⇒dydt = a-sin t + sec2t/22 tan t/2⇒dydt = a- sin t + 1sin t = a1- sin2tsin t = a cos2tsin tNow, dydx = dydt × dtdx = a cos2tsin t × 1a cos t = cot td2ydx2 = - cosec2t × dtdx =- cosec2t × 1a cos t = -cosec2ta cos t 63 View Full Answer
