X is a point on side BC of triangle ABC . XM and XN are drawn parallel to AB and AC respectively meeting AB in N and AC in M . MN produced meets CB produced at T . Prove that TX^2 = TB.TC Share with your friends Share 0 Saksham Tolani answered this Dear Student, GIVEN :PQR is a ∆, in which side QR is produced to point T.Also, LN∥PQ and LM∥PR.TO PROVE : TX2 = TB × TCPROOF : In ∆ TXM, we have, BN∥XM, so, TBTX = NTMT By BPT theorem-----(1)Now, In ∆ TMC, we haveTXTC=TNTM-----(2)From (1) and (2),TBTX=TXTCTX2=TB×TC Regards! 0 View Full Answer Rohan Kumar answered this Please find this answer 2 Rohan Kumar answered this If this answer helpful, then experts please upvote my answer. 1
