(x2+3x - 2)2 -8(x2+3x) -4=0. Find x by quadratic formula.

Hi, Let x2+3x= t x2+3x-22-8x2+3x-4=0 t-22-8t-4=0t2+4-4t-8t-4=0t2-12t=0tt-12=0t = 0 , 12 so x2+3x=0 and x2+3x-12=0xx+3=0 and x = -3±9+482x = 0 , -3 and x =-3±572 Regards

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yep
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what
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