Hello Sanjani dear, let x^3 = k then x^6 = k^2
Thus we can write the given as
k^2 - 26 k - 27
Or k^2 - 27 k + k - 27
==> k(k - 27) + 1( k - 27)
==> (k - 27) ( k + 1)
Replace x^3
So we have x^3 - 27 and x^3 + 1
Or x^3 - 3^3 and x^3 + 1
Recall a^3 - b^3 = ( a - b) ( a^2 + ab + b^2)
And a^3 + b^3 = ( a + b) ( a^2 - ab + b^2)
Hope you would do the rest in the best way
