y=ln(x+e) x=ln(1/y) area enclosed between the curves and the x axis Share with your friends Share 0 Anuradha Sharma answered this For getting the intersection point, y = lnx+ex = ln1y⇒y = e-xor e-x= lnx+e1 = ex lnx+e ⇒ 1= lnx+eexor x+eex=e1here we can see that x = 0 is one of the solution as, 0+ee0=e1 ⇒ e1=e1 at x = 0 we get y = ln0+e=1So 0,1 is one of the intersection point but here from the graph we can see that they are not intersecting at 0,1. And finding the intersection point A is not possible by the method available till your grade So kindly recheck the question -14 View Full Answer