Yellow light of wavelenght 6000A produces fringes of width 0.8mm in Youngs double slit experiment. What will be the fringe width if the light source is replaced by another light of wavelenght 7500 A and the separation between the slits is doubled?ll be the

Dear Student,
Please find below the solution to the asked query:
 Fringe width:β=λDdwhereλ=Wavelengthd=Distance between the slitsD=Distance between slits and screenHence,β2β1=λ2λ2×d1d2β2=0.8×75006000×d12d1    =0.5 mm
Hope this information will clear your doubts about Fringe width.
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