You are given an element 7X14.Find out.
a.1.number of protons,electronsneutrons in X
a.2.valency of X
a.3.electronic configuration of X.
b.If Bromine atom is available in the form of, say two isotopes
35BR79 (49.7%) 35BR82 (50.3%).
Given: 7X14
i.e atomic no. = 7 and mass no. = 14.
Mass no. = no. of protons + neutrons
Atomic no. = no.of protons/electrons.
Thus no. of protons = electrons = 7
No. of neutrons = 14 -7 = 7
Valency = 3
electronic config = 2,5
i.e atomic no. = 7 and mass no. = 14.
Mass no. = no. of protons + neutrons
Atomic no. = no.of protons/electrons.
Thus no. of protons = electrons = 7
No. of neutrons = 14 -7 = 7
Valency = 3
electronic config = 2,5