You have to show that ΔAMP ≅ AMQ.
In the following proof, supply the missing reasons.
| - | Steps | - | Reasons |
| (i) | PM = QM | (i) | … |
| (ii) | ∠PMA = ∠QMA | (ii) | … |
| (iii) | AM = AM | (iii) | … |
| (iv) | ΔAMP ≅ ΔAMQ | (iv) | … |
(i) Given
(ii) Given
(iii) Common
(iv) SAS, as the two sides and the angle included between thesesides of ΔAMP are equal to two sides and the angle includedbetween these sides of ΔAMQ.