Young modulus of elasticity of brass is 1011 N/m2. The increase in its energy on pressing a rod of length 0.1 m and cross-sectional area 1 cm2 made of brass with a force of 10 kg along its length, will be ...................... Share with your friends Share 6 Vipra Mishra answered this Dear Student Increase in energy∆E=12×stress×strain×volume∆E=12×FA×FA×Y×A×L∆E=12×FA×FLY=12×1010-4×10×0.11011=5×10-7 J Regards 18 View Full Answer