Algebra
Question 2:
Complete the entries in the third column of the table.
S. No. |
Equation |
Value of variable |
Equation satisfied Yes/No |
(a) |
10y = 80 |
y = 10 |
- |
(b) |
10y = 80 |
y = 8 |
- |
(c) |
10y = 80 |
y = 5 |
- |
(d) |
4l = 20 |
l = 20 |
- |
(e) |
4l = 20 |
l = 80 |
- |
(f) |
4l = 20 |
l = 5 |
- |
(g) |
b + 5 = 9 |
b =5 |
- |
(h) |
b + 5 = 9 |
b = 9 |
- |
(i) |
b + 5 = 9 |
b = 4 |
- |
(j) |
h − 8 = 5 |
h = 13 |
- |
(k) |
h − 8 = 5 |
h = 8 |
- |
(l) |
h − 8 = 5 |
h = 0 |
- |
(m) |
p + 3 = 1 |
p = 3 |
- |
(n) |
p + 3 = 1 |
p = 1 |
- |
(o) |
p + 3 = 1 |
p = 0 |
- |
(p) |
p + 3 = 1 |
P = − 1 |
- |
(q) |
p + 3 = 1 |
P = − 2 |
- |
Answer:
(a) 10y = 80
y = 10 is not a solution to the given equation because for y = 10,
10y = 10 × 10 = 100, and not 80
(b) 10y = 80
y = 8 is a solution to the given equation because for y = 8,
10y = 10 × 8 = 80 and hence, the equation is satisfied.
(c) 10y = 80
y = 5 is not a solution to the given equation because for y = 5,
10y = 10 × 5 = 50, and not 80
(d) 4l = 20
l = 20 is not a solution to the given equation because for l = 20,
4l = 4 × 20 = 80, and not 20
(e) 4l = 20
l = 80 is not a solution to the given equation because for l = 80,
4l = 4 × 80 = 320, and not 20
(f) 4l = 20
l = 5 is a solution to the given equation b...
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