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Algebra

Question 3:

Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation.

(a) 5m = 60 (10, 5, 12, 15)

(b) n + 12 = 20 (12, 8, 20, 0)

(c) p − 5 = 5 (0, 10, 5 − 5)

(d) (7, 2, 10, 14)

(e) r − 4 = 0 (4, − 4, 8, 0)

(f) x + 4 = 2 (− 2, 0, 2, 4)

Answer:

(a) 5m = 60

m = 12 is a solution to the given equation because for m = 12,

5m = 5 × 12 = 60 and hence, the equation is satisfied.

m = 10 is not a solution to the given equation because for m = 10,

5m = 5 × 10 = 50, and not 60

m = 5 is not a solution to the given equation because for m = 5,

5m = 5 × 5 = 25, and not 60

m = 15 is not a solution to the given equation because for m = 15,

5m = 5 × 15 = 75, and not 60

(b) n + 12 = 20

n = 8 is a solution to the given equation because for n = 8,

n + 12 = 8 + 12 = 20 and hence, the equation is satisfied.

n = 12 is not a solution to the given equation because for n = 12,

n + 12 = 12 + 12 = 24, and not 20

n = 20 is not a solution to the given equation because for n = 20,

n + 12 = 20 + 12 = 32, and not 20

n = 0 is not a solution to the given equatio...

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