Draw a triangle ABC with side BC = 7 cm, ∠B = 45°, ∠A = 105°. Then, construct a triangle whose sides are times the corresponding side of ΔABC. Give the justification of the construction.
∠B = 45°, ∠A = 105°
Sum of all interior angles in a triangle is 180°.
∠A + ∠B + ∠C = 180°
105° + 45° + ∠C = 180°
∠C = 180° − 150°
∠C = 30°
The required triangle can be drawn as follows.
Draw a ΔABC with side BC = 7 cm, ∠B = 45°, ∠C = 30°.
Draw a ray BX making an acute angle with BC on the opposite side of vertex A.
Locate 4 points (as 4 is greater in 4 and 3), B1, B2, B…
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