The vertices of a ΔABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB and AC at D and E respectively, such that. Calculate the area of the ΔADE and compare it with the area of ΔABC. (Recall Converse of basic proportionality theorem and Theorem 6.6 related to
ratio of areas of two similar triangles)
Therefore, D and E are two points on side AB and AC respectively such that they divide side AB and AC in a ratio of 1:3.
Clearly, the ratio between the areas of ΔADE and ΔABC i...
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