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Syllabus

1.Find the missing frequency f, if the mode of the given data is 154.

Classes

120-130

130-140

140-150

150-160

160-170

170-180

Frequency

2

8

12

f

9

7

plzz give an answer fast....

In the step deviation method,

What is the meaning of

u_{i }?what is hit and trial method .

how to calculate mode if two classes have same and highest frequency (bimodal) ?

If the median of the distribution is given below is 28.5, find the values of

xandy.Class intervalFrequency0 − 10

5

10 − 20

x20 − 30

20

30 − 40

15

40 − 50

y50 − 60

5

Total

60

marks obtained no of students

less than 10 14

less than 20 22

less than 30 37

less than 40 58

less than 50 67

less than 60 75

if the median of the following frequency distribution is 24. find the missing frequency x :

Age Number of persons

0 - 10 5

10 - 20 25

20 - 30 x

30 - 40 18

40 - 50 7

find the missing frequencies if N=100 and median is 32.

marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total

no. of students-10 ,? ,25 ,30 ,? ,10 ,100.

The median of the following distribution is 30. Find the missing frequencies f1 and f2:

Class frequency

0-10 10

10-20 10

20-30 f1

30-40 30

40-50 f2

50-60 10

Total 100

the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?

how to find the mean if the class intervals are unequal??

like fr e- 0-10,10-30,30-35....

The mean of unground data and the mean calculated when the same data is grouped are always the same. Is it true ? Give reasons.

The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______

Find the value of f1 from the following data if it's mode is 65:

Class frequency

0-20 6

20-40 8

40-60 f1

60-80 12

80-100 6

100-120 5

Where frequency 6,8, f1, and 12 are in ascending order.

how to find xi?

Find mean,mode and median of following.

Marks: Less than 30,40,50,60,70,80,90 (All less than )

No of students: 5,12,25,30,34,38,40

1 mode

2 median

3 mean

4 all of these

What is the formula to use median when more than ogive is given?

median.

Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90

frequency 10 8 12 24 6 25 15

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days0 − 6

6 − 10

10 − 14

14 − 20

20 − 28

28 − 38

38 − 40

Number of students11

10

7

4

4

3

1

Marks Below 10 Below 20 Below 30 Below 40 Below 50 Below 60 Below 70 Below 80 Below 90 Below 100

No. of students 5 9 17 29 45 60 70 78 83 85

for what value of x, the mean of the given observations 2x- 5, x +3, 7 - x, 5 - x, and x + 9 with frequencies 2, 3, 4 , 6 and 1 respectively is 4?

3 Median = Mode + 2 Mean

please proof it.

.

In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median

_{1 }, f_{2}and f_{3}in the following frequency distribution , when it is given taht f_{2 }: f_{3}= 4 : 3 , and mean = 5020-40

40-60

60-80

80-100

17

f

_{1}f

_{2}f

_{3 19}The mean and median of same data are 24 and 26 respectively. The value of mode is ?

No. of persons 200 500 900 1200 1400 1500 1550 1560

marks number of students

0 and above 80

10 and above 77

20 and above 72

30 and above 65

40 and above 55

50 and above 43

60 and above 28

70 and above 16

80 and above 10

90 and above 8

100 and above 0

The following distribution gives the daily income of 50 workers of a factory.

Daily income (in Rs)100 − 120

120 − 140

140 − 160

160 − 180

180 − 200

Number of workers12

14

8

6

10

Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.

the mean of first n odd natural numbers is n2/81,then n=

How is assumed mean calculated of even number of even number of class intervals ?

E.g.C.I. F

_{i}20-4051

40-6068

60-8024

80-10013

100-12005

120-14077

140-16036

160-18012

In this case what will be the assumed mean ? Please give reason also as to explain why u chose it ??

The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:

1. X+n

2. X+n/2

3. X+(n+1)/2

4. X+(n-1)/2

if the mean of the following frequency distribution is 91, find the missing frequency x and y :

classes frequency

0 - 30 12

30-60 21

60 - 90 x

90 -120 52

120 - 150 y

150 - 180 11

total 150

ci f

class frequency

40-50 5

50-60 x

60-70 15

70-80 2

80-90 7

how do we find mean using step deviation method if the classes are unequal?

should we make the classes equal in such a case?

In a given data if the MODAL CLASS is at the bottom(last) and has nothing Preceeding it then how will we find the MODE?

During the medical check-up of 35 students of a class, their weights were recorded as follows:

Weight (in kg)Number of studentsLess than 38

0

Less than 40

3

Less than 42

5

Less than 44

9

Less than 46

14

Less than 48

28

Less than 50

32

Less than 52

35

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.

In a certain year , the ages of 130 cardiac patients,admitted in a hospital,are given in the following distribution

Age in years

20-24

24-28

28-32

32-36

36-40

40-44

44-48

48-52

52-56

56-60

Numbers of patients

3

5

9

12

15

2

X

22

14

y

If mode of the above data is 47 find the missing frequencies x and y

Class interval Frequency0-10 10

10-20 20

20-30 x

30-40 40

40-50 y

50-60 25

60-70 15

Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 from

their mean.

Class interval Frequency10-20 12

20-30 30

30-40 f1

40-50 65

50-60 f2

60-70 25

70-80 18

no links plz.

Class. 0-5,5-10,10-15,15-20,20-25

Frequency.10,15,12,30,9

The sum of the lower limit of the media class and modal class is

the median of the data is 525. find x and y, if total frequency is 100

class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000

frequeency 2 5 x 12 17 20 y 9 7 4

(in years)

(A)

(B)

Find the modal age of employees in factory A and B.

9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing

The mean of the following frequency dristibution is 50. Find the value of

ppIf mean is

166 9/26(mixed fraction) andsum of observations is 52.Findf1 and f2.C I FREQUENCY

140 - 150 5

150 -160 f1

160 -170 20

170-180 f2

180-190 6

190-200 2

In a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.

class 0-10 10-20 20-30 30-40 40-50

frequency 5 18 15 p 6

how can we find the median by only less than ogive curve?

The median of the following data is 32.5.find the value of x and y

class interval f

0-10 x

10-20 5

20-30 9

30-40 12

40-50 y

50-603

60-70 2

total 40

The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.

Marks No. of studentsLess than 10 7

Less than 20 21

Less than 30 34

Less than 40 46

Less than 50 66

Less than 60 77

Less than 70 92

Less than 80 100

Find the mean, mode and median for the following data.

Q). Everyday a mango seller sells half of his stock, 10% of the stock gets spoiled overnight. If 1983 mangoes rot in 3 nights then how many did he start with on the first day?

(A) 25,000

(B) 24,000

(C) 30,000

(D) 32,000

The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.

Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40

Frequencies: -7 10 x 13 y 10 14 9

how to find the median class?

Find the mean number of pages written per day.

How to find missing frequency if the mode of the given data is given.

How to convert a

LESS THAN OGIVEand it'sCFinto the Frequency distribution?the daily expenditure of 100 families is given under

expenditure Number of families

0-10 14

10-20 ?

20-30 27

30-40 ?

40-50 15

given median=Rs 26.67,mode=Rs 29

calculate the missing frequencies

experts or anyone i need correct answer please it carries 5 marks

i need it today i need to submit it tomorrow

Find the class marks of classes 10 - 25 and 35 - 55.0-10. 4

10-20. 16

20-30. a

30-40. b

40-50. c

50-60. 6

60-70. 4

TOTAL. 230

If the mean of the following distributions is 27, Find the value of p

If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :

A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5

Find the median of the following data.

Wages ( in rupees ) :More than 150 , More than 140 , More than 130 , More than 120 , More than 110 , More than 100 , More than 90 . More than 80.No.of workers : NIL ,12,27,60,105,124,141,150.the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find

a) class size

b) lower limit of second class

c) upper lmit of last class

d) third class

Class- frequency

0-10 16

10-20 P

20-30 30

30-40 32

40-50 14

Total = 50

height in cm frequency cumulative frequency

150-155 12 a

155-160 b 25

160-165 10 c

165-170 d 43

170-175 e 48

175-180 2 f

The mean of the following data is 53, find the missing frequencies.

age in years -- 0-20, 20-40 40-60 60-80, 80-100

number of people--- 15, f1, 21, f2, 17, 100

9. Find the mean age in years form a frequency distribution given below: