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Syllabus

1.Find the missing frequency f, if the mode of the given data is 154.

Classes

120-130

130-140

140-150

150-160

160-170

170-180

Frequency

2

8

12

f

9

7

plzz give an answer fast....

how to calculate mode if two classes have same and highest frequency (bimodal) ?

what is hit and trial method .

classes frequency

0-100 8

100- 200 12

200-300 x

300-400 20

400-500 14

500-600 7

If the median of the distribution is given below is 28.5, find the values of

xandy.Class intervalFrequency0 − 10

5

10 − 20

x20 − 30

20

30 − 40

15

40 − 50

y50 − 60

5

Total

60

Find the value of f1 from the following data if it's mode is 65:

Class frequency

0-20 6

20-40 8

40-60 f1

60-80 12

80-100 6

100-120 5

Where frequency 6,8, f1, and 12 are in ascending order.

if the median of the following frequency distribution is 24. find the missing frequency x :

Age Number of persons

0 - 10 5

10 - 20 25

20 - 30 x

30 - 40 18

40 - 50 7

The median from the table is

value 7, 8, 9, 10, 11, 12 ,13

frequency 2, 1, 4, 5, 6, 1, 3

find the missing frequencies if N=100 and median is 32.

marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total

no. of students-10 ,? ,25 ,30 ,? ,10 ,100.

monthly consumption of electricity of some consumers is given below as a distribution. Find the missing frequency(x), if mode is given to be 200 units.

Monthly cosumption(in units ) 90-120 120-150 150-180 180-210 210-240

Number of consumers 20 15 X 75 30

The median of the following distribution is 30. Find the missing frequencies f1 and f2:

Class frequency

0-10 10

10-20 10

20-30 f1

30-40 30

40-50 f2

50-60 10

Total 100

d

_{i}is the deviation of x_{i }from assumed mean a.If mean = x + ∑f

_{i}d_{i}/∑f_{i}, then x isthe mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?

In the step deviation method,

What is the meaning of

u_{i }?how to find the mean if the class intervals are unequal??

like fr e- 0-10,10-30,30-35....

The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______

1. Observe the information's in the following cumilative frequency table

no. of days absentless than 5

less than 10

less than 15

less than 20

less than 25

less than 30

less than 35

less than 40

less than 45

No. of students29224465582634644650653655Q.. Draw a 'less than' ogive and 'more than' ogive to represent the above data .

Q... Find median for the above data by interpreting the graph.

Q...why regularity is essential in students life (VBQ)

how to find xi?

What is the formula to use median when more than ogive is given?

age no of cases

5-14 6

15-24 11

25-34 21

35-44 23

45-54 14

55-64 5

median.

Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90

frequency 10 8 12 24 6 25 15

Find the median of the following data.

Wages ( in rupees ) :More than 150 , More than 140 , More than 130 , More than 120 , More than 110 , More than 100 , More than 90 . More than 80.No.of workers : NIL ,12,27,60,105,124,141,150.A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days0 − 6

6 − 10

10 − 14

14 − 20

20 − 28

28 − 38

38 − 40

Number of students11

10

7

4

4

3

1

In a certain year , the ages of 130 cardiac patients,admitted in a hospital,are given in the following distribution

Age in years

20-24

24-28

28-32

32-36

36-40

40-44

44-48

48-52

52-56

56-60

Numbers of patients

3

5

9

12

15

2

X

22

14

y

If mode of the above data is 47 find the missing frequencies x and y

Marks Below 10 Below 20 Below 30 Below 40 Below 50 Below 60 Below 70 Below 80 Below 90 Below 100

No. of students 5 9 17 29 45 60 70 78 83 85

3 Median = Mode + 2 Mean

please proof it.

if the mean of the following frequency distribution is 91, find the missing frequency x and y :

classes frequency

0 - 30 12

30-60 21

60 - 90 x

90 -120 52

120 - 150 y

150 - 180 11

total 150

In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median

13. Find the mean, mode and median for the following data:

The mean and median of same data are 24 and 26 respectively. The value of mode is ?

Cost of living index /number of weeks

1400-1500—8

1550-1700—15

1700-1850—21

1850-2000—8

marks number of students

0 and above 80

10 and above 77

20 and above 72

30 and above 65

40 and above 55

50 and above 43

60 and above 28

70 and above 16

80 and above 10

90 and above 8

100 and above 0

Class : 50 –55 55 – 60 60 – 65 65 – 70 70 – 75 75 – 80

Frequency : 2 8 12 24 38 16

The following distribution gives the daily income of 50 workers of a factory.

Daily income (in Rs)100 − 120

120 − 140

140 − 160

160 − 180

180 − 200

Number of workers12

14

8

6

10

Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.

9 men visited a hotel, 8 of them spent Rs.4/- each over their meal and the 9th spentRs.2/- more than the average ofall the 9. The total money spent by them on the meal is ---?

how do we find mean using step deviation method if the classes are unequal?

should we make the classes equal in such a case?

the mean of first n odd natural numbers is n2/81,then n=

C.I. F

45-55 7

55-65 12

65-75 17

75-85 30

85-95 32

95-105 6

105-115 10

The following table shows the distribution of some families according to expenditure per week .the number of families for two class intervalsare missing. Median =Rs.25 , Mode = Rs.24. calculate the missing frequency and hence the find mean.

The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:

1. X+n

2. X+n/2

3. X+(n+1)/2

4. X+(n-1)/2

class frequency

40-50 5

50-60 x

60-70 15

70-80 2

80-90 7

…………………. Is called a positional average.

During the medical check-up of 35 students of a class, their weights were recorded as follows:

Weight (in kg)Number of studentsLess than 38

0

Less than 40

3

Less than 42

5

Less than 44

9

Less than 46

14

Less than 48

28

Less than 50

32

Less than 52

35

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.

Wages (in Rs) No. of Workers

0 - 30 10

30 - 40 15

40 - 50 30

50 - 60 32

60 - 70 8

70- 80 5

Class interval Frequency0-10 10

10-20 20

20-30 x

30-40 40

40-50 y

50-60 25

60-70 15

IF THE N/2 IS EQUAL TO THE CUMULATIVE FREQUENCY THEN WE WOULD REGARD THAT CLASS AS THE MEDIAN CLASS OR NOT.

_{i}=100 , h=10 and f_{i}u_{i}= -30 , then find the mean of following distribution.PLEASE ANSWER FAST.

Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 from

their mean.

Class interval Frequency10-20 12

20-30 30

30-40 f1

40-50 65

50-60 f2

60-70 25

70-80 18

no links plz.

Number of teachers 4, 3 ,18, 2, 3 Find mean and median for this data.

the median of the data is 525. find x and y, if total frequency is 100

class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000

frequeency 2 5 x 12 17 20 y 9 7 4

allotted for competition was of 100 minutes. Study the table given below and answer the

questions that follow:-

Time (Minutes) No of Students finished their painting

0-20 8

20-40 10

40-60 13

60-80 6

80-100 3

(A). Estimate the mean time taken by a student to finish the painting.

(i) 54

(ii) 63

(iii) 43

(iv) 50

(B). What will be the upper limit of the modal class ?

(i) 20

(ii) 40

(iii) 60

(iv) 80

(C). The construction of cumulative frequency table is useful in determining the

(i) Mean

(ii) Median

(iii) Mode

(iv) All of the above

(D). The sum of lower limits of median class and modal class is

(i) 60

(ii) 100

(iii) 80

(iv) 140

(E). How many students finished the Painting within an hour?

(i) 18

(ii) 37

(iii) 31

(iv) 8

9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing

Mode and mean of a data are 12k and 15k. Median of the data is

The mean of the following frequency dristibution is 50. Find the value of

ppHeight 160-162 163-165 166-168 169-171 172-174

frequency 15 117 x 118 14if the median of distribution is 167 . find the value of 'x'In a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.

If the median I.Q of the students is 135, find the missing frequencies f1 and f2 in the following frequency distribution for 220 students:

I.Q 100-110 110-120 120-130 130-140 140-150 150-160 160-170 170-180

Number of students 15 35 f1 f2 33 23 19 8

how can we find the median by only less than ogive curve?

For the following distribution :

Class 10-15 15-20 20-25 25-30 30-35Frequency 25 30 27 35 21The sum of the lower limit of the median class and the lower limit of the modal class is :(A) 45 (B) 50 (C) 55 (D) 62The median of the following data is 32.5.find the value of x and y

class interval f

0-10 x

10-20 5

20-30 9

30-40 12

40-50 y

50-603

60-70 2

total 40

_{1 }, f_{2}and f_{3}in the following frequency distribution , when it is given taht f_{2 }: f_{3}= 4 : 3 , and mean = 5020-40

40-60

60-80

80-100

17

f

_{1}f

_{2}f

_{3 19}The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.

Marks No. of studentsLess than 10 7

Less than 20 21

Less than 30 34

Less than 40 46

Less than 50 66

Less than 60 77

Less than 70 92

Less than 80 100

Find the mean, mode and median for the following data.

The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.

Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40

Frequencies: -7 10 x 13 y 10 14 9

is

7^5*3^2*5+3a composite number ?justifyif the median salary of 100 employees of a factory is 24800, then find the missing frequencies f

_{1}and f

_{2 }in the given dataSalary 10000-15000 15000-20000 20000-25000 25000-30000 30000-35000 35000-40000

frequen. 18 f1 f2 15 12 22

how to find the median class?

How to find missing frequency if the mode of the given data is given.

i)3(median)

ii)4(median)

iii)2(median)

iv)5(median)

How to convert a

LESS THAN OGIVEand it'sCFinto the Frequency distribution?the interest paid on each of the three different sums of money yeilding 1%, 2% and 4% simple interest per annum respectively, is the same. find the average yield percent on the total sum inverted.

Find the class marks of classes 10 - 25 and 35 - 55.calculate the aritemetic mean,for the following frequency distribution

class interval frequency

0-80 22

80-160 35

160-240 44

240-320 25

320-400 24

If the mean of the following distributions is 27, Find the value of p

Q1) among the following which is not the measure of central tendency?

A) Mean B) Median C) Mode D) range

Q2) among the following which is the best measure of central tendency?

A) Mean B) Median C) Mode

If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :

A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5

10. If median = 15 and mean = 16, find mode of the distributionThe mean of the following data is 53, find the missing frequencies.

age in years -- 0-20, 20-40 40-60 60-80, 80-100

number of people--- 15, f1, 21, f2, 17, 100

Class Interval

20-30

30-40

40-50

50-60

60-70

Frequency

25

47

62

p

10

Total = 50

height in cm frequency cumulative frequency

150-155 12 a

155-160 b 25

160-165 10 c

165-170 d 43

170-175 e 48

175-180 2 f

the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find

a) class size

b) lower limit of second class

c) upper lmit of last class

d) third class

THE MEAN OF THE FOLLOWING DISTRIBUTION IS 132 AND THE SUM OF THE OBSERVATION IS 50. FIND THE MISSING FREQUENCIES f1 AND F2.