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Syllabus

1.Find the missing frequency f, if the mode of the given data is 154.

Classes

120-130

130-140

140-150

150-160

160-170

170-180

Frequency

2

8

12

f

9

7

plzz give an answer fast....

Find the value of f1 from the following data if it's mode is 65:

Class frequency

0-20 6

20-40 8

40-60 f1

60-80 12

80-100 6

100-120 5

Where frequency 6,8, f1, and 12 are in ascending order.

what is hit and trial method .

how to calculate mode if two classes have same and highest frequency (bimodal) ?

If the median of the distribution is given below is 28.5, find the values of

xandy.Class intervalFrequency0 − 10

5

10 − 20

x20 − 30

20

30 − 40

15

40 − 50

y50 − 60

5

Total

60

if the median of the following frequency distribution is 24. find the missing frequency x :

Age Number of persons

0 - 10 5

10 - 20 25

20 - 30 x

30 - 40 18

40 - 50 7

find the missing frequencies if N=100 and median is 32.

marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total

no. of students-10 ,? ,25 ,30 ,? ,10 ,100.

The median of the following distribution is 30. Find the missing frequencies f1 and f2:

Class frequency

0-10 10

10-20 10

20-30 f1

30-40 30

40-50 f2

50-60 10

Total 100

13. Find the mean, mode and median for the following data:

the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?

Number of teachers 4, 3 ,18, 2, 3 Find mean and median for this data.

how to find the mean if the class intervals are unequal??

like fr e- 0-10,10-30,30-35....

_{1 }, f_{2}and f_{3}in the following frequency distribution , when it is given taht f_{2 }: f_{3}= 4 : 3 , and mean = 5020-40

40-60

60-80

80-100

17

f

_{1}f

_{2}f

_{3 19}The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______

Marks Below 10 Below 20 Below 30 Below 40 Below 50 Below 60 Below 70 Below 80 Below 90 Below 100

No. of students 5 9 17 29 45 60 70 78 83 85

how to find xi?

53 – 55

56 – 58

59 – 61

62 – 64

120

105

125

30

What is the formula to use median when more than ogive is given?

IF THE N/2 IS EQUAL TO THE CUMULATIVE FREQUENCY THEN WE WOULD REGARD THAT CLASS AS THE MEDIAN CLASS OR NOT.

median.

Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90

frequency 10 8 12 24 6 25 15

Marks No.of students

Below 10 0

Below 20 12

Below 30 20

Below 40 28

Below 50 33

Below 60 40

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days0 − 6

6 − 10

10 − 14

14 − 20

20 − 28

28 − 38

38 − 40

Number of students11

10

7

4

4

3

1

Find the median of the following data.

Wages ( in rupees ) :More than 150 , More than 140 , More than 130 , More than 120 , More than 110 , More than 100 , More than 90 . More than 80.No.of workers : NIL ,12,27,60,105,124,141,150.3 Median = Mode + 2 Mean

please proof it.

In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median

The mean and median of same data are 24 and 26 respectively. The value of mode is ?

In the step deviation method,

What is the meaning of

u_{i }?marks number of students

0 and above 80

10 and above 77

20 and above 72

30 and above 65

40 and above 55

50 and above 43

60 and above 28

70 and above 16

80 and above 10

90 and above 8

100 and above 0

In a given data if the MODAL CLASS is at the bottom(last) and has nothing Preceeding it then how will we find the MODE?

The following distribution gives the daily income of 50 workers of a factory.

Daily income (in Rs)100 − 120

120 − 140

140 − 160

160 − 180

180 − 200

Number of workers12

14

8

6

10

Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.

height 150-156 156-162 162-168 168-174 174-180

no.students 4 7 15 8 6

find mean height.

the mean of first n odd natural numbers is n2/81,then n=

How is assumed mean calculated of even number of even number of class intervals ?

E.g.C.I. F

_{i}20-4051

40-6068

60-8024

80-10013

100-12005

120-14077

140-16036

160-18012

In this case what will be the assumed mean ? Please give reason also as to explain why u chose it ??

if the mean of the following frequency distribution is 91, find the missing frequency x and y :

classes frequency

0 - 30 12

30-60 21

60 - 90 x

90 -120 52

120 - 150 y

150 - 180 11

total 150

Class 0 – 20 20 – 40 40 – 60 60 – 80 80 –100 100 –120

Frequency 6 8 f 12 6 5

8. The mean of the following distribution is 53. Calculate missing frequencies

The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:

1. X+n

2. X+n/2

3. X+(n+1)/2

4. X+(n-1)/2

Cost of living index /number of weeks

1400-1500—8

1550-1700—15

1700-1850—21

1850-2000—8

class frequency

40-50 5

50-60 x

60-70 15

70-80 2

80-90 7

class frequency

25-30 x

30-35 22

35-40 y

40-45 8

45-50 7

50-55 3

55-60 2

how do we find mean using step deviation method if the classes are unequal?

should we make the classes equal in such a case?

If the class marks of a continuous frequency distribution are 12,14,16,18,........., then find the class intervals corresponding to the class marks 16 and 22.

During the medical check-up of 35 students of a class, their weights were recorded as follows:

Weight (in kg)Number of studentsLess than 38

0

Less than 40

3

Less than 42

5

Less than 44

9

Less than 46

14

Less than 48

28

Less than 50

32

Less than 52

35

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.

Class interval Frequency0-10 10

10-20 20

20-30 x

30-40 40

40-50 y

50-60 25

60-70 15

p' if the mean of the given data is 15.45.pFind the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 from

their mean.

Class interval Frequency10-20 12

20-30 30

30-40 f1

40-50 65

50-60 f2

60-70 25

70-80 18

no links plz.

Classes Frequency

0-5 7

5-10 6

10-15 f

15-20 4

20-25 3

a) f <8

b) f

>8c) f > 8 only

d) f<7

the median of the data is 525. find x and y, if total frequency is 100

class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000

frequeency 2 5 x 12 17 20 y 9 7 4

9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing

d

_{i}is the deviation of x_{i }from assumed mean a.If mean = x + ∑f

_{i}d_{i}/∑f_{i}, then x isThe mean of the following frequency dristibution is 50. Find the value of

ppThe mean of the following data is 38.2. Find the missing frequencies f1 and f2 if the total frequency is 50.

Classes

0-10

10-20

20-30

30-40

40-50

50-60

60-70

Frequency

4

4

F1

10

F2

8

5

In a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.

how can we find the median by only less than ogive curve?

The median of the following data is 32.5.find the value of x and y

class interval f

0-10 x

10-20 5

20-30 9

30-40 12

40-50 y

50-603

60-70 2

total 40

The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.

Marks No. of studentsLess than 10 7

Less than 20 21

Less than 30 34

Less than 40 46

Less than 50 66

Less than 60 77

Less than 70 92

Less than 80 100

Find the mean, mode and median for the following data.

In an arranged series of an even number of 2n terms the median is__________

The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.

Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40

Frequencies: -7 10 x 13 y 10 14 9

Number of days 0-5 5-10 10-15 15-20 20-25 30-35 35-40 Total

Number of students 15 16 x 8 y 6 4 70

how to find the median class?

(in percent)

is the ans median class 60-70 and modal class 50-60??

How to find missing frequency if the mode of the given data is given.

Marks

obtained

No. of students

Less than 10 14

Less than 20 22

Less than 30 37

Less than 40 58

Less than 50 67

Less than 60 75

How to convert a

LESS THAN OGIVEand it'sCFinto the Frequency distribution?Find the class marks of classes 10 - 25 and 35 - 55.If the mean of the following distributions is 27, Find the value of p

class 0-20 20-40 40-60 60-80 80-100 100-120

frequency14 x 24 32

10 2

If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :

A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5

monthly consumption of electricity of some consumers is given below as a distribution. Find the missing frequency(x), if mode is given to be 200 units.

Monthly cosumption(in units ) 90-120 120-150 150-180 180-210 210-240

Number of consumers 20 15 X 75 30

The mean of the following data is 53, find the missing frequencies.

age in years -- 0-20, 20-40 40-60 60-80, 80-100

number of people--- 15, f1, 21, f2, 17, 100

Total = 50

height in cm frequency cumulative frequency

150-155 12 a

155-160 b 25

160-165 10 c

165-170 d 43

170-175 e 48

175-180 2 f

the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find

a) class size

b) lower limit of second class

c) upper lmit of last class

d) third class

calculate the median from the following data

class interval frequency

130-1405

140-150 9

150-160 17

160-170 28

170-180 24

180-190 10

190-200 7