Select Board & Class

Login

Triangles

Question 13:

D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. Show that

Answer:

In ΔADC and ΔBAC,

∠ADC = ∠BAC (Given)

∠ACD = ∠BCA (Common angle)...

To view the solution to this question please

What are you looking for?

Syllabus