In the given figure, ABC is a triangle in which ∠ABC < 90° and AD ⊥ BC. Prove that AC2 = AB2 + BC2 − 2BC.BD.
Applying Pythagoras theorem in ΔADB, we obtain
AD2 + DB2 = AB2
⇒ AD2 = AB2 − DB2 … (1)
Applying Pythagoras …
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