Rs Aggarwal 2020 2021 Solutions for Class 10 Maths Chapter 12 Trigonometric Ratios Of Some Complemantary Angles are provided here with simple step-by-step explanations. These solutions for Trigonometric Ratios Of Some Complemantary Angles are extremely popular among Class 10 students for Maths Trigonometric Ratios Of Some Complemantary Angles Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2020 2021 Book of Class 10 Maths Chapter 12 are provided here for you for free. You will also love the ad-free experience on Meritnationâ€™s Rs Aggarwal 2020 2021 Solutions. All Rs Aggarwal 2020 2021 Solutions for class Class 10 Maths are prepared by experts and are 100% accurate.

#### Page No 590:

(i) $\frac{\mathrm{sin}26°}{\mathrm{cos}64°}$

(iii) $\frac{\mathrm{tan}65°}{\mathrm{cot}25°}$

(iv) $\frac{\mathrm{cos}37°}{\mathrm{sin}53°}$

(vi) $\frac{\mathrm{cot}34°}{\mathrm{tan}56°}$

#### Page No 590:

(iii) To Prove: cosec60° − sec30° = 0

(iv) To Prove: cot34° − tan56° = 0

(vi) To Prove: cos272° + cos218° = 1

#### Page No 590:

(i) To prove: sin212° + sin2 78° = 1

(ii) To prove: sec229° – cot261° = 1

(iii) To prove: tan256° – cot234° = 0

(iv) To prove: cos257° – sin233° = 0

(v) To prove: sec250° – cot240° = 1

(vi) To prove: cosec272° – tan218° = 1

#### Page No 590:

(iv) To prove: tan15° tan60° tan75° = $\sqrt{3}$

(vii) To prove: cosec39° cos51° + tan21° cot69° – sec221° = 0

#### Page No 590:

(i) sin72° + cosec72°

(ii) cosec66° + tan66°

(iii) tan68° + sec68°

(iv) cot59° + cosec59°

(v) cos51° + cot49° – sec47°

(vi) sin67° + cos75°

#### Page No 591:

Given: sin3A = cos(A – 10°)

#### Page No 591:

Given: tanA = cot(A + 10°)

#### Page No 591:

Given: cos2A = sin(A – 15°)

#### Page No 591:

Given: sec4A = cosec(A – 15°)

#### Page No 591:

Given: tan2θ = cot(θ + 60°)

#### Page No 591:

Given: sin(θ + 36°) = cosθ

Ans

Ans

#### Page No 594:

Disclaimer: There must be $\mathrm{sin}31°$ instead of $\mathrm{sin}21°$.

#### Page No 594:

Given: sinA = cosB

#### Page No 594:

Given: cos(α + β) = 0

#### Page No 594:

Given: sec4A = cosec(– 10°)

#### Page No 594:

Given: sin3A = cos(A – 10°)

#### Page No 594:

(i) cot34° – tan56° = .......

(ii) cosec31° – sec59° = .......

(iii) cos267° + cos223° = ..........

(iv) cosec254° – tan236° = .........

(v) sec240° – cot250° = ..........

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