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Syllabus

What is componendo and dividendo method? Plz explain.

a person of normal eye sight can read a print at such a distance that the letters subtend an angle of 5' at the eye. find the height of the letters if he can read at a distance of 420 meters.

urgent solution required

cos20.cos40.cos80=1/8

Prove that.....Tan 70 = tan 20 + 2 tan 50...

Find the values of theta lying between between 0 degrees and 360 degrees when

1)sin theta=1/2

2)tan theta = -1

3)sec theta = -2

4)sin theta =sin 21 degrees

5)tan theta= -2.0145

6)sin theta=cos 317 degrees

7)cos theta=sin 285 degrees

Solve Sinx + Sin3x + Sin5x = 0.

sin 20 sin 40 sin 60 sin 80=3/16

solution of ml agarwal for isc 11std

can we find the value(in degrees) of tan(4/3)

The chapter trigonometry in RS Aggarwal book (of class 11th) is divided into 6 sub-chapters. But its chapter 5 ( Solution of triangles ) and 6 ( Graphs of trigonometric functions ) are not the topics of NCERT Book.

Now my question is:

Should I study these two chapters (5 &6 of RS Aggarwal) as these are not in NCERT Book?prove the following :

root 3 cosec 20 - sec 20 = 4

Q: prove that cos

^{3}x+ cos^{3 }( 2pi/3 ) + x ) + cos^{3}(2pi/3 )- x)=3/4cos 3x.prove that tan20 .tan40.tan80=tan60.

sin

^{4}x+cos^{4}x=1-2sin^{2}xcos^{2}xcos

^{2}x + cos^{2}(x + pi/3) + cos^{2}(x - pi/3) = 3/2. proveConsider a triangle with sides 3,6,8 cm respectivelty.Now if a man runs around the triangle in such a way that he is always at a distance of 1cm from the sides of triangle then how much distance will he travel.

cotx cot2x - cot2x cot3x-cot3x cotx=1

The circular measure of an angle of a triangle is 3 pi/ 10 ,the number of grades in the second is 70, find the number of degrees in the third angle.

sinA . sin(60-A) . sin(60+A) = 1/4 sin3A

if sin alpha + sin beta= a and cos alpha + cos beta= b, show that

1. Sin(alpha+beta)= 2ab/a sq.+b sq.

2. Cos(alpha+beta)= b sq.-a sq./b sq.+a sq.

prove that cos20 cos 40 cos 60 cos 80=1/16.

prove that cos 10.cos30.cos50.cos70 = 3/16

prove that tan 50 = 2 tan 10 + tan40

1.(1+cos pi/ 8) (1+cos 3pi / 8) (1+cos 5pi / 8) (cos 7pi / 8)=1/8

In a circle of diameter 60 cm the length of a chord is 30 cm. Find the length of the minor and the major arcs of the chord. { hint: Triangle OAB being equilateral theta=60 degrees=pie/3 rad

Now minor arc AB=r theta

Also major arc = 2 pie r - minor arc}

Prove that sin3x + sin 2x – sinx = 4 sinx cos x/2 cos3x/2

sin10*sin50*sin70=1/8?

cot(2pi+x)=?

sin 105 degree +cos 105 degree =cos 45 degree

Prove the following: cosA / 1 - sinA = tan (45 + A/2)

13 sin A+5 sec A divided by 5 tan A + 6cosec A

Find the maximum and minimum values of sin^4x + cos^2x and hence or otherwise find the maximum value of sin^1000 x + cox^2008 x

cos4 pi /8+ cos4 3pi /8+ cos4 5pi /8 +cos4 7pi/ 8=3/2 prove it fast rely plssss

PROVE THAT

cos

^{3}A + cos^{3}(120+A) + cos^{3}(240+A) = 3/4 cos3A?

cos4 pi / 8+cos4 3pi /8 + cos4 5pi / 8 +cos4 7pi /8 =3/2

tan22 + tan23 +tan22tan23 = 1

if A+B=45 degree.show that {1+tanA}{1+tanB}=2

Prove that:

4 cosA cos(60-A) cos(60+A) = cos3A

The moon's distance from the earth is 360000 km and its diameter subtends an angle of 31' at the eye of the observer. Find the diameter of the moon.

in any triangleABC P.T

(b

^{2}-c^{2})cotA + (c^{2}-a^{2})cotB + (a^{2}-b^{2})cotC = 0Is it right.....?? tan ( 1485 ) = tan ( 2 multiply 360 + 765 )

= tan 765

= tan ( 720 + 45 )

= tan 45 degree.

= 1

Prove cos5x=16cos

^{5}x-20cos^{3}x+5cosxprove that cos11+sin11/cos11-sin11=tan56

prove using sine rule - 1) sin ( B-C)/2 = b-c/a cos ( A/2)

2)1+cos(A-B) cos C / 1+cos(A-C) cos B = a2+ b2/ a2- c2

3) (b-c)cot (A/2) + (c-a)cot (B/2) + (a-b)cot (C/2) = 0

4) a cos(B-C/2) = (b+c) sin(A/2)

5) c/(a-b) = tan(A/2) + tan(B/2) / tan(A/2) - tan(B/2)

6) a(cos C - cos B) = 2(b-c) cos^2 (A/2)

evaluate the following;

a)cos 1050 degree

b)cosec (-585 degree)

c)cot 495 degree

d)tan 120 degree

show that tan3x-tan2x-tanx =tan3x*tan2x*tanx

IF cos(alpha + beta) = 4/5 and sin(alpha - beta) = 5/13

FIND THE VALUE OF tan 2 alpha, where 0 is less than equal to alpha is less than equal to pie/4.

plz reply!!

Prove that tan4x= (4tanx(1-tan^2x)) / 1-6tan^x+tan^4x

a tree stands vertically on a hill side which makes an angle of 15degree with the horizontal. from a point on the ground 35m down the hill from the base of the tree, the angle of elevation of the top of the tree is 60degree. find the height of the tree.

ans(35root2m) plese tell the xact solution

prove that sec4x-1/sec2x-1=tan4x/tan2x.

Solve the equation:

4sinxcosx + 2sinx + 2cosx + 1 = 0

Show that cos 24 + cos 55 + cos 125 + cos 204 + cos 300= 1/2

geometrically prove that :

1.sin(X-Y) = sinx.cosy-cosx-siny

2. sin(x+y)=sinx.cosy + cosx.siny

3, cos(x+y)= cosx.cosy-sinx.siny

4.tan(x+y)= tanx+tany/1-tanxtany

5. tan(x'y) =tanx-tany/1+tanxtany

prove-

cos

^{2}(pi /8) + cos^{2 (}3pi / 8) +cos^{2}(5pi / 8) +cos^{2 (}7pi / 8) = 2If tan

θ= 15/8 and cosθis negative, find the value of:[sin(-

θ)-cosθ] / [tan(-θ)+sec(-θ)]If A+B+C = pai, prove that

sinA + sinB + sinC = 4 cosA/2 cosB/2 cosC/2

Thea value of cos pi/14*cos 3pi/14 * cos 5pi/14 is ?

find the derivative of cotx by the first principle?

The angles of a triangle are in AP and the ratio of the number of degrees in the least to the number of radians in the greatest is 60:

π. Find the angles in degrees and radians.

If theta lies in second quadrant and

tan theta = -5/12find the value of2 cos theta/1-sin thetaprove sin

^{2}A - sin^{2}B/sinA .cosA- sinB. cosB = tan(A+B)Express in circular measure and also in degrees the angle of a regular octagon.

Prove that: cosA cos2A cos4A cos8A =sin16A / 16sinAPlease explain working

prove that 1+cos2x+cos4x+cos6x= 4cosx cos2x cos3x.

EVALUATE cos(-1125)

in triangle ABC , prove that b^2 sin2C + c^2 sin2B = 2bc sinA

Solve sin2x+sin4x+sin6x=0

IF sin x + cos x = root over 7/2 where x belongs to A , then tan x/2 =?

prove that

cos20cos40cos60cos80 =1/16