Select Board & Class

From the figure,
$O{P}^{2}={{x}_{1}}^{2}+{{y}_{1}}^{2}$
$O{Q}^{2}={{x}_{2}}^{2}+{{y}_{2}}^{2}$
$P{Q}^{2}=\sqrt{{\left({x}_{2}-{x}_{1}\right)}^{2}+{\left({y}_{2}-{y}_{1}\right)}^{2}}$
Using cosine formula in $∆OPQ$, we get:
$P{Q}^{2}=\mathrm{O\dots }$

To view the solution to this question please

Syllabus