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urgent ..
formula for sin-1X + sin-1Y , sin-1X -sin-1Y
cos-1X + cos-1Y
cos-1X - cos-1Y
prove: tan inverse [ cos x / (1+sin x)] = pie /4 - (x/2)
formula of 1-sinx
show that tan(1/2 sin-1 3/4) = 4-root7/3
prove that :
tan [pi/4 + 1/2 cos-1 a/b] + tan[pi/4 - 1/2cos-1 a/b] = 2b/a
URGENT!!
Show that sin-1(4/5) +cos-1(2/square root of 5)=cot-1 (2/11)
Please ans in a simple way
find the value of x : sin-1x + sin-1(1-x) = cos-1x
Show that tan(1/2sin-13/4) = (4-Squareroot of 7)/ 3
i have 2 question -
1)if cos-1(x/a)+cos-1(y/b)=d
prove that : x2/a2-2xy/ab-cosd+y2/b2=sin2d
2)solve tan(cos-1x)=sin(tan-1x)
3)tan-1x+tan-1y+tan-1z=pi/2
prove that xy+yz+zx =1
integrate 0-pi x dx/4-cos2x
cos^-1(x) + sin^-1(x/2)=pi/6
find x.
cos{cos-1(-√3/2)+pi/4}
Prove that :
tan-1(1/4) + tan-1(2/9) = 1/2 Cos-1 (3/5)
if cos-1x + cos-1y + cos-1z = pi
prove that x2 + y2 + z2 +2xyz = 1
2tan-1(1/3) +cot-14 =tan-1(16/13)
find the greatest and least values:(sin-1x)2+(cos-1x)2
prove that tan -1(1) + tan-1(2) + tan-1(3) = pie.
sin-1(1-x)-2sin-1x=pi/2
If y=cot-1(square root cosx) - tan-1(square root cosx)
prove that sin y= tan2 x/2.
if tan-1x+tan-1y+tan-1z=π/2 show that xy+yz+zx=1?
cos cos-1 [-root3/2] +pi/4]
Solve for x : sin-1 6x + sin-1 6root3 x = -pi/2
solve for X
sin-1x + sin-12x = ∏/3
Solve for the equation cos (tan-1x) = sin(cot-13/4)
Solve the equation:
sin-1 (3x/5) + sin-1(4x/5)= sin-1x
if sin -1x +sin-1 y+ sin-1 z= pie ,prove that
a)x( root 1-x2)+y( root 1- y2)+ z(root 1-z2)= 2xyz
b)x4+ y4+z4+ 4 x2y2z2= 2( x2y2+y2z2+ z2x2)
If tan-1{root (1+x2) - root(1-x2)}/{ root (1+x2) +root (1-x2)} =theta , then prove that x2 =sin 2 theta .
Solve for x - tan^-1 (x+1) + tan^-1 (x-1) = tan^-1 8/31
PROVE THAT-
tan -1 ((1/root over 3) tan x/2) = 1/2 cos -1 ((1+2cos x)/ (2cos x+1))
prove that
2tan-1 [ { (a-b) / (a+b) }1/2 tan x/2 ] = cos-1{ (b +acos x ) / (a+bcos x) }
prove that sec square (tan inverse 2) +cosec square (cot inverse 3) =15
Maximum and minimum values of sin6x+cos6x is
how to solve tan-1 2x/1-x2 + cot-1 1-x2/2x = pie/3
sin inverse sin 3pi/5????
Write the function, cot^-1 (sqrt(1+x^2)+x) in the simplest form
If tan-1x+tan-1y+tan-1z=pie, prove x+y+z=xyz
tan-1 x + 2cot-1 x = 2pi/3 find value of x
prove that 1/2 tan -1 x = cos -1 ( 1 + root ( 1 + x2 )) / 2 root (1 + x2 ) ) 1/2
sin(1/2 cos inverse 4/5) ??evaluate
prove that 2 tan-1 (root of a+b/a-b tn theta/2) = cos -1 (acos theta b/a b cos theta)
simplify
sin-1(sinx+cosx/root 2)where pie
prove that Tan-1(1/4) + tan-1(2/9) = ½ sin-1 (4/5)
Find x if sin-1(5/x) + sin-1(12/x) =pi/2
sin^-1 x - cos^-1 x = pi/6
IF y = sin-1 (2x+1/1+4x) find dy/dx
cot[pi/4 - 2cot-1 3] =7
(i) sin^-1 (12/13) + cos^-1 (4/5) +tan^-1 (63/16)=0
(ii) 2sin^-1(3/5) - tan^-1 (17/31) =pi / 4
solve:
cos-1 ([x2-1]/[x2+1]) + tan-1[(2x)/(x2-1)]=2pi/3
please solve them for me quick:
1)Evaluate Tan-1(tan(-6))
2)Simplify sin -1 (sinx + cosx)/root 2
5)Solve
tan-1(x+1) + tan-1(x-1) = tan-18/31
(cosx - cosy)2 + (sinx - siny)2 = 4 sin2(x-y)/2.
cos-1 [ 3/5 cosx + 4/5sinx ] find its value?
I can ' t understand this question . please explain it briefly ?
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Syllabus
urgent ..
formula for sin-1X + sin-1Y , sin-1X -sin-1Y
cos-1X + cos-1Y
cos-1X - cos-1Y
prove: tan inverse [ cos x / (1+sin x)] = pie /4 - (x/2)
formula of 1-sinx
show that tan(1/2 sin-1 3/4) = 4-root7/3
prove that :
tan [pi/4 + 1/2 cos-1 a/b] + tan[pi/4 - 1/2cos-1 a/b] = 2b/a
URGENT!!
Show that sin-1(4/5) +cos-1(2/square root of 5)=cot-1 (2/11)
Please ans in a simple way
find the value of x : sin-1x + sin-1(1-x) = cos-1x
Show that tan(1/2sin-13/4) = (4-Squareroot of 7)/ 3
i have 2 question -
1)if cos-1(x/a)+cos-1(y/b)=d
prove that : x2/a2-2xy/ab-cosd+y2/b2=sin2d
2)solve tan(cos-1x)=sin(tan-1x)
3)tan-1x+tan-1y+tan-1z=pi/2
prove that xy+yz+zx =1
integrate 0-pi x dx/4-cos2x
cos^-1(x) + sin^-1(x/2)=pi/6
find x.
cos{cos-1(-√3/2)+pi/4}
Prove that :
tan-1(1/4) + tan-1(2/9) = 1/2 Cos-1 (3/5)
a) 1+x b)1-x c) x d)1/x
if cos-1x + cos-1y + cos-1z = pi
prove that x2 + y2 + z2 +2xyz = 1
2tan-1(1/3) +cot-14 =tan-1(16/13)
find the greatest and least values:(sin-1x)2+(cos-1x)2
prove that tan -1(1) + tan-1(2) + tan-1(3) = pie.
Sin1 or cos1
Why how!?
sin-1(1-x)-2sin-1x=pi/2
If y=cot-1(square root cosx) - tan-1(square root cosx)
prove that sin y= tan2 x/2.
if tan-1x+tan-1y+tan-1z=π/2 show that xy+yz+zx=1?
cos cos-1 [-root3/2] +pi/4]
Solve for x : sin-1 6x + sin-1 6root3 x = -pi/2
solve for X
sin-1x + sin-12x = ∏/3
Solve for the equation cos (tan-1x) = sin(cot-13/4)
Solve the equation:
sin-1 (3x/5) + sin-1(4x/5)= sin-1x
if sin -1x +sin-1 y+ sin-1 z= pie ,prove that
a)x( root 1-x2)+y( root 1- y2)+ z(root 1-z2)= 2xyz
b)x4+ y4+z4+ 4 x2y2z2= 2( x2y2+y2z2+ z2x2)
If tan-1{root (1+x2) - root(1-x2)}/{ root (1+x2) +root (1-x2)} =theta , then prove that x2 =sin 2 theta .
Solve for x - tan^-1 (x+1) + tan^-1 (x-1) = tan^-1 8/31
PROVE THAT-
tan -1 ((1/root over 3) tan x/2) = 1/2 cos -1 ((1+2cos x)/ (2cos x+1))
prove that
2tan-1 [ { (a-b) / (a+b) }1/2 tan x/2 ] = cos-1{ (b +acos x ) / (a+bcos x) }
sin-1(root3 - 1/ 2root2)
prove that sec square (tan inverse 2) +cosec square (cot inverse 3) =15
Maximum and minimum values of sin6x+cos6x is
pls answer , I have a test tomorrow :/
tan-1 ( x-1 ) + tan-1x + tan-1 ( x+1 ) = tan-1 3x
how to solve tan-1 2x/1-x2 + cot-1 1-x2/2x = pie/3
sin inverse sin 3pi/5????
Write the function, cot^-1 (sqrt(1+x^2)+x) in the simplest form
if y = tan-1 x, find d2y/dx2 in terms of y alone
If tan-1x+tan-1y+tan-1z=pie, prove x+y+z=xyz
tan-1 x + 2cot-1 x = 2pi/3 find value of x
prove that 1/2 tan -1 x = cos -1 ( 1 + root ( 1 + x2 )) / 2 root (1 + x2 ) ) 1/2
sin(1/2 cos inverse 4/5) ??evaluate
prove that 2 tan-1 (root of a+b/a-b tn theta/2) = cos -1 (acos theta b/a b cos theta)
2tan-1{tan(α/2).tan((π/4)-(β/2)) = tan-1{(sinαcosβ)/(cosα+sinβ)}
simplify
sin-1(sinx+cosx/root 2)where pie
sin inverse[root of 1+x+root of 1-x/2]
prove that Tan-1(1/4) + tan-1(2/9) = ½ sin-1 (4/5)
Find x if sin-1(5/x) + sin-1(12/x) =pi/2
sin^-1 x - cos^-1 x = pi/6
IF y = sin-1 (2x+1/1+4x) find dy/dx
cos (sin^-1 3/5 + cos^-1 12/13)
cot[pi/4 - 2cot-1 3] =7
prove that
(i) sin^-1 (12/13) + cos^-1 (4/5) +tan^-1 (63/16)=0
(ii) 2sin^-1(3/5) - tan^-1 (17/31) =pi / 4
a)triangle is obtuse angled b)triangle is always acute angled
c)triangle is always equilateral d)nothing can be said
solve:
cos-1 ([x2-1]/[x2+1]) + tan-1[(2x)/(x2-1)]=2pi/3
please solve them for me quick:
1)Evaluate Tan-1(tan(-6))
2)Simplify sin -1 (sinx + cosx)/root 2
5)Solve
tan-1(x+1) + tan-1(x-1) = tan-18/31
(cosx - cosy)2 + (sinx - siny)2 = 4 sin2(x-y)/2.
represent cot(sin-1 x) in terms of x only
cos-1 [ 3/5 cosx + 4/5sinx ] find its value?
I can ' t understand this question . please explain it briefly ?
cos-1 (tan 3pi/4)