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formula for sin

^{-1}X + sin^{-1}Y , sin^{-1}X -sin^{-1}Ycos

^{-1}X + cos^{-1}Ycos

^{-1}X - cos^{-1}Yprove: tan inverse [ cos x / (1+sin x)] = pie /4 - (x/2)

show that tan(1/2 sin-1 3/4) = 4-root7/3

If cos

^{-1}3/5- sin^{-1}4/5 = cos^{-1}x then x =a.0 b.1

c.-1 d.2

prove that :

tan [pi/4 + 1/2 cos

^{-1}a/b] + tan[pi/4 - 1/2cos^{-1}a/b] = 2b/afind the value of x : sin

^{-1}x + sin^{-1}(1-x) = cos^{-1}xShow that tan(1/2sin

^{-1}3/4) = (4-Squareroot of 7)/ 3i have 2 question -

1)if cos

_{-1}(x/a)+cos^{-1}(y/b)=dprove that : x

^{2}/a^{2}-2xy/ab-cosd+y^{2}/b^{2}=sin^{2}d2)solve tan(cos

^{-1}x)=sin(tan^{-1}x)3)tan

^{-1}x+tan^{-1}y+tan^{-1}z=pi/2prove that xy+yz+zx =1

2

tan(1/3) +^{-1}cot4 =^{-1}tan(16/13)^{-1}cos^-1(x) + sin^-1(x/2)=pi/6

find x.

formula of 1-sinx

Prove that :

tan

^{-1}(1/4) + tan-1(2/9) = 1/2 Cos^{-1}(3/5)sin[ tan^-1 x (1-x^2/2x) + + cos^-1 (1-x^2/1+x^2)]=1pls prove this

pls answer , I have a test tomorrow :/

if cos

^{-1}x + cos^{-1}y + cos^{-1}z = piprove that x

^{2}+ y^{2}+ z^{2}+2xyz = 1find the greatest and least values:(sin

^{-1}x)^{2}+(cos^{-}^{1}x)^{2}Write the function, cot^-1 (sqrt(1+x^2)+x) in the simplest form

prove that tan

^{-1}(1) + tan^{-1}(2) + tan^{-1}(3) = pie.Plz fast..

if sin

^{-1}x+sin^{-1}y=pi/2 then find cos^{-1}x+cos^{-1}ysin

^{-1}(1-x)-2sin^{-1}x=pi/2If y=cot

^{-1}(square root cosx) - tan^{-1}(square root cosx)prove that sin y= tan

^{2}x/2.if tan-1x+tan-1y+tan-1z=π/2 show that xy+yz+zx=1?

If tan-1{root (1+x

^{2}) - root(1-x^{2})}/{ root (1+x^{2}) +root (1-x^{2})} =theta , then prove that x^{2}=sin 2 theta .Solve for x : sin-1 6x + sin-1 6root3 x = -pi/2

solve for X

sin-1x + sin-12x = ∏/3

Solve for the equation cos (tan

^{-1}x) = sin(cot^{-1}3/4)IF y = sin

^{-1}(2^{x+1}/1+4^{x}) find dy/dx^{-1 }(x + 1) ) = cos ( tan^{-1}x ) ...... find x ..... i asked this question and an expert proved it wrong .....but this question is absolutely correct ...it's 2015 board question .... so kindly find x ...since question is correct ..!!! @ PRIYANKA KEDIA ......AND OTHER MERITNATION EXPERTS ....!!!if sin

^{-1}x +sin^{-1}y+ sin^{-1}z= pie ,prove thata)x( root 1-x

^{2})+y( root 1- y^{2})+ z(root 1-z^{2})= 2xyzb)x

^{4}+ y^{4}+z^{4}+ 4 x^{2}y^{2}z^{2}= 2( x^{2}y^{2}+y^{2}z^{2}+ z^{2}x^{2})prove that sec square (tan inverse 2) +cosec square (cot inverse 3) =15

^{-1}x-cos^{-1}y=cos^{-1}{xy+whole root over(1-x^{2)}(1-y^{2})^{}}Solve for x - tan^-1 (x+1) + tan^-1 (x-1) = tan^-1 8/31

then find the value of theta.

prove that

2tan

^{-1}[ { (a-b) / (a+b) }^{1/2 }tan x/2 ] = cos^{-1}{ (b +acos x ) / (a+bcos x) }Sin(Cos^-1(4/5) + tan^-1(2/3))

tan

^{-1}( x-1 ) + tan^{-1}x + tan^{-1}( x+1 ) = tan^{-1}3xsin^-1 x - cos^-1 x = pi/6

how to solve tan

^{-1}2x/1-x^{2}+ cot^{-1}1-x^{2}/2x = pie/3sin inverse sin 3pi/5????

Please explain me in detail that how [cos inverse(cos 7pi/6)] is equal to 5pi/6.

It is Q. no. 19 of Ex. 2.2 of chapter INVERSE TRIGONOMETRIC FUNCTION (N.C.E.R.T).

sin inverse[root of 1+x+root of 1-x/2]

If tan

^{-1}x+tan^{-1}y+tan^{-1}z=pie, prove x+y+z=xyzsin

^{-1}(4/5) + sin^{-1}(5/13) + sin^{-1}(16/65) = pi/2Instead of solving it straight away, I took the sin

^{-1}(16/65) term to the right hand side and thus proved that sin^{-1}(4/5) + sin^{-1}(5/13) = cos^{-1}(16/65). Is it correct to do so? Will I be awarded marks if in case this question happens to appear in the exam?^{-1}1 + tan^{-1}2 + tan^{-1}3 =?tan

^{-1}x + 2cot^{-1}x = 2pi/3 find value of xsin(1/2 cos inverse 4/5) ??evaluate

Sin

^{-1}x+Sin^{-1}y+Sin^{-1}z=3(pi)/2 then find x+y+z=?prove that 2 tan-1 (root of a+b/a-b tn theta/2) = cos -1 (acos theta b/a b cos theta)

if two angles of a triangle are tan

^{-1}(2) and tan^{-1}(3) find the third anglesimplify

sin-1(sinx+cosx/root 2)where pie

Find x if sin

^{-1}(5/x) + sin^{-1}(12/x) =pi/2. Find x

cot[pi/4 - 2cot

^{-1}3] =7If sin x

_{1}+sinx_{2}+sinx_{3}?? = 3, then write the value of cosx_{1}+cosx_{2}+cosx_{3}??if y = tan-1 x, find d2y/dx2 in terms of y alone

prove that

(i) sin^-1 (12/13) + cos^-1 (4/5) +tan^-1 (63/16)=0

(ii) 2sin^-1(3/5) - tan^-1 (17/31) =pi / 4

solve:

cos

^{-1 }([x^{2}-1]/[x^{2}+1]) + tan^{-1}[(2x)/(x^{2}-1)]=2pi/3^{-1}root(x(x+1)) + sin^{-1}root(x^{2}+x+1) = pi/2.(cosx - cosy)

^{2}+ (sinx - siny)^{2}= 4 sin^{2}(x-y)/2.solve for x

cos(2sin

^{-}^{1}x) =1/9 ,x>0^{-1}x + tan^{-1}y + tan^{-1}z = ?