NCERT Solutions for Class 6 Math Chapter 5  Understanding Elementary Shapes
NCERT Solutions for Class 6 Math Chapter 5 Understanding Elementary Shapes are provided here with simple stepbystep explanations. These solutions for Understanding Elementary Shapes are extremely popular among class 6 students for Math Understanding Elementary Shapes Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the NCERT Book of class 6 Math Chapter 5 are provided here for you for free. You will also love the adfree experience on Meritnation’s NCERT Solutions. All NCERT Solutions for class 6 Math are prepared by experts and are 100% accurate.
Page No 88:
Question 1:
What is the disadvantage in comparing line segments by mere observation?
Answer:
By mere observation, we cannot be absolutely sure about the judgement. When we compare two line segments of almost same lengths, we cannot be sure about the line segment of greater length. Therefore, it is not an appropriate method to compare line segments having a slight difference between their lengths. This is the disadvantage in comparing line segments by mere observation.
Page No 88:
Question 2:
Why is it better to use a divider than a ruler, while measuring the length of a line segment?
Answer:
It is better to use a divider than a ruler because while using a ruler, positioning error may occur due to the incorrect positioning of the eye.
Page No 88:
Question 3:
Draw any line segment, say. Take any point C lying in between A and B. Measure the lengths of AB, BC and AC. Is AB = AC + CB?
[Note: If A, B, C are any three points on a line such that AC + CB = AB, then we can be sure that C lies between A and B]
Answer:
It is given that point C is lying somewhere in between A and B. Therefore, all these points are lying on the same line segment. Hence, for every situation in which point C is lying in between A and B, it may be said that AB = AC + CB.
For example,
is a line segment of 6 cm and C is a point between A and B, such that it is 2 cm away from point B. We can find that the measure of line segment comes to 4 cm.
Hence, relation AB = AC + CB is verified.
Page No 89:
Question 4:
If A, B, C are three points on a line such that AB = 5 cm, BC = 3 cm and AC = 8 cm, which one of them lies between the other two?
Answer:
Given that,
AB = 5 cm
BC = 3 cm
AC = 8 cm
It can be observed that AC = AB + BC
Clearly, point B is lying between A and C.
Page No 89:
Question 5:
Verify, whether D is the mid point of .
Answer:
From the given figure, it can be observed that
= 4 − 1 = 3 units
= 7 − 4 = 3 units
= 7 − 1 = 6 units
Clearly, D is the midpoint of AG.
Page No 89:
Question 6:
If B is the mid point of and C is the mid point of, where A, B, C, D lie on a straight line, say why AB = CD?
Answer:
Since B is the midpoint of AC,
AB = BC (1)
Since C is the midpoint of BD,
BC = CD (2)
From equation (1) and (2), we may find that
AB = CD
Page No 91:
Question 1:
What fraction of a clock wise revolution does the hour hand of a clock turn through when it goes from
(a) 3 to 9 (b) 4 to 7 (c) 7 to 10
(d) 12 to 9 (e) 1 to 10 (f) 6 to 3
Answer:
We may observe that in 1 complete clockwise revolution, the hour hand will
rotate by 360º.
(a) When the hour hand goes from 3 to 9 clockwise, it will rotate by 2 right angles or 180º.
Fraction =
(b) When the hour hand goes from 4 to 7 clockwise, it will rotate by 1 right angle or 90º.
Fraction =
(c) When the hour hand goes from 7 to 10 clockwise, it will rotate by 1 right angle or 90º.
Fraction =
(d) When the hour hand goes from 12 to 9 clockwise, it will rotate by 3 right angles or 270º.
Fraction =
(e) When the hour hand goes from 1 to 10 clockwise, it will rotate by 3 right angles or 270º.
Fraction =
(f) When the hour hand goes from 6 to 3 clockwise, it will rotate by 3 right angles or 270º.
Fraction =
Video Solution for understandingelementaryshapes (Page: 91 , Q.No.: 1)
NCERT Solution for Class 6 math  understandingelementaryshapes 91 , Question 1
Page No 91:
Question 2:
Where will the hand of a clock stop if it
(a) Starts at 12 and makes of a revolution, clockwise?
(b) Starts at 2 and makes of a revolution, clockwise?
(c) Starts at 5 and makes of a revolution, clockwise?
(d) Starts at 5 and makes of a revolution, clockwise?
Answer:
In 1 complete clockwise revolution, the hand of a clock will rotate by 360º.
(a) If the hand of the clock starts at 12 and makes of a revolution clockwise, then it will rotate by 180º and hence, it will stop at 6.
(b) If the hand of the clock starts at 2 and makes of a revolution clockwise, then it will rotate by 180º and hence, it will stop at 8.
(c) If the hand of the clock starts at 5 and makes of a revolution clockwise, then it will rotate by 90º and hence, it will stop at 8.
(d) If the hand of the clock starts at 5 and makes of a revolution clockwise, then it will rotate by 270º and hence, it will stop at 2.
Video Solution for understandingelementaryshapes (Page: 91 , Q.No.: 2)
NCERT Solution for Class 6 math  understandingelementaryshapes 91 , Question 2
Page No 91:
Question 3:
Which direction will you face if you start facing
(a) East and make of a revolution clockwise?
(b) East and make of a revolution clockwise?
(c) West and make of a revolution anticlockwise?
(d) South and make one full revolution?
(Should we specify clockwise or anticlockwise for this last question? Why not? )
Answer:
If we revolve one complete round in either clockwise or anticlockwise direction, then we will revolve by 360º and the two adjacent directions will be at 90º or of a complete revolution away from each other.
(a) If we start facing East and make of a revolution clockwise, then we will face the West direction.
(b) If we start facing East and make of a revolution clockwise, then we will face the West direction.
(c) If we start facing West and make of a revolution anticlockwise, then we will face the North direction.
(d) If we start facing South and make a full revolution, then we will again
face the South direction.
In case of revolving by 1 complete round, the direction in which we are revolving does not matter. In both cases, clockwise or anticlockwise, we will be back at our initial position.
Video Solution for understandingelementaryshapes (Page: 91 , Q.No.: 3)
NCERT Solution for Class 6 math  understandingelementaryshapes 91 , Question 3
Page No 91:
Question 4:
What part of a revolution have you turned through if you stand facing
(a) East and turn clock wise to face north?
(b) South and turn clockwise to face east?
(c) West and turn clockwise to face east?
Answer:
If we revolve one complete round in either clockwise or anticlockwise direction, then we will revolve by 360º and the two adjacent directions will be at 90º or of a complete revolution away from each other.
(a) If we start facing East and turn clockwise to face North, then we have to makeof a revolution.
(b) If we start facing South and turn clockwise to face east, then we have to makeof a revolution.
(c) If we start facing West and turn clockwise to face East, then we have to makeof a revolution.
Video Solution for understandingelementaryshapes (Page: 91 , Q.No.: 4)
NCERT Solution for Class 6 math  understandingelementaryshapes 91 , Question 4
Page No 91:
Question 5:
Find the number of right angles turned through by the hour hand of a clock when it goes from
(a) 3 to 6 (b) 2 to 8 (c) 5 to 11
(d) 10 to 1 (e) 12 to 9 (f) 12 to 6
Answer:
The hour hand of a clock revolves by 360º or 4 right angles in 1 complete round.
(a) The hour hand of a clock revolves by 90º or 1 right angle when it goes from 3 to 6.
(b) The hour hand of a clock revolves by 180º or 2 right angles when it goes from 2 to 8.
(c) The hour hand of a clock revolves by 180º or 2 right angles when it goes from 5 to 11.
(d) The hour hand of a clock revolves by 90º or 1 right angle when it goes from 10 to 1.
(e) The hour hand of a clock revolves by 270º or 3 right angles when it goes from 12 to 9.
(f) The hour hand of a clock revolves by 180º or 2 right angles when it goes from 12 to 6.
Video Solution for understandingelementaryshapes (Page: 91 , Q.No.: 5)
NCERT Solution for Class 6 math  understandingelementaryshapes 91 , Question 5
Page No 92:
Question 6:
How many right angles do you make if you start facing
(a) South and turn clockwise to west?
(b) North and turn anticlockwise to east?
(c) West and turn to west?
(d) South and turn to north?
Answer:
If we revolve one complete round in either clockwise or anticlockwise direction, then we will revolve by 360º or 4 right angles and the two adjacent directions will be at 90º or 1 right angle away from each other.
(a) If we start facing South and turn clockwise to West, then we make 1 right angle.
(b) If we start facing North and turn anticlockwise to East, then we make 3 right angles.
(c) If we start facing West and turn to West, then we make 1 complete round or 4 right angles.
(d) If we start facing South and turn to North, then we make 2 right angles.
Page No 92:
Question 7:
Q7. Where will the hour hand of a clock stop if it starts
(a) From 6 and turns through 1 right angle?
(b) From 8 and turns through 2 right angles?
(c) From 10 and turns through 3 right angles?
(d) From 7 and turns through 2 straight angles?
Answer:
In 1 complete revolution (clockwise or anticlockwise), the hour hand of a clock will rotate by 360º or 4 right angles.
If the hour hand of a clock starts from 6 and turns through 1 right angle, then it will stop at 9.
If the hour hand of a clock starts from 8 and turns through 2 right angles, then it will stop at 2.
If the hour hand of a clock starts from 10 and turns through 3 right angles, then it will stop at 7.
If the hour hand of a clock starts from 7 and turns through 2 straight angles, then it will stop at 7.
Page No 94:
Question 1:
Match the following:
(i) Straight angle (a) Less than onefourth of a revolution
(ii) Right angle (b) More than half a revolution
(iii) Acute angle (c) Half of a revolution
(iv) Obtuse angle (d) Onefourth of a revolution
(v) Reflex angle (e) Between of a revolution
(f) One complete revolution
Answer:
(i) Straight angle is of 180º and half of a revolution is 180º.
Hence, (i) ↔ (c)
(ii) Right angle is of 90º and onefourth of a revolution is 90º.
Hence, (ii) ↔ (d)
(iii) Acute angles are the angles less than 90º. Also, less than onefourth of a revolution is the angle less than 90º.
Hence, (iii) ↔ (a)
(iv) Obtuse angles are the angles greater than 90º but less than 180º. Also, between of a revolution is the angle whose measure lies between 90º and 180º.
Hence, (iv) ↔ (e)
(v) Reflex angles are the angles greater than 180º but less than 360º. Also, more than half a revolution is the angle whose measure is greater than 180º.
Hence, (v) ↔ (b)
Page No 95:
Question 2:
Classify each one of the following angles as right, straight, acute, obtuse or reflex:
Answer:
(a) Acute angle as its measure is less than 90º.
(b) Obtuse angle as its measure is more than 90º but less than 180º.
(c) Right angle as its measure is 90º.
(d) Reflex angle as its measure is more than 180º but less than 360º.
(e) Straight angle as its measure is 180º.
(f) Acute angle as its measure is less than 90º.
Page No 97:
Question 1:
What is the measure of (i) a right angle? (ii) a straight angle?
Answer:
(i) The measure of a right angle is 90°.
(ii) The measure of a straight angle is 180°.
Page No 97:
Question 2:
Say True or False:
(a) The measure of an acute angle < 90°
(b) The measure of an obtuse angle < 90°
(c) The measure of a reflex angle > 180°
(d) The measure of one complete revolution = 360°
(e) If m∠A = 53° and m∠B = 35°, then m∠A > m∠B.
Answer:
(a) True
The measure of an acute angle is less than 90°.
(b) False
The measure of an obtuse angle is greater than 90º but less than 180º.
(c) True
The measure of a reflex angle is greater than 180°.
(d) True
The measure of one complete revolution is 360º.
(e) True
Page No 97:
Question 3:
Write down the measures of
(a) Some acute angles. (b) Some obtuse angles.
(Give at least two examples of each).
Answer:
(a) 45°, 70°
(b) 105°, 132°
Page No 97:
Question 4:
Measure the angles given below using the Protractor and write down the measure.
Answer:
(a) 45º
(b) 120º
(c) 90º
(d) 60º, 90º, and 130º
Page No 98:
Question 5:
Which angle has a large measure? First estimate and then measure.
Measure of angle A =
Measure of angle B =
Answer:
Measure of angle A = 40º
Measure of angle B = 68º
∠B has the greater measure than ∠A.
Page No 98:
Question 6:
From these two angles which has larger measure? Estimate and then confirm by measuring them.
Answer:
The measures of these angles are 45º and 55º. Therefore, the angle shown in 2^{nd} figure is greater.
Page No 98:
Question 7:
Fill in the blanks with acute, obtuse, right or straight:
(a) An angle whose measure is less than that of a right angle is _______.
(b) An angle whose measure is greater than that of a right angle is _______.
(c) An angle whose measure is the sum of the measures of two right angles is _______.
(d) When the sum of the measures of two angles is that of a right angle, then each one of them is _______.
(e) When the sum of the measures of two angles is that of a straight angle, and if one of them is acute then the other should be _______.
Answer:
(a) Acute angle
(b) Obtuse angle (if the angle is less than 180º)
(c) Straight angle
(d) Acute angle
(e) Obtuse angle
Page No 98:
Question 8:
Find the measure of the angle shown in each figure. (First estimate with your eyes and then find the actual measure with a protractor).
Answer:
The measures of the angles shown in the above figure are 40º, 130º, 65º, 135º respectively.
Page No 98:
Question 9:
Find the angle measure between the hands of the clock in each figure:
Answer:
(a) 90°
(b) 30°
(c) 180°
Page No 99:
Question 10:
Investigate
In the given figure, the angle measures 30°. Look at the same figure through a magnifying glass. Does the angle become larger? Does the size of the angle change?
Answer:
The measure of this angle will not change.
Page No 99:
Question 11:
Measure and classify each angle:
Angle 
Measure 
Type 
∠AOB 
 
 
∠AOC 
 
 
∠BOC 
 
 
∠DOC 
 
 
∠DOA 
 
 
∠DOB 
 
 
Answer:
Angle 
Measure 
Type 
∠AOB 
40º 
Acute 
∠AOC 
125º 
Obtuse 
∠BOC 
85º 
Acute 
∠DOC 
95º 
Obtuse 
∠DOA 
140º 
Obtuse 
∠DOB 
180º 
Straight 
Page No 100:
Question 1:
Which of the following are models for perpendicular lines:
(a) The adjacent edges of a table top.
(b) The lines of a railway track.
(c) The line segments forming the letter ’L’
(d) The letter V.
Answer:
(a) The adjacent edges of a table top are perpendicular to each other.
(b) The lines of a railway track are parallel to each other.
(c) The line segments forming the letter ’L’ are perpendicular to each other.
(d) The sides of letter V are inclined at some acute angle on each other.
Hence, (a) and (c) are the models for perpendicular lines.
Page No 100:
Question 2:
Let be the perpendicular to the line segment. Let and intersect in the point A. What is the measure of ∠PAY?
Answer:
From the figure, it can be easily observed that the measure of ∠PAY is 90°.
Page No 100:
Question 3:
There are two setsquares in your box. What are the measures of the angles that are formed at their corners? Do they have any angle measure that is common?
Answer:
One has a measure of 90°, 45°, 45°.
Other has a measure of 90°, 30°, 60°.
Therefore, the angle of 90° measure is common between them.
Page No 100:
Question 4:
Study the diagram. The line l is perpendicular to line m.
(a) Is CE = EG?
(b) Does PE bisect CG?
(c) Identify any two line segments for which PE is the perpendicular bisector.
(d) Are these true?
(i) AC > FG.
(ii) CD = GH.
(iii) BC < EH.
Answer:
(a) Yes. As CE = EG = 2 units
(b) Yes. PE bisects CG since CE = EG.
(c) and
(d) (i) True. As length of AC and FG are of 2 units and 1 unit respectively.
(ii) True. As both have 1 unit length.
(iii) True. As the length of BC and EH are of 1 unit and 3 units respectively.
Page No 103:
Question 1:
Name the types of following triangles:
(a) Triangle with lengths of sides 7 cm, 8 cm and 9 cm.
(b) ΔABC with AB = 8.7 cm, AC = 7 cm and BC = 6 cm.
(c) ΔPQR such that PQ = QR = PR = 5 cm.
(d) ΔDEF with m∠D = 90°
(e) ΔXYZ with m∠Y = 90° and XY = YZ.
(f) ΔLMN with m∠L = 30°, m∠M = 70° and m∠N = 80°
Answer:
(a) Scalene triangle
(b) Scalene triangle
(c) Equilateral triangle
(d) Rightangled triangle
(e) Rightangled isosceles triangle
(f) Acuteangled triangle
Page No 103:
Question 2:
Match the following:
Measures of Triangle 
Type of Triangle 
(i) 3 sides of equal length 
(a) Scalene 
(ii) 2 sides of equal length 
(b) Isosceles right angled 
(iii) All sides are of different length 
(c) Obtuse angled 
(iv) 3 acute angles 
(d) Right angled 
(v) 1 right angle 
(e) Equilateral 
(vi) 1 obtuse angle 
(f) Acute angled 
(vii) 1 right angle with two sides of equal length 
(g) Isosceles 
Answer:
(i) Equilateral (e)
(ii) Isosceles (g)
(iii) Scalene (a)
(iv) Acuteangled (f)
(v) Rightangled (d)
(vi) Obtuseangled (c)
(vii) Isosceles rightangled (b)
Page No 103:
Question 3:
Name each of the following triangles in two different ways: (you may judge the nature of the angle by observation)
Answer:
(a) Acuteangled and isosceles
(b) Rightangled and scalene
(c) Obtuseangled and isosceles
(d) Rightangled and isosceles
(e) Acuteangled and equilateral
(f) Obtuseangled and scalene
Page No 104:
Question 4:
Try to construct triangles using match sticks. Some are shown here. Can you make a triangle with
(a) 3 matchsticks?
(b) 4 matchsticks?
(c) 5 matchsticks?
(d)6 matchsticks?
(Remember you have to use all the available matchsticks in each case)
Name the type of triangle in each case. If you cannot make a triangle, think of reasons for it.
Answer:
(a) By using 3 matchsticks, we can form a triangle as
(b) By using 4 matchsticks, we cannot form a triangle. This is because the sum of the lengths of any two sides of a triangle is always greater than the length of the remaining side of the triangle.
(c) By using 5 matchsticks, we can form a triangle as
(d) By using 6 matchsticks, we can form a triangle as
Page No 106:
Question 1:
Say True of False:
(a) Each angle of a rectangle is a right angle.
(b) The opposite sides of a rectangle are equal in length.
(c) The diagonals of a square are perpendicular to one another.
(d) All the sides of a rhombus are of equal length.
(e) All the sides of a parallelogram are of equal length.
(f) The opposite sides of a trapezium are parallel.
Answer:
(a) True
(b) True
(c) True
(d) True
(e) False
(f) False
Page No 106:
Question 2:
Give reasons for the following:
(a) A square can be thought of as a special rectangle.
(b) A rectangle can be thought of as a special parallelogram.
(c) A square can be thought of as a special rhombus.
(d) Squares, rectangles, parallelograms are all quadrilaterals.
(e) Square is also a parallelogram.
Answer:
(a) In a rectangle, all the interior angles are of the same measure, i.e., 90º and only the opposite sides of the rectangle are of the same length whereas in case of a square, all the interior angles are of 90° and all the sides are of the same length. In other words, a rectangle with all sides equal becomes a square. Therefore, a square is a special rectangle.
(b) Opposite sides of a parallelogram are parallel and equal. In a rectangle, the opposite sides are parallel and equal. Also, all the interior angles of the rectangle are of the same measure, i.e., 90º. In other words, a parallelogram with each angle a right angle becomes a rectangle. Therefore, a rectangle can be thought of as a special parallelogram.
(c) All sides of a rhombus and a square are equal. However, in case of a square, all interior angles are of 90º measure. A rhombus with each angle a right angle becomes a square. Therefore, a square can be thought of as a special rhombus.
(d) All are closed figures made of 4 line segments. Therefore, all these are quadrilaterals.
(e) Opposite sides of a parallelogram are parallel and equal. In a square, the opposite sides are parallel and the lengths of all the four sides are equal. Therefore, a square can be thought of as a special parallelogram.
Page No 106:
Question 3:
A figure is said to be regular if its sides are equal in length and angles are equal in measure. Can you identify the regular quadrilateral?
Answer:
In a square, all the interior angles are of 90° and all the sides are of the same length. Therefore, a square is a regular quadrilateral.
Page No 108:
Question 1:
Examine whether the following are polygons. If any one among them is not, say why?
Answer:
(a) It is not a polygon as it is not a closed figure.
(b) Yes, it is a polygon made of 6 sides.
(c) No, it is not made of line segments.
(d) No, it is not made of only line segments.
Page No 108:
Question 2:
Name each polygon.
Make two more examples of each of these.
Answer:
(a) The given figure is a quadrilateral as this closed figure is made of 4
line segments. Two more examples are
(b) The given figure is a triangle as this closed figure is made of 3 line segments. Two more examples are
(c) The given figure is a pentagon as this closed figure is made of 5 line segments. Two more examples are
(d) The given figure is an octagon as this closed figure is made of 8 line segments. Two more examples are
Page No 108:
Question 3:
Draw a rough sketch of a regular hexagon. Connecting any three of its vertices, draw a triangle. Identify the type of the triangle you have drawn.
Answer:
An isosceles triangle by joining three of the vertices of a hexagon can be drawn as follows.
Page No 108:
Question 4:
Draw a rough sketch of a regular octagon. (Use squared paper if you wish). Draw a rectangle by joining exactly four of the vertices of the octagon.
Answer:
Page No 108:
Question 5:
A diagonal is a line segment that joins any two vertices of the polygon and is not a side of the polygon. Draw a rough sketch of a pentagon and draw its diagonals.
Answer:
It can be observed here that AC, AD, BD, BE, CE are the diagonals.
Page No 111:
Question 1:
Match the following:
(a) 
Cone 
(i) 

(b) 
Sphere 
(ii) 

(c) 
Cylinder 
(iii) 

(d) 
Cuboid 
(iv) 

(e) 
Pyramid 
(v) 

Give two new examples of each shape.
Answer:
(a) (ii)
(b) (iv)
(c) (v)
(d) (iii)
(e) (i)
Page No 111:
Question 2:
What shape is
(a) Your instrument box? (b) A brick?
(c) A match box? (d) A roadroller?
(e) A sweet laddu?
Answer:
(a) Cuboid
(b) Cuboid
(c) Cuboid
(d) Cylinder
(e) Sphere
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