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#### Question 1:

Find each of the following ratios in the simplest form:
(i) 24 to 56
(ii) 84 paise to Rs 3
(iii) 4 kg to 750 g
(iv) 1.8 kg to 6 kg
(v) 48 minutes to 1 hour
(vi) 2.4 km to 900 m

#### Answer:

(i) 24:56 =     24  =     24 ​÷ 8     =    3
56       56 ​÷ 8            7
As the H.C.F. of 3 and 7 is 1, the simplest form of 24:56 is 3:7.

(ii) 84 paise to Rs 3 = Rs 0.84 to R. 3 =  0.84  =  0.84​ ÷ 3    0.28    28    =  28 ​÷  4    7
3             3 ​÷ 3             1          100      100 ​÷ 4        25
As the H.C.F. of 7 and 25 is 1, the simplest form of  0.84:3 is 7:25.

(iii) 4 kg:750 g = 4000 g:750 g =   4000 ​÷ 250     16
750 ​÷ 250            3
As the H.C.F. of 16 and 3 is 1, the simplest form of 4000:750 is 16:3.

(iv) 1.8 kg:6 kg  =   1.8   =   18   18 ​÷ 6  =     3
6           60      60 ​÷ 6        10
As the H.C.F. of 3 and 10 is 1, the simplest form of 1.8:6 is 3:1.

(v) 48 minutes to 1 hour = 48 minutes to 60 minutes = 48:60 =  48 ​÷ 12   4
60 ​÷ 12        5
As the H.C.F. of 4 and 5 is 1, the simplest form of 48:60 is 4:5.

(vi) 2.4 km to 900 m = 2400m:900m =    2400    24     24 ​÷ 3     8
900          9           9 ​÷ 3          3
As the H.C.F. of 8 and 3 is 1, the simplest form of 2400:900 is 8:3.

#### Question 2:

Express each of the following ratios in the simplest form:
(i) 36 : 90
(ii) 324 : 144
(iii) 85 : 561
(iv) 480 : 384
(v) 186 : 403
(vi) 777 : 1147

#### Answer:

(i) 36:90 =   36    =    36 ​÷ 18    =     2          (As the H.C.F. of 36 and 90 is 18.)
90          90 ​÷ 18            5
Since the H.C.F. of 2 and 5 is 1, the simplest form of 36:90 is 2:5.

(ii) 324:144 =   324   =    324 ​÷ 36    =    9       (As the H.C.F. of  324 and 144 is 36.)
144          144 ​÷ 36           4
Since the H.C.F. of 9 and 4 is 1, the simplest form of 324:144 is 9:4.

(iii) 85:561 =  85    85 ​÷ 17   =      5         (As the H.C.F. of 85 and 561 is 17.)
561      561 ​​÷ 17           33
Since the H.C.F. of 5 and 33 is 1, the simplest form of 85:561 is 5:33.

(iv) 480:384 =    480      480 ​÷ 96     5       (As the H.C.F. of 480 and 384 is 96.)
384          384 ​​÷ 96          4
Since the H.C.F. of 5 and 4 is 1, the simplest form of 480:384 is 5:4.

(v) 186:403 =     186   =   186 ÷ 31     6        (As the H.C.F. of 186 and 403 is 31.)
403        403 ÷ 31        13
Since the H.C.F. of 6 and 13 is 1, the simplest form of 186:403 is 6:13.

(vi) 777:1147 =  777  ​÷ 37       21           (As the H.C.F. of 777 and 1147 is 37.)
1147  ​÷  37         31
Since the H.C.F. of 21 and 31 is 1, the simplest form of 777:1147 is 21:31.

#### Question 3:

Write each of the following ratios in the simplest form:
(i) Rs 6.30 : Rs 16.80
(ii) 3 weeks : 30 days
(iii) 3 m 5 cm : 35 cm
(iv) 48 min : 2 hours 40 min
(v) 1 L 35 mL : 270 mL
(vi) 4 kg : 2 kg 500 g

#### Answer:

(i) Rs 6.30:Rs 16.80
6.30     =    63    =   63 ​÷ 21      3        (H.C.F. of 63 and 168 is 21.)
16.80         168        168  ​÷ 21        8
Ratio = 3 : 8
(ii)3 weeks:30 days = 21days:30 days          (1 week = 7 days)
21     =   21 ​÷ 3    7          (H.C.F. of 21 and 30 is 3.)
30          30 ​ ​÷ 3       10
Ratio = 7 : 10
(iii) 3 m 5 cm:35 cm = 305 cm:35 cm      (1 m = 100 cm)
305   305  ​÷ 5    61        (H.C.F. of 305 and 35 is 5.)
35         35  ​÷ 5          7
Ratio = 61:7
(iv) 48 min:2 hours 40 min = 48 min:160 min        (1 hour = 60 mins)
48     48  ​÷ 16      3         (H.C.F. of 48 and 160 is 16.)
160        160  ​÷ 16       10
Ratio = 3:10
(v) 1 L 35 mL:270 mL = 1035 mL:270 mL         (1 L = 1000 mL)
1035    1035  ​÷ 45    =   23        (H.C.F. of 1035 and 270 is 45.)
270           270  ​÷ 45          6
Ratio = 23:6
(vi) 4 kg:2 kg 500 g = 4000 g:2500 g        (1 kg= 1000 g)
4000   =   40  40  ​÷ 5    8     (H.C.F. of 40 and 25 is 5.)
2500         25      25  ​÷ 5        5
Ratio = 8:5

#### Question 4:

Mr Sahai and his wife are both school teachers and earn Rs 16800 and Rs 10500 per month respectively. Find the ratio of
(i) Mr Sahai's income to his wife's income;
(ii) Mrs Sahai's income to her husband's income;
(iii) Mr Sahai's income to the total income of the two.

#### Answer:

Mr Sahai's earning = Rs 16800
Mrs Sahai's earning = Rs 10500
(i) Ratio = 16800:10500 = 168:105 =  168  ​÷ 21  =           (H.C.F. of 168 and 105 is 21.)
105 ​ ​÷ 21           5
Mr Sahai's income:Mrs Sahai's income = 8:5
(ii)Ratio = 10500:16800 = 105:168 =  105  ​÷ 21   =    5        (H.C.F. of 168 and 105 is 21.)
168 ​ ​÷ 21          8
Mrs Sahai's income:Mr Sahai's income = 5:8

(iii) Total income = 16800 + 10500 = Rs  27300
Ratio = 16800:27300 = 168:273 =  168   =  168  ​÷ 21   (H.C.F. of 168 and 273 is 21.)
273        273  ​÷ 21     13
Mrs Sahai's income:Total income = 8:13

#### Question 5:

Rohit earns Rs 15300 and saves Rs 1224 per month. Find the ratio of
(i) his income and savings;
(ii) his income and expenditure;
(iii) his expenditure and savings.

#### Answer:

Rohit's income = Rs 15300
Rohit's savings = Rs 1224
(i) Income:Savings = 15300:1224 = 15300 ​÷ 612   25        (H.C.F. of 15300 and 1224 is 612.)
1224  ​÷ 612         2
Income:Savings = 25:2
(ii) Monthly expenditure = Rs (15300 $-$ 1224) = Rs 14076
Income:Expenditure = 15300:14076 =  15300  ÷ 612   25       (H.C.F. of 15300 and 14076 is 612.)
14076  ​÷ 612        23
Income:Expenditure = 25:23
(iii) Expenditure : Savings = 14076:1224 =  14076  ÷ 612  23       (H.C.F. of 14076 and 1224 is 612.)
1224  ​÷ 612         2
Expenditure:Savings = 23:2

#### Question 6:

The ratio of the number of male and female workers in a textile mill is 5 : 3. If there are 115 male workers, what is the numkber of female workers in the mill?

#### Answer:

Number of male:Number of female = 5:3
Let the number be x.
Number of male = 5x
​Number of female = 3x
Number of male workers = 115
Now, 5x = 115
⇒  x  115   = 23
5
Number of female workers in the mill = 3x = 3 × 23 = 69

#### Question 7:

The bosys and the girls in a school are in the ratio 9 : 5. If the total strength of the school is 448, find the number of girls.

#### Answer:

Boys:Girls = 9:5
Let the number of boys = 9x
Let the number of girls = 5x
Total strength of the school = 448
According to given condition, we have:
9x + 5x = 448
⇒         14x = 448
⇒            x  448   = 32
14
Number of boys = 9x = 9 × 32 = 288
Number of girls = 5x = 5 ​× 32 = 160

#### Question 8:

Divide Rs 1575 between Kamal and Madhu in the ratio 7 : 2.

#### Answer:

Kamal:Madhu = 7:2
Sum of the ratio terms = 7 + 2 = 9
Kamal's share =   7   × 1575 =   11025   = Rs 1225
9                         9
Madhu's share =   2   × 1575 =   3150   = Rs 350
9                       9

#### Question 9:

Divide Rs 3450 among A, B and C in the ratio 3 : 5 : 7.

#### Answer:

A:B:C = 3:5:7
Sum of the ratio terms = 3 + 5 +7 = 15
A's share =   3    × 3450 =   10350   = Rs 690
15                       15

B's share =   5   × 3450 =   17250   = Rs 1150
15                        15

C's share =     7   × 3450 =   24150  = Rs 1610
15                       15

#### Question 10:

Two numbers are in the ratio 11 : 12 and their sum is 460. Find the numbers.

#### Answer:

Two number are in the ratio 11:12.
Let the numbers be 11x and 12x.
Given:     11x + 12x = 460
⇒          23x = 460
⇒               x =   460   =  20
23
First number = 11x = 11 × 20 = 220
Second number = 12x = 12 × 20 = 240
Hence, the numbers are 220 and 240.

#### Question 11:

A 35-cm line segment is divided into two parts in the ratio 4 : 3. Find the length of each part.

#### Answer:

Ratio of the two parts of line segment = 4:3
Sum of the ratio terms = 4 + 3 = 7
First part =   4   × 35 cm = 4 × 5 cm = 20 cm
7
Second part =    3   × 35 cm = 3 × 5 cm = 15 cm
7

#### Question 12:

A factory produces electric bulbs. If 1 out of every 10 bulbs is defective and the factory produces 630 bulbs per day, find the number of defective bulbs produced each day.

#### Answer:

Number of bulbs produced each day = 630
Out of 10 bulbs, 1 is defective.
Number of defective bulbs =  630  = 63
10

$\therefore$ Number of defective bulbs produced each day = 63

#### Question 13:

Find the ratio of the price of a pencil to that of a ball pen if pencils cost Rs 96 per score and ball pens cost Rs 50.40 per dozen.

#### Answer:

Price of pencil = Rs 96 per score
Price of ball pen = Rs 50.40 per dozen
Price per unit of pencil =  96  = 4.8
20
Price per unit of ball pen =  50.40  =  4.2
12
Ratio =    4.8   =   48    48  ​÷ 6      8
4.2        42        42  ​÷  6         7
Price of a pencil:Price of a ball pen = 8:7

#### Question 14:

The ratio of the length of a field to its width is 5 : 3. Find its length if the width is 42 metres.

#### Answer:

Length:Width = 5:3
Let the length and the width of the field be 5x m and 3x m, respectively.
Width = 42 m
3x = 42
x  42   = 14
3
$\therefore$ Length = 5x = 5 × 14 = 70 metres

#### Question 15:

The ratio of income to savings of a family is 11 : 2. Find the expenditure if the savings is Rs 1520.

#### Answer:

Income:Savings = 11:2
Let the income and the saving be Rs 11x and Rs 2x, respectively.
Saving = Rs 1520
2x = 1520
x  1520   = 760
2
$\therefore$ Income = Rs 11x =Rs (11 × 760) = Rs 8360
Expenditure = Income $-$ Saving
= Rs (8360 $-$ 1520 )
= Rs 6840

#### Question 16:

The ratio of income to expenditure of a family is 7 : 6. Find the savings if the income is Rs 14000.

#### Answer:

Income:Expenditure = 7:6
Let the income and the expenditure be Rs 7x and Rs 6x, respectively.
Income = Rs 14000
7x = 14000
x =    14000  =  2000
7
Expenditure = Rs 6x = Rs 6 × 2000 = Rs 12000
$\therefore$ Saving = Income $-$ Expenditure
= Rs (14000 $-$ 12000)
= Rs 2000

#### Question 17:

The ratio of zinc and copper in an alloy is 7 : 9. If the weight of copper in the alloy is 11.7 kg find the weight of zinc in it.

#### Answer:

Let the weight of zinc be x kg.
Ratio of zinc and copper = 7:9
Weight of copper in the alloy = 11.7 kg
7     x
9       11.7
⇒  x =  11.7 × 7   81.9   = 9.1
9                9
Weight of zinc = 9.1 kg

#### Question 18:

A bus covers 128 km in 2 hours and a train covers 240 km in 3 hours. Find the ratio of their speeds.

#### Answer:

A bus covers 128 km in 2 hours.
Speed of the bus =   Distance  128 km   = 64 km/ hr
Time               2 hr

A train covers 240 km in 3 hours.
Speed of the train =  Distance   =  240   = 80 km /hr
Time             3

Ratio of their speeds = 64:80 =  64   64 ÷ 16    4
80       80 ÷ 16        5
$\therefore$ Ratio of the speeds of the bus and the train = 4:5

#### Question 19:

From each of the given pairs, find which ratio is larger:
(i) (3 : 4) or (9 : 16)
(ii) (5 : 12) or (17 : 30)
(iii) (3 : 7) or (4 : 9)
(iv) (1 : 2) or (13 : 27)

#### Answer:

(i) (3:4) or (9:16)

Making the denominator equal:

3 × 4   12  and 12    9
4 × 4       16         16       16

$\therefore$ (3:4) > (9:16)

(ii) (5:12) or (17:30)

Making the denominator equal:

5 × 5     25   and   17 × 2      34
12 × 5         60            30 × 2          60
⇒    25   <    34
60         60
$\therefore$ (5:12) < (17:30)

(iii) (3:7) or (4:9)

Making the denominator equal:

3 × 9   27   and   4 × 7   28
7 × 9       63            9 ​× 7       63
⇒       27   28
63       63

(3:7) < (4:9)

(iv) (1:2) or (13:27)

Making the denominator equal:

1× 27    27   and   13 × 2   =   26
2 × 27       54            27 ​× 2        54

⇒   27  26
54       54

(1:2) > (13:27)

#### Question 20:

Fill in the place holders:
(i)
(ii)
(iii)

#### Answer:

(i)   24   =   24 ​÷ 8    3   =    3 × 4  12
40         40 ​÷ 8      5          5  × 4      20

(ii)    36    36  ​÷ 9    =   4 × 3    12
63        63  ​÷ 9      7        7 × 3        21

(iii)   5    5 × 4   20   5 × 7    35
7        7 × 4       28        7 × 7         49

#### Question 1:

Determine if the following numbers are in proportion:
(i) 4, 6, 8, 12
(ii) 7, 42, 13, 78
(iii) 33, 121, 9, 96
(iv) 22, 33, 42, 63
(v) 32, 48, 70, 210
(vi) 150, 200, 250, 300

#### Answer:

(i) 4, 6, 8, 12
4  =    4 ​÷ 2   =   2 ;     8  =    8  ​÷ 4    2
6        6  ​÷ 2       3       12       12  ​÷ 4       3
Hence, 4:9::8:12 are in proportion.

(ii) 7, 42, 13, 78
7    7  ​÷ 7    1 ;     13   =  13  ​÷ 13     =    1
42      42  ​÷ 7      6        78        78  ​÷ 13           6
Hence, 7:42::13:78 are in proportion.

(iii) 33, 121, 9, 96
33    33  ​÷ 11    3   ;     9    9  ​÷ 3    3
121      121  ​÷ 11      11         96       96  ​÷ 3      32
Hence, 33:121::9:96 are not in proportion.

(iv) 22, 33, 42, 63

Hence, 22:33 :: 42 : 63 are not in proportion.

(v) 32, 48, 70, 210
32    32  ​÷ 6   7 ;    70    70  ​÷ 70   1
48        48  ​÷ 6       8     210      210  ​÷ 70      3
Hence, 32:48::70:210 are not in proportion.

(vi) 150, 200, 250, 300
150    150  ​÷ 50   3;   250  250  ​÷ 50  =   5
200         200  ​÷ 50        4   300      300  ​÷ 50       6
Hence, 150:200::250:300 are not in proportion.

#### Question 2:

Verify the following:
(i) 60 : 105 : : 84 : 147
(ii) 91 : 104 : : 119 : 136
(iii) 108 : 72 : : 129 : 86
(iv) 39 : 65 : : 141 : 235

#### Answer:

(i) 60:105::84:147
60    60  ​÷ 15    4         (H.C.F. of 60 and 105 is 15.)
105       105  ​÷ 15       7
84    84  ​÷ 21   4         (H.C.F. of 84 and 147 is 21.)
147     147  ​÷ 21        7
Hence, 60:105::84:147 are in proportion.
(ii) 91:104::119:136
91   91  ​÷ 13    7         (H.C.F. of 91 and 104 is 13.)
104       104  ​÷ 13      8
119   119  ​÷ 17   7      (H.C.F. of 11 and 136 is 17.)
136        136  ​÷ 17       8
Hence, 91:104::119:136 are in proportion.
(iii) 108:72::129:86
108   108  ​÷ 36    3        (H.C.F. of 108 and 72 is 36.)
72           72 ​ ​÷ 36        2
129    ​129  ​÷  43  3       (H.C.F. of 129 and 86 is 43.)
86          86   ​÷ 43        2
Hence, 108:72::129:86 are in proportion.
(iv) 39:65::141:235
39    39  ​÷ 13   3        (H.C.F. of 39 and 65 is 13.)
65         65  ​÷ 13      5
141    141  ​÷  47    3     (H.C.F. of 141 and 235 is 47.)
235         235  ​÷ 47        5
Hence, 39:65::141:235 are in proportion.

#### Question 3:

Find the value of x in each of the following proportions:
(i) 55 : 11 : : x : 6
(ii) 27 : x : : 63 : 84
(iii) 51 : 85 : : 57 : x
(iv) x : 92 : : 87 : 116

#### Answer:

(i) 55:11::x:6
Product of extremes = Product of means
55 × 6 = 11 × x
⇒                            11x = 330
⇒                               x 330   = 30
11
(ii) 27:x::63:84
Product of extremes = Product of means
27 ​× 84 = ​× 63
⇒                         63x = 2268
⇒                             x 2268  = 36
63
(iii) 51:85::57:x
Product of extremes = Product of means
51 × x = 85 × 57
⇒                           51x = 4845
⇒                               x =   4845   = 95
51
(iv) x:92::87:116
Product of extremes = Product of means
x ×  116 = 92 ​× 87
⇒                      116x = 8004
⇒                           x  =   8004  = 69
116

#### Question 4:

Write (T) for true and (F) for false in case of each of the following:
(i) 51 : 68 : : 85 : 102
(ii) 36 : 45 : : 80 : 100
(iii) 30 bags : 18 bags : : Rs 450 : Rs 270
(iv) 81 kg : 45 kg : : 18 men : 10 men
(v) 45 km : 60 km : : 12 h : 15 h
(vi) 32 kg : Rs 36 : : 8 kg : Rs 9

#### Answer:

(i) 51:68::85:102
Product of means = 68 × 85 = 5780
Product of extremes = 51 × 102 = 5202
Product of means ≠ Product of extremes
Hence, (F).
(ii) 36:45::80:100
Product of means = 45 ​× 80 = 3600
Product of extremes = 36 × 100 = 3600
Product of means = Product of extremes
Hence, (T).
(iii) 30 bags:18 bags::Rs 450:Rs 270
or 30:18::450:270
Product of means = 18 × 450 = 8100
Product of extremes = 30 ​× 270 = 8100
Product of means = Product of extremes
Hence, (T).
(iv) 81 kg:45 kg::18 men:10 men
or 81:45::18:10
Product of means = 45 × 18 = 810
Product of extremes = 81 × 10 = 810
Product of means = Product of extremes
Hence, (T).
(v) 45 km:60 km::12 h:15 h
or,45:60::12:15
Product of means = 60 × 12 = 720
Product of extremes = 45 × 15 = 675
Product of means ≠ Product of extremes
Hence, (F).
(vi) 32 kg:Rs 36::8 kg:Rs 9
Product of means = 36 × 8 = 288
Product of extremes = 32 × 9 = 288
Product of means = Product of extremes
Hence, (T).

#### Question 5:

Determine if the following ratios form a proportion:
(i) 25 cm : 1 m and Rs 40 : Rs 160
(ii) 39 litres : 65 litres and 6 bottles : 10 bottles
(iii) 200 mL : 2.5 L and Rs 4 : Rs 50
(iv) 2 kg : 80 kg and 25 g : 625 kg

#### Answer:

(i) 25 cm:1 m and Rs 40:Rs 160 (or) 25 cm:100 cm and Rs 40:Rs 160
25  25 ​÷ 25  and  40  40 ÷ 40  1
100      100 ​​÷ 25     4         160    160 ​÷ 40      4
Hence, they are in proportion.

(ii) 39 litres:65 litres and 6 bottles:10 bottles
39   39 ​÷ 13    3    and   6    6 ​÷ 2    3
65        65 ​​÷ 13       5            10      10 ​÷ 2        5
Hence they are  in proportion.

(iii) 200 mL:2.5 L and Rs 4:Rs 50 (or) 200 mL:2500 mL and Rs 4:Rs 50
200   =   2   and   4    4 ​÷ 2     2
2500      25           50       50 ÷ 2       25
Hence, they are in proportion.

(iv) 2 kg:80 kg and 25 g:625 kg  (or)  2 kg:80 kg and 25 g:625000 g
2   2 ​÷ 2     1    and   25       25 ​÷ 25        1
80      80 ​÷ 2       40         625000    625000 ​​÷ 25     25000
Hence, they are not in proportion.

#### Question 6:

In a proportion, the 1st, 2nd and 4th terms are 51, 68 and 108 respectively. Find the 3rd term.

#### Answer:

Let the 3rd term be x.
Thus, 51:68::x:108
We know:
Product of extremes = Product of means
51 × 108 = 68 × x
⇒                     5508 = 68x
⇒                          x 5508  = 81
68
Hence, the third term is 81.

#### Question 7:

The 1st, 3rd and 4th terms of a proportion are 12, 8 and 14 respectively. Find the 2nd term.

#### Answer:

Let the second term be x.
Then. 12:x::8:14
We know:
Product of extremes = Product of means
12 × 14 = 8x
⇒                       168 = 8x
​            ⇒                           x  168  = 21
8
Hence, the second term is 21.

#### Question 8:

Show that the following numbers are in continued proportion:
(i) 48, 60, 75
(ii) 36, 90, 225
(iii) 16, 84, 441

#### Answer:

(i) 48:60, 60:75
Product of means = 60 × 60 = 3600
Product of extremes = 48 × 75 = 3600
Product of means = Product of extremes
Hence, 48:60::60:75 are in continued proportion.

(ii) 36:90, 90:225
Product of means = 90 × 90 = 8100
Product of extremes = 36 × 225 = 8100
Product of means = Product of extremes
Hence, 36:90::90:225 are in continued proportion.

(iii) 16:84, 84:441
Product of means = 84 × 84 = 7056
Product of extremes = 16 × 441 = 7056
Product of means = Product of extremes
Hence, 16:84::84:441 are in continued proportion.

#### Question 9:

If 9, x, x 49 are in proportion, find the value of x.

#### Answer:

Given: 9:x::x:49
We know:
Product of means = Product of extremes
x × x = 9 × 49
⇒               x2 = 441
⇒               x2 = (21)2
⇒                x = 21

#### Question 10:

An electric pole casts a shadow of length 20 m at a time when a tree 6 m high casts a shadow of length 8 m. Find the height of the pole.

#### Answer:

Let the height of the pole = x m
Then, we have:
x:20::6:8
Now, we know:
Product of extremes = Product of means
8x = 20​ × 6
x 120  = 15
8
​Hence, the height of the pole is 15 m.

#### Question 11:

Find the value of x if 5 : 3 : : x : 6.

#### Answer:

5:3::x:6
We know:
Product of means = Product of extremes
3x = 5 ​× 6
⇒ x 30  = 10
3
$\therefore$ x = 10

#### Question 1:

If the cost of 14 m of cloth is Rs 1890, find the cost of 6 m of cloth.

#### Answer:

Cost of 14 m of cloth = Rs 1890
Cost of 1 m of cloth =  1890  = Rs 135
14
Cost of 6 m of cloth = 6​ × 135 = Rs 810

#### Question 2:

If the cost of a dozen soaps is Rs 285.60, what wil be the cost of 15 such soaps?

#### Answer:

Cost of dozen soaps = Rs 285.60
Cost of 1 soap =  285.60
12
Cost of 15 soaps = 15​ ×  285.60  4284  = Rs 357
12            12

#### Question 3:

If 9 kg of rice costs Rs 327.60, what will be the cost of 50 kg of rice?

#### Answer:

Cost of 9 kg of rice = Rs 327.60
Cost of 1 kg of rice =  327.60
9
Cost of 50 kg of rice = 50​ ×  327.60  16380  = Rs 1820
9              9
Hence, the cost of 50 kg of rice is Rs 1820.

#### Question 4:

If 22.5 m of a uniform iron rod weighs 85.5 kg, what will be the weight of 5 m of the  same rod?

#### Answer:

Weight of 22.5 m of uniform iron rod = 85.5 kg
Weight of 1 m of uniform iron rod =  85.5  kg
22.5
Weight of 5 m of uniform iron rod = 5​ ×  85.5  427.5  = 19 kg
22.5       22.5
Thus, the weight of 5 m of iron rod is 19 kg.

#### Question 5:

If 15 tins of the same size contain 234 kg of oil, how much oil will there be in 10 such tins?

#### Answer:

Oil contained by 15 tins = 234 kg
Oil contained by 1 tin =  234  kg
15
Oil contained by 10 tins = 10 ×  234  2340  = 156 kg
15         15

#### Question 6:

If 12 L of diesel is consumed by a car in covering a distance of 222 km, how many kilometres will it go in 22 L of diesel?

#### Answer:

Distance covered by a car in 12 L diesel = 222 km
Distance covered by it in 1 L diesel =  222  km
12
Distance covered by it in 22 L diesel = 22 ×  222  4884  = 407 km
12          12

#### Question 7:

A transport company charges Rs 540 to carry 25 tonnes of weight. What will it charge to carry 35 tonnes?

#### Answer:

Cost of transporting 25 tonnes of weight = Rs 540
Cost of transporting 1 tone of weight =  540
25
Cost of transporting 35 tonnes of weight = 35​ ×  540  18900  = Rs 756
25          25

#### Question 8:

4.5 g of an alloy of copper and zinc contains 3.5 g of copper. What weight of copper will there be in 18.9 g of the alloy?

#### Answer:

Let the weight of copper be x g.
​Then, 4.5:3.5::18.9:x
Product of extremes = Product of means
4.5 × x  = 3.5 × 18.9
⇒ x 66.15  = 14.7
4.5
So, the weight of copper is 14.7 g.

#### Question 9:

35 inland letters cost Rs 87.50. How many such letters can we buy for 315?

#### Answer:

Number of inland letters whose total cost is Rs 87.50 = 35
Number of inland letters of whose cost is Re 1 =   35
87.50
Number of inland letters whose cost is Rs 315 = 315​ ×   35    11025  = 126
87.50      87.50
Hence, we can buy 126 inland letters for Rs 315.

#### Question 10:

Cost of 4 dozen bananas is Rs 104. How many bananas can be purchased for Rs 6.50?

#### Answer:

Number of bananas that can be purchased for Rs 104 = 48 (4 dozen)
Number of bananas that can be purchased for Re 1 =  48
104
Number of bananas that can be purchased for Rs 6.50 = 6.50 ×  48   312  = 3
104       104
Hence, 3 bananas can be purchased for Rs 6.50.

#### Question 11:

The cost of 18 chairs is Rs 22770. How many such chairs can be bought for Rs 10120?

#### Answer:

Number of chairs that can be bought for Rs 22770 = 18
Number of chairs that can be bought for Re 1 =    18
22770
Number of chairs that can be bought for Rs 10120 = 10120 ×    18     182160  = 8
22770       22770

#### Question 12:

A car travels 195 km in 3 hours.
(i) How long will it take to travel 520 km?
(ii) How far will it travel in 7 hours with the same speed?

#### Answer:

(i) Time taken by the car to travel 195 km = 3 hours
Time taken by it to travel 1 km =   3   hours
195
Time taken by it to travel 520 km = 520 ×   3   1560  = 8 hours
195      195

(ii) Distance covered by the car in 3 hours = 195 km
Distance covered by it in 1 hour =  195  = 65 km
3
Distance covered by it in 7 hours = 7 × 65 = 455 km

#### Question 13:

A labourer earns Rs 1980 in 12 days.
(i) How much does he earn in 7 days?
(ii) In how many days will he earn Rs 2640?

#### Answer:

(i) Earning of a labourer in 12 days = Rs 1980
Earning of the labourer in 1 day =  1980  = Rs 165
12
Earning of the labourer in 7 days = 7​ × 165 = Rs 1155
(ii) Number of days taken by the labourer to earn Rs 1980 = 12 days
Number of days taken by him to earn Re 1 =  12  days
1980
Number of days taken by him to earn Rs 2640 = 2640 ×  12   31680  = 16 days
1980      1980

#### Question 14:

The weight of 65 books is 13 kg.
(i) What is the weight of 80 such books?
(ii) How many such books weigh 6.4 kg?

#### Answer:

Weight of 65 books = 13 kg
(i) Weight of 1 book =  13  kg
65
Weight of 80 books = 80 ×  13   1040   = 16 kg
65         65

(ii) Number of books weighing 13 kg = 65
Number of books weighing 1 kg =  65  = 5
13
Number of books weighing 6.4 kg = 6.4 × 5 = 32

#### Question 15:

If 48 boxes contain 6000 pens, how many such boxes will be needed for 1875 pens?

#### Answer:

Number of boxes containing 6000 pens = 48
Number of boxes containing 1 pen =   48
6000
Number of boxes containing 1875 pens = 1875 ×   48     90000  = 15
6000        6000
15 boxes are needed for 1875 pens.

#### Question 16:

24 workers can build a wall in 15 days. How many days will 9 workers take to build a similar wall?

#### Answer:

Number of days taken by 24 workers to build a wall = 15 days
Number of days taken by 1 worker to build the wall = 15 × 24 = 360 days         (less worker means more days)
Number of days taken by 9 workers to build the wall =  360  = 40 days
9

#### Question 17:

40 men can finish a piece of work in 26 days. How many men will be needed to finish it in 16 days?

#### Answer:

Number of men required to complete the work in 26 days = 40
Number of men required to complete the work in 1 day = 40 × 26 = 1040 men  (less men more days)
Number of men required to complete the work in 16 days =  1040  = 65
16

#### Question 18:

In an army capm, there were provisions for 550 men for 28 days. But, 700 men attended the camp. How long did the provisions last?

#### Answer:

Number of days the provisions will last for 550 men = 28 days
Number of days the provisions will last for 1 man = 28 × 550 = 15400 days  (less men means more days)
Number of days the provisions will last for 700 men =  15400  = 22 days
700
The provision will last for 22 days.

#### Question 19:

A given quantity of rice is sufficient for 60 persons for 3 days. How many days would the rice last for 18 persons?

#### Answer:

Number of days for which the given quantity of rice is sufficient for 60 persons = 3 days
Number of days for which it is sufficient for 1 person = 3 × 60 = 180 days      (less men means more days )
Number of days for which it is sufficient for 18 persons =  180  = 10 days
18

#### Question 1:

The ratio 92 : 115 in its simplest for is
(a) 23 : 25
(b) 18 : 23
(c) 3 : 5
(d) 4 : 5

#### Answer:

(d) 4 : 5
92:115 =   92 ​÷ 23   (As H.C.F. of 92 and 115 is 23.)
115 ​÷ 23       5

#### Question 2:

If 57 : x : : 51 : 85, then the value of x is
(a) 95
(b) 76
(c) 114
(d) none of these

#### Answer:

(a) 95
57:x::51:85
57   51
x        85
x 57 × 85
51
x 4845  = 95
51

#### Question 3:

If 25 : 35 : : 45 : x, then the value of x is
(a) 63
(b) 72
(c) 54
(d) none of these

#### Answer:

(a) 63
25:35::45:x
25  45
35       x
x 35 × 45  1575  = 63
25             25

#### Question 4:

If 4 : 5 : : x : 35, then the value of x is
(a) 42
(b) 32
(c) 28
(d) none of these

#### Answer:

(c) 28
4:5::x:35
⇒  x
5      35
x 4 × 35  = 4 × 7 = 28
5

#### Question 5:

If a, b, c, d are in proportion, then
(a) ac = bd
(b) ad = bc
(c) ab = cd
(d) none of these

#### Answer:

(b) ad = bc
Given:
a, b, c, d are in proportion.
a:b::c:d
a  c
b      d
ad = bc

#### Question 6:

If a, b, c are in proportion, then
(a) a2 = bc
(b) b2 = ac
(c) c2 = ab
(d) none of these

#### Answer:

(b) b2 = ac
Given:
a, b, c are in proportion.
a:b::b:c
Product of means = Product of extremes
⇒​ b2 = ac

#### Question 7:

Choose the correct statement:
(a) (5 : 8) > (3 : 4)
(b) (5 : 8) < (3 : 4)
(c) two ratios cannot be compared

#### Answer:

(b) (5 : 8) < (3 : 4)

We can write

Making the denominator equal:
5   and   3 × 2   6
8           4 × 2        8
As 6 > 5,   5    3
8        4

#### Question 8:

If Rs 760 is divided between A and B in the ratio 8 : 11, then B's share is
(a) Rs 440
(b) Rs 320
(c) Rs 430
(d) Rs 330

#### Answer:

(a) Rs 440
A:B = 8:11
Sum of ratio terms = 8 + 11 = 19
B's share =  11  × 760 =  8360  = Rs 440
19                  19

#### Question 9:

Two numbers are in the ratio 5 : 7 and the sum of these numbers is 252. The larger of these numbers is
(a) 85
(b) 119
(c) 105
(d) 147

#### Answer:

(d) 147
Ratio = 5:7
Let x be any number such that we have:
5x + 7x = 252
⇒ 12x = 252
x 252  = 21
12
Now, 5x = 5 × 21= 105
7x = 7 × 21 = 147

The largest number is 147.

#### Question 10:

The sides of a triangle are in the ratio 1 : 3 : 5 and its perimeter is 90 cm. The length of its largest side is
(a) 40 cm
(b) 50 cm
(c) 36 cm
(d) 54 cm

#### Answer:

(b) 50 cm
The sides of the triangle are in the ratio 1:3:5.
Let x be any number such that the sides are 1x cm, 3x cm and 5x cm.
1x + 3x + 5x = 90
⇒ 9x = 90
​⇒ x 90  = 10
9
First side = 1x = 1 ​× 10 = 10 cm
Second side = 3x = 3 ​× 10 = 30 cm
Third side = 5x = 5 × 10 = 50 cm
The length of the largest side is 50 cm.

#### Question 11:

The ratio of boys and girls in a school is 12 : 5. If the number of girls is 840, the total strength of the school is
(a) 1190
(b) 2380
(c) 2856
(d) 2142

#### Answer:

(c) 2856
Ratio of boys and girls = 12:5
Let x be any number such that the number of boys and girls are 12x and 5x, respectively.
Number of girls = 840
5x = 840
⇒ x 840  = 168
5
Number of boys = 12x = 12 × 168 = 2016
Number of girls = 840
Total strength of the school = 2016 + 840 = 2856

#### Question 12:

If the cost of 12 pens is Rs 138, then the cost of 14 such pens is
(a) Rs 164
(b) Rs 161
(c) Rs 118.30
(d) Rs 123.50

#### Answer:

(b) Rs 161
Cost of 12 pens = Rs 138
Cost of 1 pen = Rs  138
12
Cost of 14 pens = Rs  138  × 14 = Rs 1932  = Rs 161
12                     12

#### Question 13:

If 24 workers can build a wall in 15 days, how many days will 8 workers take to build a similar wall?
(a) 42 days
(b) 45 days
(c) 48 days
(d) none of these

#### Answer:

(b) 45 days
Time taken by 24 workers to build a wall = 15 days
Time taken by 1 worker to build a wall = 24 × 15 = 360 days        (clearly less workers will take more time to build a wall)
Time taken by 8 workers to build a wall =  360  = 45 days
8

#### Question 14:

If 40 men can finish a piece of work in 26 days, how many men will be required to finish it in 20 days?
(a) 52
(b) 31
(c) 13
(d) 65

#### Answer:

(a) 52
Number of men required to finish the work in 26 days = 40
Number of men required to finish it in 1 day = 40 × 26 = 1040 men          (More men means less days)
Number of men required to finish it in 20 days =  1040  = 52
20

#### Question 15:

In covering 111 km, a car consumes 6 L of petrol. How many kilometres will it go in 10 L of petrol?
(a) 172 km
(b) 185 km
(c) 205 km
(d) 266.4 km

#### Answer:

(b) 185 km
Distance covered in 6 L of petrol = 111 km
Distance covered in 1 L of  petrol =  111 km
6
Distance covered in 10 L of petrol =  111  × 10 =  1110  = 185 km
6                    6

#### Question 16:

In a fort, 550 men had provisions for 28 days. How many days will it last for 700 men?
(a) 22 days
(b) $35\frac{7}{11}$ days
(c) 34 days
(d) none of these

#### Answer:

(a) 22 days
Number of days for which 550 men had provisions = 28 days
Number of days for which 1 man had provisions = 28 × 550 = 15400 days (more men means less days)
Number of days for which 700 men had provisions =  15400  = 22 days
700

#### Question 17:

The angles of a triangle are in the ratio 3 : 1 : 2. The measure of the largest angle is
(a) 30°
(b) 60°
(c) 90°
(d) 120°

#### Answer:

(c) 90°
Ratio of the angles of a triangle is 3:1: 2
Let x be any number such that the three angles are (3x)$°$, (1x)$°$ and (2x)$°$.
We know, the sum of the angles of a triangle is 180$°$.
3x + 1x + 2x = 180
⇒ 6x = 180
​      ⇒ x 180  = 30
6
$\therefore$  (3x )$°$ = (3 ​× 30)$°$ = 90o
​     (1x)$°$ = (1​ × 30)$°$ = 30o
​     (2x)$°$ = (2 × 30)$°$ = 60o
The measure of the largest angle is 90o​.

#### Question 18:

Length and breadth of a rectangular field are in the ratio 5 : 4. If the width of the field is 36 m, what is its length?
(a) 40 m
(b) 45 m
(c) 54 m
(d) 50 m

#### Answer:

(b) 45 m
Length:Breadth = 5:4
Let x be any number such that the length and the breadth are 5x and 4x, respectively.
Now , 4x = 36
x 36  = 9
4
Length = 5x = 5 × 9 = 45 m

#### Question 19:

If a bus covers 195 km in 3 hours and a train covers 300 km in 4 hours, then the ratio of their speeds is
(a) 13 : 15
(b) 15 : 13
(c) 13 : 12
(d) 12 : 13

#### Answer:

(a) 13 : 15

Speed =  Distance
Time
Speed of the bus =  195 km = 65 km/hr
3 hr
Speed of the train =  300 km  = 75 km/hr
4 hr
Ratio =  65  65 ÷ 5  13  = 13:15
75       75 ÷ 5      15

#### Question 20:

If the cost of 5 bars of soap is Rs 82.50, then the cost of one dozen such bars is
(a) Rs 208
(b) Rs 192
(c) Rs 198
(d) Rs 204

#### Answer:

(c) Rs 198
Cost of 5 bars of soap = Rs 82.50
Cost of 1 bar of soap =  82.50  = Rs 16.5
5
Cost of 12 (1 dozen) bars of soap = 16.5 × 12 = Rs 198

#### Question 21:

If the cost of 30 packets of 8 pencils each is Rs 600, what is the cost of 25 packets of 12 pencils each?
(a) Rs 725
(b) Rs 750
(c) Rs 480
(d) Rs 720

#### Answer:

(b) Rs 750
Cost of 30 packets of 8 pencils each = Rs 600
Cost of 1 packet of 8 pencils =  600   = Rs 20
30
Cost of  1 pencil = Rs  20
8
Cost of 1 packet of 12 pencils = 12​ ×  20  240  = Rs 30
8         8
Cost of 25 packets of 12 pencils each = 25 × 30 = Rs 750

#### Question 22:

A rail journey of 75 km costs Rs 215. How much will a journey of 120 km cost?
(a) Rs 344
(b) Rs 324
(c) Rs 268.75
(d) none of these

#### Answer:

(a) Rs 344
Cost of rail journey of 75 km = Rs 215
Cost of rail journey of 1 km = Rs  215
75
Cost of rail journey of 120 km = 120​ ×  215   = 25800 = Rs 344
75          75

#### Question 23:

The 1st, 2nd and 4th terms of a proportion are 12, 21 and 14 respectively. Its third term is
(a) 16
(b) 18
(c) 21
(d) 8

#### Answer:

(d) 8
Let the third term be x.
Then, we have:
12:21::x:14
We know:
Product of means = Product of extremes
21x = 12 × 14
⇒ 21x = 168
⇒ x 168  = 8
21
The third term is 8

#### Question 24:

10 boys can dig a pitch in 12 hours. How long will 8 boys take to do it?
(a) 9 h 36 min
(b) 15 h
(c) 6 h 40 min
(d) 13 h 20 min

#### Answer:

(b) 15 h
Time taken by 10 boys to dig a pitch = 12 hours
Time taken by 1 boy to dig a pitch = 12 × 10 = 120 hours        (less boys means more time)
Time taken by 8 boys to dig a pitch =  120 = 15 hours
8

#### Question 1:

Find the ratio of:
(a) 90 cm to 1.05 m
(b) 35 minutes to an hour
(c) 150 mL to 2 L
(d) 2 dozens to a score

#### Answer:

(a) 90 cm:1.05 m (or) 90 cm:105 cm             (1 m = 100 cm)
90   90 ​÷ 15   6         (H.C.F. of 90 and 105 is 15.)
105      105 ​÷ 15      7
$\therefore$ 6:7

(b) 35 minutes to an hour (or) 35 minutes:60 minutes      (1 hour = 60 minutes)
35  35 ​÷ 5  7       (H.C.F. of 35 and 60 is 5.)
60       60 ​÷ 5     12
$\therefore$  7:12

(c) 150 mL to 2 L (or) 150 L:2000 L                (1 L= 1000 mL)
150   150 ​÷ 50   3    (HCF of 150 and 2000 is 50)
2000      2000​ ​÷50       40
$\therefore$ 3:40

(d) 2 dozens to a score (or) 24:20       (1 dozen = 12 and 1 score = 20)
24   24 ​÷ 4     (H.C.F. of 24 and 20 is 4)
20        20​ ​÷ 4      5
$\therefore$ 6:5

#### Question 2:

The ratio of zinc and copper in an alloy is 7 : 9. If the weight of copper in the alloy is 12.6 kg, find the weight of zinc in it.

#### Answer:

Ratio of zinc and copper in an alloy is = 7:9
Let the weight of zinc and copper in it be (7x) and (9x), respectively.
Now, the weight of a copper = 12.6 kg   (given)
∴ 9x = 12.6
⇒  x = 12.6  = 1.4
9
∴ Weight of zinc = 7x = 7​ × 1.4 = 9.8 kg

#### Question 3:

Divide Rs 1400 among A. B and C in the ratio 2 : 3 : 5.

#### Answer:

Given:
A:B:C = 2:3:5
Sum of ratio = 2 + 3 + 5 = 10
Total money = Rs 1400
Then, share of A =   2   × Rs 1400 = Rs  2800  = Rs 280
10                             10
Share of B =  ​× Rs 1400 = Rs  4200  = Rs 420
10                             10
Share of C =  ​× Rs 1400 = Rs  7000  = Rs 700
10                            10

#### Question 4:

Prove that (5 : 6) > (3 : 4).

#### Answer:

We can write:

By making their denominators same: (Taking the L.C.M. of 6 and 4, which is 24.)
Consider, 5:6
5 ​× 4  20
6 ​× 4      24

And,  3 ​× 6  18
4 ​× 6       24
As 20 > 18
Clearly, (5:6) > (3:4)

#### Question 5:

40 men can finish a piece of work in 26 days. How many men will be needed to finish it in 16 days?

#### Answer:

Number of men needed to finish a piece of work in 26 days = 40
Number of men needed to finish it in 1 day = 26 × 40 = 1040    (less days means more men)
Number of men needed to finish it in 16 days =  1040  = 65
16

#### Question 6:

In an army camp, there were provisions for 425 men for 30 days. How long did the provisions last for 375 men?

#### Answer:

Number of days for which provisions last for 425 men = 30 days
Number of days for which provisions last for 1 men = 30 × 425 = 12750 days. (less men means more days)
Number of days for which provisions last for 375 men = 12750  = 34 days
375
Hence, provisions will last for 34 days for 375 men.

#### Question 7:

Find the value of x when 36 : x : : x : 16.

#### Answer:

Given:
36:x::x:16
We know:
Product of means = Product of extremes
× x = 36 × 16
x2 = 576
x2 = 242
x = 24

#### Question 8:

Show that 48, 60, 75 are in continued proportion.

#### Answer:

Consider 48:60::60:75

Product of means = 60 × 60 = 3600
Product of extremes = 48 × 75 = 3600
So product of means = Product of extremes
Hence, 48, 60, 75 are in continued proportion.

#### Question 9:

Two numbers are in the ratio 3 : 5 and their sum is 96. The larger number is
(a) 36
(b) 42
(c) 60
(d) 70

#### Answer:

(c) 60
Ratio = 3:5
Let x be any number such that we have:
3x + 5x = 96
⇒ 8x = 96
⇒ x 96  = 12
8
The numbers are:
3x = 3 ​× 12 = 36
5x = 5 ​× 12 = 60
The largest number = 60

#### Question 10:

A car travels 288 km is 4 hours and a train travels 540 km in 6 hours. The ratio of their speeds is
(a) 5 : 4
(b) 4 : 5
(c) 5 : 6
(d) 3 : 5

#### Answer:

(b) 4 : 5
Speed of the car =  Distance  288 km  = 72 km/hr
Time            4 hr

Speed of the train =  Distance  540 km  = 90 km/hr
Time             6 hr

Ratio of their speeds = 72:90
where, 72  = 72 ​÷ 18      (H.C.F. of 72 and 90 is 18.)
90      90 ​÷ 18      5

#### Question 11:

The first three terms of a proportion are 12, 21 and 8 respectively. The 4th term is
(a) 18
(b) 16
(c) 14
(d) 20

#### Answer:

(c) 14
Let the 4th term be x, such that we have:
12:21::8:x
Now, we know:
Product of extremes = Product of means
12x = 21 × 8
x 168  = 14
12

#### Question 12:

The ratio 92 : 115 in simplest form is
(a) 23 : 25
(b) 18 : 23
(c) 3 : 5
(d) 4 : 5

#### Answer:

(d) 4 : 5
92:115
92  92 ​÷ 23          (H.C.F. of 92 and 115 is 23)
115     115 ​÷ 23      5

#### Question 13:

If 57 : x : : 51 : 85, then the value of x is
(a) 95
(b) 76
(c) 114
(d) none of these

#### Answer:

(a) 95
Given :
57:x::51:85
We know:
Product of means = Product of extremes
51x = 57 × 85
x =   4845  = 95
51

#### Question 14:

If 4 : 5 : : x : 45, then the value of x is
(a) 54
(b) 60
(c) 36
(d) 30

#### Answer:

(c) 36
Given:
4:5::x:45
We know:
Product of mean = Product of extremes
5x = 4 ​× 45
x =    180   = 36
5

#### Question 15:

If a, b, c are in proportion, then
(a) a2 = bc
(b) b2 = ac
(c) c2 = ab
(d) none of these

#### Answer:

(b) b2 = ac
Given:
a, b, c are in proportion, such that we have:
a:b::b:c
Now, we know:
Product of means = Product of extremes
b ​× b = a ​× c
b2 = ac

#### Question 16:

10 boys can dig a pitch in 12 hours. How long will 8 boys take to do it?
(a) 9 hrs 36 min
(b) 15 hrs
(c) 6 hrs 40 min
(d) 13 hrs 10 min

#### Answer:

(b) 15 hrs
Time taken by 10 boys to dig a pitch = 12 hours
Time taken by 1 boy to dig a pitch = 12 × 10 = 120 hours   (Less boys would take more hours.)
Time taken by 8 boys to dig a pitch =  120  = 15 hours
8

#### Question 17:

In covering 148 km, a car consumes 8 litres of petrol. How many kilometres will it go in 10 litres of petrol?
(a) 172 km
(b) 185 km
(c) 205 km
(d) 266.4 km

#### Answer:

(b) 185 km
Distance covered by a car in 8 litres of petrol = 148 km
Distance covered by it in 1 litre of petrol =  148  km
8
Distance covered by it in 10 litres of petrol = 10 × 148 = 1480 = 185 km
8         8

#### Question 18:

Fill in the blanks.
(i)
(ii) 90 cm : 1.5 m = ...... .
(iii) If 36 : 81 : : x : 63, then x = ...... .
(iv) If 25, 35, x are in proportion, then x = ...... .
(v) If 9, x, x, 49 are in proportion, then x = ...... .

#### Answer:

(i)

(ii) 90 cm:1.5 m (or) 90 cm:150 cm          (1 m = 100 cm)
90  9 ÷ 3              (H.C.F. of 9 and 15 is 3.)
150     15    15 ​​÷ 3      5

(iii) If 36:81::x:63
Product of means = Product of extremes
81x = 36 × 63
x =  2268
81
x = 28

(iv) Given:
25, 35, x are in proportion.
25:35::35:x

Now, we know:
Product of extremes = Product of means
25 × x = 35 ​× 35
25x1225
x =  1225  = 49
25

(v) Given:
9, xx, 49 are in proportion.
9:x::x:49
Now, we know:
Product of means = Product of extremes
x ​× = 9 ​× 49
x2 = 441
x2 = 212
x = 21

#### Question 19:

Write 'T' for true and 'F' for false for each of the statements given below:
(i) 30, 40, 45, 60 are in proportion.
(ii) 6 : 8 and 9 : 12 are equivalent ratios of 3 : 4.
(iii) a dozen : a score = 5 : 3.
(iv) 60 p : Rs 3 = 1 : 5.

#### Answer:

(i) 30, 40, 45, 60
30  =    3 ,    45  =   45 ​÷ 15  =         They are in proportion.
40        4      60        60 ​÷ 15         4
Hence, true.

(ii)  6  6 ​÷ 2  3 9 ​÷ 3  3     Hence, they are equivalent to 3:4.
8       8 ​÷ 2      4    2      12 ​÷ 3     4
Hence, true.
(iii) 1 dozen:1 score = 12:20
12  12 ​÷ 4
20      20 ​÷ 4       5
Hence, false.
(iv) 60p:Rs 3 = 60p:300p                        (1 Re = 100 p)
60  6 ​÷ 6
300     30    30 ​÷ 6      5

Hence, true.

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