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#### Question 1:

Complete the following statements:

(a) Two line segments are congruent if __________.

(b) Among two congruent angles, one has a measure of 70°; the measure of the other angle is __________.

(c) When we write ∠A = ∠ B, we actually mean __________.

(a) They have the same length

(b) 70°

(c) m ∠A = m ∠B

#### Question 2:

Give any two real-life examples for congruent shapes.

(i) Sheets of same letter pad

(ii) Biscuits in the same packet

#### Question 3:

If ΔABC ≅ ΔFED under the correspondence ABC ↔ FED, write all the Corresponding congruent parts of the triangles.

If these triangles are congruent, then the corresponding angles and sides will be equal to each other.

∠A ↔ ∠F

∠B ↔ ∠E

∠C ↔ ∠D

#### Question 4:

If ΔDEF ≅ ΔBCA, write the part(s) of ΔBCA that correspond to

(i) ∠E (ii) (iii) ∠F (iv)

(i) ∠C

(ii)

(iii) ∠A

(iv)

##### Video Solution for Congruence of Triangles (Page: 137 , Q.No.: 4)

NCERT Solution for Class 7 math - Congruence of Triangles 137 , Question 4

#### Question 1:

Which congruence criterion do you use in the following?

(a) Given: AC = DF

AB = DE

BC = EF

So, ΔABC ≅ ΔDEF

(b) Given: ZX = RP

RQ = ZY

∠PRQ = ∠XZY

So, ΔPQR ≅ ΔXYZ

(c) Given: ∠MLN = ∠FGH

∠NML = ∠GFH

ML = FG

So, ΔLMN ≅ ΔGFH

(d) Given: EB = DB

AE = BC

∠A = ∠C = 90°

So, ΔABE ≅ ΔCDB

(a) SSS, as the sides of ΔABC are equal to the sides of ΔDEF.

(b) SAS, as two sides and the angle included between these sides of ΔPQR are equal to two sides and the angle included between these sides of ΔXYZ.

(c) ASA, as two angles and the side included between these angles of ΔLMN are equal to two angles and the side included between these angles of ΔGFH.

(d) RHS, as in the given two right-angled triangles, one side and the hypotenuse are respectively equal.

#### Question 2:

You want to show that ΔART ≅ ΔPEN,

(a) If you have to use SSS criterion, then you need to show

(i) AR = (ii) RT = (iii) AT =

(b) If it is given that ∠T = ∠N and you are to use SAS criterion, you need to have

(i) RT = and (ii) PN =

(c) If it is given that AT = PN and you are to use ASA criterion, you need to have

(i) ? (ii) ?

(a)

(i) AR = PE

(ii) RT = EN

(iii) AT = PN

(b)

(i) RT = EN

(ii) PN = AT

(c)

(i) ∠ATR = ∠PNE

(ii) ∠RAT = ∠EPN

##### Video Solution for Congruence of Triangles (Page: 149 , Q.No.: 2)

NCERT Solution for Class 7 math - Congruence of Triangles 149 , Question 2

#### Question 3:

You have to show that ΔAMP ≅ AMQ.

In the following proof, supply the missing reasons.

 - Steps - Reasons (i) PM = QM (i) … (ii) ∠PMA = ∠QMA (ii) … (iii) AM = AM (iii) … (iv) ΔAMP ≅ ΔAMQ (iv) …

(i) Given

(ii) Given

(iii) Common

(iv) SAS, as the two sides and the angle included between these sides of ΔAMP are equal to two sides and the angle included between these sides of ΔAMQ.

#### Question 4:

In ΔABC, ∠A = 30°, ∠B = 40° and ∠C = 110°

In ΔPQR, ∠P = 30°, ∠Q = 40° and ∠R = 110°

A student says that ΔABC ≅ ΔPQR by AAA congruence criterion. Is he justified? Why or why not?

No. This property represents that these triangles have their respective angles of equal measure. However, this gives no information about their sides. The sides of these triangles have a ratio somewhat different than 1:1. Therefore, AAA property does not prove the two triangles congruent.

#### Question 5:

In the figure, the two triangles are congruent.

The corresponding parts are marked. We can write ΔRAT ≅ ?

It can be observed that,

∠RAT = ∠WON

∠ART = ∠OWN

AR = OW

Therefore, ΔRAT ΔWON, by ASA criterion.

##### Video Solution for Congruence of Triangles (Page: 150 , Q.No.: 5)

NCERT Solution for Class 7 math - Congruence of Triangles 150 , Question 5

#### Question 6:

Complete the congruence statement:

ΔBCA ≅?

ΔQRS ≅?

Given that, BC = BT

TA = CA

BA is common.

Therefore, ΔBCA ΔBTA

Similarly, PQ = RS

TQ = QS
PT = RQ

Therefore, ΔQRS ΔTPQ

#### Question 7:

In a squared sheet, draw two triangles of equal areas such that

(i) The triangles are congruent.

(ii) The triangles are not congruent.

What can you say about their perimeters?

(i)

Here, ΔABC and ΔPQR have the same area and are congruent to each other also. Also, the perimeter of both the triangles will be the same.

(ii)

Here, the two triangles have the same height and base. Thus, their areas are equal. However, these triangles are not congruent to each other. Also, the perimeter of both the triangles will not be the same.

##### Video Solution for Congruence of Triangles (Page: 150 , Q.No.: 7)

NCERT Solution for Class 7 math - Congruence of Triangles 150 , Question 7

#### Question 8:

Draw a rough sketch of two triangles such that they have five pairs of congruent parts but still the triangles are not congruent.

Consider two triangles $△$ABC and $△$XYZ.

In $△$ABC and $△$XYZ,
$\angle \mathrm{A}=\angle \mathrm{X}=40°\phantom{\rule{0ex}{0ex}}\angle \mathrm{B}=\angle \mathrm{Y}=80°\phantom{\rule{0ex}{0ex}}\angle \mathrm{C}=\angle \mathrm{Z}=60°\phantom{\rule{0ex}{0ex}}\mathrm{AB}=\mathrm{YZ}\phantom{\rule{0ex}{0ex}}\mathrm{AC}=\mathrm{XY}$

The given triangles have five pairs of congruent parts. But these two triangles are not congruent by any criterion of congruence.

#### Question 9:

If ΔABC and ΔPQR are to be congruent, name one additional pair of corresponding parts. What criterion did you use?

BC = QR

ΔABC ΔPQR (ASA criterion)

#### Question 10:

Explain, why

ΔABC ≅ ΔFED

Given that, ∠ABC = ∠FED (1)

∠BAC = ∠EFD (2)

The two angles of ΔABC are equal to the two respective angles of ΔFED. Also, the sum of all interior angles of a triangle is 180º. Therefore, third angle of both triangles will also be equal in measure.

∠BCA = ∠EDF (3)

Also, given that, BC = ED (4)

By using equation (1), (3), and (4), we obtain

ΔABC ≅ ΔFED (ASA criterion)

##### Video Solution for Congruence of Triangles (Page: 151 , Q.No.: 10)

NCERT Solution for Class 7 math - Congruence of Triangles 151 , Question 10

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