RD Sharma (2014) Solutions for Class 7 Math Chapter 25 Data Handling IV (Probability) are provided here with simple step-by-step explanations. These solutions for Data Handling IV (Probability) are extremely popular among class 7 students for Math Data Handling IV (Probability) Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the RD Sharma (2014) Book of class 7 Math Chapter 25 are provided here for you for free. You will also love the ad-free experience on Meritnation’s RD Sharma (2014) Solutions. All RD Sharma (2014) Solutions for class 7 Math are prepared by experts and are 100% accurate.

Page No 25.6:

Question 1:

A coin is tossed 1000 times with the following frequencies:

Head: 445, Tail: 555
When a coin is tossed at random, what is the probability of getting (i) a head? (ii) a tail?

Answer:

Total number of times a coin is tossed = 1000
Number of times a head comes up = 445
Number of times a tail comes up = 555

(i) Probability of getting a head = Number of headsTotal no. of trails=4451000=0.445

(ii) Probability of getting a tail = Number of tailsTotal no. of trails=5551000=0.555

Page No 25.6:

Question 2:

A die is thrown 100 times and outcomes are noted as given below:

Outcome: 1 2 3 4 5 6
Frequency: 21 9 14 23 18 15
If a die is thrown at random, find the probability of getting a/an.
(i) 3
(ii) 5
(iii) 4
(iv) Even number
(v) Odd number
(vi) Number less than 3.

Answer:

Total number of trials = 100

Number of times "1" comes up = 21
Number of times "2" comes up = 9
Number of times "3" comes up = 14
Number of times "4" comes up = 23
Number of times "5" comes up = 18
Number of times "6" comes up = 15


(i) Probability of getting 3

=frequency of 3Total no. of trails=14100=0.14

(ii) Probability of getting 5

= frequency of 5Total no. of trails=18100=0.18

(iii) Probability of getting 4

=frequency of 4Total no. of trails=23100=0.23

(iv) Frequency of getting an even no. = Frequency of 2 + Frequency of 4 + Frequency of 6 = 9+ 23 + 15 = 47

Probability of getting an even no. =frequency of even no.Total no. of trails=47100=0.47


(v) Frequency of getting an  odd no. = Frequency of 1 + Frequency of 3 + Frequency of 5 = 21+ 14 + 18 = 53

Probability of getting an odd no. =frequency of odd no.Total no. of trails=53100=0.53


(vi) Frequency of getting a no. less than 3 = Frequency of 1 + Frequency of 2= 21 + 9 = 30

Probability of getting a no. less than 3

=frequency of no. less than 3Total no. of trails=30100=0.30

Page No 25.6:

Question 3:

A box contains two pair of socks of two colours (black and white). I have picked out a white sock. I pick out one more with my eyes closed. What is the probability that I will make a pair?

Answer:

No. of socks in the box = 4
Let B and W denote black and white socks respectively.
Then we have:
S = {B,B,W,W}

If a white sock is picked out, then the total no. of socks left in the box = 3
No. of white socks left = 2-1 =1

Probability of getting a white sock

               =Number of white socks left in the boxTotal no. of socks left in the box=13

Page No 25.6:

Question 4:

Two coins are tossed simultaneously 500 times and the outcomes are noted as given below:

Outcome: Two heads
(HH)
One head
(HT or TH)
No head
(TT)
Frequency: 105 275 120
If same pair of coins is tossed at random, find the probability of getting (i) Two heads (ii) One head (iii) No head.

Answer:

Number of trials = 500
Number of outcomes of two heads (HH) =  105
Number of outcomes of one head (HT or TH) =  275
Number of outcomes of no head (TT) =  120

(i) Probability of getting two heads =frequency of getting 2 headsTotal number of trails=105500=21100

(ii) Probability of getting one head =frequency of getting 1 headTotal number of trails=255500=1120

(iii) Probability of getting no head =frequency of getting no headTotal number of trails=120500=625



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