Rs Aggarwal 2017 Solutions for Class 7 Math Chapter 17 Constructions are provided here with simple step-by-step explanations. These solutions for Constructions are extremely popular among Class 7 students for Math Constructions Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2017 Book of Class 7 Math Chapter 17 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2017 Solutions. All Rs Aggarwal 2017 Solutions for class Class 7 Math are prepared by experts and are 100% accurate.

#### Page No 207:

When we will measure angles of triangle using protractor then we find that all angles are equal to 60$°$

#### Page No 208:

$\begin{array}{l}\left(\mathrm{c}\right)x=35\\ \\ \left(2x-10\right)+\left(3x+15\right)=180\\ =>2x-10+3x+15=180\\ =>5x+5=180\\ =>5x=180-5\\ =>5x=175\\ =>x=\frac{\overline{)1}\overline{)7}{\overline{)5}}^{35}}{{\overline{)5}}^{1}}\\ =>x=35\end{array}$

#### Page No 213:

(i) The sum of the angles of a triangle is 180°.
(ii) The sum of any two sides of a triangle is always greater than the third side.
(iii) In ∆ABC, if ∠A = 90°, then:
BC2 = (AB2) + (BC2)

(iv) In ∆ABC:
AB = AC
Then, BD = DC

(v) In the given figure, side BC of ABC is produced to D and CE || BA.
If ∠BAC = 50°, then ∠ACE = 50°.