Rs Aggarwal 2017 for Class 7 Math Chapter 1 - Integers

Share with your friends

Rs Aggarwal 2017 Solutions for Class 7 Math Chapter 1 Integers are provided here with simple step-by-step explanations. These solutions for Integers are extremely popular among Class 7 students for Math Integers Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2017 Book of Class 7 Math Chapter 1 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2017 Solutions. All Rs Aggarwal 2017 Solutions for class Class 7 Math are prepared by experts and are 100% accurate.

Page No 157:

Question 1:

Find the SP when:

(i) CP = Rs 950, gain = 6%
(ii) CP = Rs 9600, gain = $16 \frac{2}{3} %$
(iii) CP = Rs 1540, loss = 4%
(iv) CP = Rs 8640, loss = $12 \frac{1}{2} %$

Answer:

(i) CP = Rs. 950
Gain = 6%

$SP = {\frac{(100 + G ain %)}{100} \times CP} = {\frac{(100 + 6)}{100} \times 950} = \frac{106}{100} \times 950 = \frac{100700}{100} = Rs . 1007$

(ii) CP = Rs. 9600
Gain = $16 \frac{2}{3} % = \frac{50}{3} %$

$S P = {\frac{(100 + G ain %)}{100} \times CP} = {\frac{(100 + \frac{50}{3})}{100} \times 9600} = \frac{350}{300} \times 9600 = \frac{3360}{3} = Rs . 11200$

(iii) CP = Rs. 1540
Loss = 4%

$S P = {\frac{(100 - L oss %)}{100} \times CP} = {\frac{(100 - 4)}{100} \times 1540} = \frac{96}{100} \times 1540 = \frac{147840}{100} = Rs . 1478.40$

(iv) CP = Rs. 8640
Loss = $12 \frac{1}{2} % = \frac{25}{2} %$

$S P = {\frac{(100 - L oss %)}{100} \times CP} = {\frac{(100 - \frac{25}{2})}{100} \times 8640} = \frac{175}{200} \times 8640 = \frac{1512000}{200} = Rs . 7560$

Page No 157:

Question 2:

Find the gain or loss per cent when:

(i) CP = Rs 2400 and SP = Rs 2592
(ii) CP = Rs 1650 and SP = Rs 1452
(iii) CP = Rs 12000 and SP = Rs 12800
(iv) CP = Rs 1800 and SP = Rs 1611

Answer:

(i) CP = Rs. 2400
SP = Rs. 2592
Gain = SP - CP = Rs. ( 2592 - 2400) = Rs. 192

Gain% = $(\frac{Gain}{CP} \times 100)$ $= (\frac{192}{2400} \times 100)$ = $8$

(ii) CP = Rs. 1650
SP = Rs. 1452
Loss = CP - SP = ( 1650 - 1452) = Rs. 198

   Loss% = $(\frac{L oss}{CP} \times 100)$ $= (\frac{198}{1650} \times 100) = 12$

(iii) CP = Rs. 12000 and SP = Rs. 12800
Gain = SP - CP = ( 12800 - 12000) = Rs. 800

   Gain% = $(\frac{Gain}{CP} \times 100) =$ $(\frac{800}{12000} \times 100) = 6.66$

(iv) CP = Rs. 1800
SP = Rs. 1611
Loss = CP - SP = ( 1800 - 1611) = Rs. 189

   Loss% = $(\frac{L oss}{CP} \times 100) =$ $(\frac{189}{1800} \times 100) = 10.5$

Page No 157:

Question 3:

Find the CP when:

(i) SP = Rs 924, gain = 10%
(ii) SP = Rs 1755, gain = $12 \frac{1}{2} %$
(iii) SP = Rs 8510, loss = 8%
(iv) SP = Rs 5600, loss = $6 \frac{2}{3} %$

Answer:

(i) SP = Rs. 924
Gain = 10%

$CP = {\frac{100}{(100 + G ain %)} \times SP}$

$= {\frac{100}{(100 + 10)} \times 924} = \frac{92400}{110} = Rs . 840$

(ii) SP = Rs. 1755
Gain = $12 \frac{1}{2} % = \frac{25}{2} %$

$CP = {\frac{100}{(100 + G ain %)} \times SP} = {\frac{100}{(100 + \frac{25}{2})} \times 1755} = {\frac{200}{225} \times 1755} = \frac{351000}{225} = Rs . 1560$

(iii) SP = Rs. 8510
Loss = 8%

$CP = {\frac{100}{(100 - L oss %)} \times SP} = {\frac{100}{(100 - 8)} \times 8510} = \frac{851000}{92} = Rs . 9250$

(iv) SP = Rs. 5600
Loss = $6 \frac{2}{3} % = \frac{20}{3} %$

$CP = {\frac{100}{(100 - L oss %)} \times SP} = {\frac{100}{(100 - \frac{20}{3})} \times 5600} = {\frac{300}{280} \times 5600} = \frac{168000}{28} = Rs . 6000$

Page No 157:

Question 4:

Sudhir bought an almirah for Rs 13600 and spent Rs 400 on its transportation. He sold it for Rs 16800. Find his gain per cent.

Answer:

Cost price of an almirah = Rs. 13600
Transportation cost = Rs. 400
Total cost price = Rs. (13600 + 400) = Rs. 14000
Selling price = Rs. 16800
Now, SP > CP
$Gain = SP - CP =$ ( 16800 - 14000) = Rs. 2800

$Gain % = (\frac{Gain}{CP} \times 100)$ %

$= (\frac{2800}{14000} \times 100)$ %

$= \frac{2800}{140} % = 20 %$

Page No 157:

Question 5:

Ravi purchased an old house for Rs 765000 and spent Rs 115000 on its repairs. Then, he sold it at a gain of 5%. How much did he get?

Answer:

Cost price of the house = Rs. 765000
Cost of repairing the house = Rs. 115000
Total Cost price = (765000 + 115000) = Rs. 880000
Ravi sold it at a gain of 5%.

$SP = {\frac{(100 + gain %)}{100} \times CP} = {\frac{(100 + 5)}{100} \times 880000} = \frac{105}{100} \times 880000 = Rs . 924000$

He gets Rs. 924000.

Page No 157:

Question 6:

A vendor busy lemons at Rs 25 per dozen and sells them at the rate of 5 for Rs 12. Find his gain or loss per cent.

Answer:

CP of 12 lemons (dozen) = Rs. 25
CP of one lemon = Rs. $\frac{25}{12}$

CP of five lemons = 5 × $\frac{25}{12} =$ $\frac{125}{12} = Rs . 10.42$

SP of five lemons = Rs. 12 (given)

Gain = SP - CP = ( 12 - 10.42 ) = Rs 1.58

$Gain % = (\frac{Gain}{CP} \times 100)$ %

$= (\frac{1.58}{10.42} \times 100)$ %

= 15.2%

Page No 157:

Question 7:

The selling price of 12 pens is equal to the cost price of 15 pens. Find the gain per cent.

Answer:

Let the cost price of the pen be Re 1.
Cost price of 12 pens = Rs 12
SP of 12 pens = CP of 15 pens = Rs 15
Gain = SP - CP = Rs (15 - 12) = Rs 3

$Gain % = (\frac{Gain}{CP} \times 100)$ %

$= (\frac{3}{12} \times 100) % = 25 %$

Gain% = 25%

Page No 157:

Question 8:

The selling price of 16 spoons is equal to the cost price of 15 spoons. Find the loss per cent.

Answer:

Let the cost price of one spoon be Re 1.
CP of 16 spoons = Rs 16
SP of 16 spoons = CP of 15 spoons = Rs 15
Loss = CP - SP = (16 - 15) = Re 1

$Loss % = (\frac{Loss}{CP} \times 100) % = (\frac{1}{16} \times 100) % = 6.25 %$

Loss% = 6.25%

Page No 157:

Question 9:

Manoj purchased a video for Rs 12000. He sold it to Rahul at a gain of 10%. If Rahul sells it to Rakesh at a loss of 5%, what did Rakesh pay for it?

Answer:

Cost price of a video = Rs. 12000
SP of a video at a gain of 10% = ${\frac{(100 + Gain %)}{100} \times CP}$

$= {\frac{(100 + 10)}{100} \times 12000} = {\frac{110}{100} \times 12000} = Rs . 13200$

So, Rahul purchased at a cost price of Rs. 13200.

Rahul sells it at a loss of 5%.

SP of a video at loss of 5% = ${\frac{(100 - Loss %)}{100} \times CP}$

$= {\frac{(100 - 5)}{100} \times 13200} = \frac{95}{100} \times 13200 = Rs . 12540$

∴ Rakesh pays = Rs. 12540

Page No 157:

Question 10:

On selling a sofa-set for Rs 21600, a dealer gains 8%. For how much did he purchase it?

Answer:

SP of the sofa set = Rs. 21600
Gain% = 8

$CP of the sofa se t = {\frac{100}{(100 + G a i n %)} \times S P} = {\frac{100}{(100 + 8)} \times 21600} = \frac{2160000}{108} = R s . 20000$

He purchased it at the cost of Rs. 20000.

Page No 157:

Question 11:

On selling a watch for Rs 11400, a shopkeeper loss 5%. For how much did the purchase it?

Answer:

SP of the watch = Rs 11400
Loss% = 5

$CP = {\frac{100}{(100 - Loss %)} \times SP}$

$= {\frac{100}{(100 - 5)} \times 11400} = \frac{11400}{95} = Rs . 12000$

He purchased it at the cost of Rs. 12000.

Page No 157:

Question 12:

On selling a calculator for Rs 1325, a man gains 6%. For how much should he sell it to gain 12%?

Answer:

SP of the calculator = Rs. 1325
Gain % = 6

CP of the calculator = ${\frac{100}{(100 + Gain %)} \times SP}$

$= {\frac{100}{(100 + 6)} \times 1325} = \frac{132500}{106} = Rs . 1250$

$SP of the calculator = {\frac{(100 + Gain %)}{100} \times CP} = {\frac{(100 + 12)}{100} \times 1250} = \frac{140000}{100} = Rs . 1400$

Page No 157:

Question 13:

On selling a computer for Rs 24480, a dealer loses 4%. For how much should he sell it to gain 4%?

Answer:

SP of a computer = Rs. 24480
Loss% = 4

$CP of the c omputer = {\frac{100}{(100 - Loss %)} \times SP} = {\frac{100}{(100 - 4)} \times 24480} = \frac{2448000}{96} = Rs . 25500$

In order to gain 4%:
$SP of the c omputer = {\frac{(100 + Gain %)}{100} \times CP} = {\frac{(100 + 4)}{100} \times 25500} = {\frac{104}{100} \times 25500} = \frac{2652000}{100} = Rs . 26520$

Page No 157:

Question 14:

A tricycle is sold at a gain of 15%. Had it been sold for Rs 108 more, the profit would have been 20%. Find its cost price.

Answer:

Let the CP of the tricycle be Rs. x

SP at 15% gain = ${\frac{(100 + G ain %)}{100} \times CP}$
$= {\frac{(100 + 15)}{100} \times x} = \frac{115}{100} x$

$= Rs . \frac{23}{20} x$

SP at 20% gain = $x \times \frac{120}{100} =$ $Rs . \frac{6}{5} x$

$\frac{6}{5} x - \frac{23}{20} x = 108 \Rightarrow \frac{24 x - 23 x}{20} = 108 \Rightarrow \frac{x}{20} = 108 \Rightarrow x = 2160$

Hence, the cost price of the tricycle is Rs. 2160

Page No 157:

Question 15:

Sandeep sold a television at a loss of 8%. If he had sold it for Rs 3360 more, he would have gained 6%. For how much did Sandeep buy it?

Answer:

Let CP of a television be Rs x.
SP at 8% loss = $\frac{(100 - 8)}{100} \times x = Rs . \frac{92}{100} x$
100
SP at 6% gain = $(\frac{100 + 6)}{100} \times x = Rs . \frac{106}{100} x$

      $\frac{106}{100} x - \frac{92}{100} x = 3360$

⇒ $\frac{14}{100} x = 3360$

⇒ $x = \frac{336000}{14} = 24000$

∴ CP = Rs. 24000
Sandeep bought it at the cost of Rs. 24000.

Page No 157:

Question 16:

Pankaj sells two cycles for Rs 2376 each. On one he gains 10% and on the other he loss 10%. Find his gain or loss per cent.

Answer:

SP of each cycle = Rs. 2376
He gains 10% in one cycle.
CP = ${\frac{100}{(100 + G ain %)} \times SP}$
$= {\frac{100}{(100 + 10)} \times 2376} = \frac{100}{110} \times 2376 = Rs . 2160$

He looses 10% in the second cycle.
CP = $\frac{100}{(100 - L oss %)} \times SP$

$= \frac{100}{(100 - 10)} \times 2376 = \frac{100}{90} \times 2376 = \frac{23760}{9} = Rs . 2640$

Total CP = $Rs . (2160 + 2640) = Rs . 4800$
Total SP = $Rs . (2376 + 2376) = Rs . 4752$
Loss = CP - SP = $Rs . (4800 - 4752) = Rs . 48$
$Loss %$ = $(\frac{Loss}{CP} \times 100)$ %
$= (\frac{48}{4800} \times 100) % = 1 %$

Page No 157:

Question 17:

On selling an exhaust fan for Rs 7350, a man gains $\frac{1}{6}$ of its cost price. Find the cost price of the fan.

Answer:

Let the CP of the exhaust fan be Rs. x.
Gain = $Rs . \frac{x}{6}$

SP = $R s (x + \frac{x}{6})$

SP = Rs. 7350

∴ $x + \frac{x}{6} = 7350$
⇒ $\frac{7}{6} x = 7350$
⇒ $x = \frac{7350 \times 6}{7} = \frac{44100}{7} = 6300$
CP of the fan = Rs. 6300

Page No 157:

Question 18:

Mohit sold a watch to Karim at a gain of 10% and Karim sold it to Rahim at a gain of 4%. If Rahim pays Rs 14300 for it, for how much did Mohit purchase it?

Answer:

Mohit sold a watch to Karim at Rs. x.
Mohit sold it at a gain of 10%.
SP of the watch = $110 % o f x$
= $(x + \frac{110}{100}) = Rs . \frac{11}{20} x$
Karim sold it to Rahim at a gain of 4%.
SP of the watch = $104 % o f \frac{11}{10} x = (\frac{104}{100} \times \frac{11}{10} x) = Rs . (\frac{26}{25} \times \frac{11}{10} x)$

But, Rahim pays Rs. 14300.
∴ $\frac{26}{25} \times \frac{11}{10} x = 14300$

$\Rightarrow x = \frac{14300 \times 25 \times 10}{26 \times 11} = \frac{3575000}{286} = 12500$

Mohit purchased it at Rs. 25000.

Page No 157:

Question 19:

If the manufacturer gains 10%, the wholesale dealer 15%, and the retailer 25% then what is the production cost of a washing machine whose retail price is Rs 37950?

Answer:

Let the production cost of a washing machine be Rs. x.
Profit of the manufacturer = 10%
SP of the manufacturer = $110 % o f x$
= $(x + \frac{110}{100}) = \frac{110}{100} x = Rs . \frac{11}{10}$
Profit of the wholesale dealer = 15%
SP of the wholesale dealer = $115 % o f R s \frac{11}{10} x$
= $R s (\frac{11}{10} x \times \frac{115}{100}) = R s (\frac{11}{10} x \times \frac{23}{20})$

Profit of the retailer = 25%
SP of the retailer = $125 % o f R s (\frac{11}{10} x \times \frac{23}{20})$

= $Rs . (\frac{11}{10} x \times \frac{23}{20} \times \frac{125}{100}) = Rs . (\frac{11}{10} x \times \frac{23}{20} \times \frac{5}{4})$

Given:
Retail price = Rs. 37950
∴ $(\frac{11}{10} x \times \frac{23}{20} \times \frac{5}{4}) = 37950$

$\Rightarrow x = \frac{37950 \times 10 \times 20 \times 4}{11 \times 23 \times 5}$
=> x= $\frac{30360000}{1265} = 24000$

∴ Production cost of a washing machine = Rs. 24000

Page No 157:

Question 20:

Mr Mehta purchased a video for Rs 20000 and a television for Rs 30000. On the video he lost 5% and on the television he gained 8%. Find his total gain or loss per cent.

Answer:

Mr. Mehta purchased a video at the cost of Rs. 20000.
Mr. Mehta purchased a television at the cost of Rs. 30000.
Total cost = Rs. (20000 + 30000) = Rs. 50000

He lost 5% on the video.

$SP = \frac{(100 - L oss %)}{100} \times CP = \frac{100 - 5}{100} \times 20000 = \frac{95}{100} \times 20000 = Rs . 19000$

He gained 8% on the television.

$SP = \frac{(100 + G ain %)}{100} \times CP = \frac{100 + 8}{100} \times 30000 = \frac{108}{100} \times 30000 = Rs . 32400$

Total SP = $Rs . (190000 + 32400) = Rs . 51400$

Total CP = Rs. 50000
Total Gain = SP - CP = $Rs . (51400 - 50000) = Rs . 1400$
$Gain % = (\frac{Gain}{CP} \times 100) % = (\frac{1400}{50000} \times 100) % = 2.8 %$

Page No 158:

Question 21:

By selling 36 oranges, a vendor suffers a loss equal to the selling price of 4 oranges. Find his loss per cent.

Answer:

Let the CP of 1 orange be Rs. x.
∴ CP of 36 oranges = Rs. 36x
Let SP of orange be Rs. y.
∴ SP of 36 oranges = Rs. 36y

Loss = SP of 4 oranges = $4 y$      (given)

We know:
Loss = CP - SP
⇒    $4 y = 36 x - 36 y$
⇒ $4 y + 36 y = 36 x$
  ⇒    $40 y = 36 x$
⇒ $10 y = 9 x$
⇒ $y = \frac{9}{10} x$

$Loss % = (\frac{Loss}{CP} \times 100)$ %

$= (\frac{4 y}{36 x} \times 100)$ %

$= (\frac{4 \times 9 x}{36 x \times 10} \times 100) % = 10 %$

Loss% = 10%

Page No 158:

Question 22:

By selling 8 dozen pencils, a shopkeeper gains the selling price of one dozen pencils. Find his gain per cent.

Answer:

Let the CP of one pencil be Rs. x.
Therefore, the CP of 96 pencils will be Rs. 96x.
Let SP of one pencil be Rs. y.
∴ SP of 96 pencils = Rs. 96y
Gain= SP of one dozen pencil = Rs.12y           (given)

Gain = SP - CP

   $\Rightarrow 12 y = 96 y - 96 x \Rightarrow 96 x = 96 y - 12 y \Rightarrow 96 x = 84 y \Rightarrow x = \frac{84 y}{96}$

$Gain % = (\frac{Gain}{CP} \times 100) % = (\frac{12 y}{96 x} \times 100) % = (\frac{12 y \times 96}{96 \times 84 y} \times 100) % = 14.28 %$

Page No 158:

Question 1:

Mark (✓) against the correct answer
A man buys a book for Rs 80 and sells it for Rs 100. His gain % is

(a) 20%
(b) 25%
(c) 120%
(d) 125%

Answer:

(b) 25%

CP of the book = Rs. 80
SP of the book = Rs. 100
Gain = SP - CP = Rs. (100 - 80) = Rs. 20
$Gain % = (\frac{Gain}{CP} \times 100) % = (\frac{20}{80} \times 100) % = 25 %$

Page No 158:

Question 2:

Mark (✓) against the correct answer
A football is bought for Rs 120 and sold for Rs 105. The loss % is

(a) $12 \frac{1}{2} %$
(b) $14 \frac{2}{7} %$
(c) $16 \frac{2}{3} %$
(d) $13 \frac{1}{3} %$

Answer:

(a) $12 \frac{1}{2} %$

CP of a football = Rs. 120
SP of a football = Rs. 105

CP>SP
∴ Loss = CP - SP = Rs. ( 120 - 105 ) = Rs. 15
$Loss % = (\frac{Loss}{CP} \times 100) % = (\frac{15}{120} \times 100) % = \frac{25}{2} % = 12 \frac{1}{2} %$

Page No 158:

Question 3:

Mark (✓) against the correct answer
On selling a bat for Rs 100, a man gains Rs 20. His gain % is

(a) 20%
(b) 25%
(c) 18%
(d) 22%

Answer:

(b) 25%

SP of the bat = Rs. 100
Gain = Rs. 20

Gain = SP - CP
⇒ 20 = 100 - CP
⇒ CP = 100 - 20 = Rs. 80

$Gain % = (\frac{Gain}{CP} \times 100) % = (\frac{20}{80} \times 100) % = 25 %$

Page No 158:

Question 4:

Mark (✓) against the correct answer
On selling a racket for Rs 198, a shopkeeper gains 10%. The cost price of the racket is

(a) Rs 180
(b) Rs 178.20
(c) Rs 217.80
(d) Rs 212.50

Answer:

(a) Rs. 180

SP of the racket = Rs. 198
Gain% = 10

$CP of the r acket = {\frac{100}{(100 + Gain %)} \times 100} = {\frac{100}{(100 + 10)} \times 198} = \frac{100}{110} \times 198 = Rs . 180$

Page No 158:

Question 5:

Mark (✓) against the correct answer
On selling a jug for Rs 144, a man loses $\frac{1}{7}$ of his outlay. If it is sold for Rs 189, what is the gain%?

(a) 50%
(b) 25%
(c) 30%
(d) 12%

Answer:

Let the cost price be Rs. x.
Loss = $Rs . \frac{x}{7}$
∴ SP = $(x - \frac{x}{7}) = Rs . \frac{6}{7} x$

Given:
SP = Rs. 144

∴   $\frac{6}{7} x = 144$
⇒ $x = \frac{144 \times 7}{6} = Rs . 168$

∴ CP = Rs. 168
SP = Rs. 144

New SP = Rs. 189
Gain = SP - CP = $Rs . (189 - 168) = Rs . 21$

$Gain % = (\frac{Gain}{CP} \times 100) % = (\frac{21}{168} \times 100) % = 12.5 %$

The correct answer is 12.5%.
All the given options are wrong.

Page No 158:

Question 6:

Mark (✓) against the correct answer
On selling a pen for Rs 48, a shopkeeper loses 20%. In order to gain 20% what would be the selling price?

(a) Rs 52
(b) Rs 56
(c) Rs 68
(d) Rs 72

Answer:

(d) Rs. 72

SP of the pen = Rs. 48
Loses = 20%
Then , $CP = {\frac{100}{(100 - Loss %)} \times SP}$
$= {\frac{100}{(100 - 20)} \times 48} = Rs . 60$

In order to gain 20%:

$SP = {\frac{(100 + Gain %)}{100} \times CP} = {\frac{(100 + 20)}{100} \times 60} = \frac{120}{100} \times 60 = Rs . 72$

Page No 158:

Question 7:

Mark (✓) against the correct answer
If the cost price of 12 pencils is equal to the selling price of 15 pencils, then the loss% is

(a) 20%
(b) 25%
(c) 3%
(d) $16 \frac{2}{3} %$

Answer:

(a) 20%

Let the cost price of each pencil be Rs.1
Cost of 15 pencils = Rs 15
SP of 15 pencil = CP of 12 pencil = Rs 12
∴ CP = Rs 15
SP = Rs 12

Loss = CP - SP = $Rs (15 - 12) = Rs 3$

$Los s % = (\frac{Loss}{CP} \times 100) % = (\frac{3}{15} \times 100) % = \frac{300}{15} % = 20 %$

Page No 158:

Question 8:

Mark (✓) against the correct answer
If the cost price of 4 toffees be equal to the selling price of 3 toffees, then the gain% is

(a) 25%
(b) 30%
(c) $16 \frac{2}{3} %$
(d) $33 \frac{1}{3} %$

Answer:

(d) $33 \frac{1}{3} %$

Let the cost price of each toffee be Rs. 1
Cost price of three toffees = Rs 3
SP of three toffees = CP of four toffees = Rs 4

CP = Rs 3
SP = Rs 4

Gain = SP - CP = $Rs (4 - 3) = Re 1$
$G a i n % = (\frac{G a i n}{C P} \times 100) % = (\frac{1}{3} \times 100) % = \frac{100}{3} % = 33 \frac{1}{3} %$

Page No 158:

Question 9:

Mark (✓) against the correct answer
On selling an article for Rs 144 a man loses 10%. At what price should he sell it to gain 10%?

(a) Rs 158.40
(b) Rs 172.80
(c) Rs 176
(d) Rs 192

Answer:

(c) Rs. 176

SP of an article = Rs. 144
Loss% = 10
$C P = {\frac{100}{(100 - Loss %)} \times S P} = {\frac{100}{(100 - 10)} \times 144} = \frac{100}{90} \times 144 = \frac{1440}{9} = Rs . 160$

In order to gain 10%:

$S . P . = \frac{(100 + Gain %)}{100} \times C P = \frac{(100 + 10)}{100} \times 160 = \frac{110}{100} \times 160 = Rs . 176$

Page No 159:

Question 10:

Mark (✓) against the correct answer
A vendor bought lemons at 6 for a rupee and sold them at 4 for a rupee. His gain % is

(a) 50%
(b) 40%
(c) $33 \frac{1}{3} %$
(d) $16 \frac{2}{3} %$

Answer:

(a) 50%

CP of six lemons = Re 1
CP of one lemon = $Rs \frac{1}{6}$

CP of four lemon = $Rs \frac{4}{6}$
SP of four lemon = Re 1

Gain = $1 - \frac{4}{6} = \frac{2}{6} = Rs \frac{1}{3}$
$Gain % = (\frac{Gain}{C P} \times 100) = (\frac{3}{2 \times 3} \times 100) = \frac{100}{2} = 50$

Page No 159:

Question 11:

Mark (✓) against the correct answer
On selling a chair for Rs 720, a man gains 20%. The cost price of the chair is

(a) Rs 864
(b) Rs 576
(c) Rs 650
(d) Rs 600

Answer:

(d)Rs. 600

SP of the chair = Rs 720
Gain% = 20

$C . P . = {\frac{100}{(100 + Profit percentage)} \times S . P .} = {\frac{100}{120} \times 720} = \frac{7200}{12} = Rs . 600$

Page No 159:

Question 12:

Mark (✓) against the correct answer
On selling a stool for Rs 630, a man loses 10%. The cost price of the stool is

(a) Rs 567
(b) Rs 693
(c) Rs 700
(d) Rs 730

Answer:

(c) Rs. 700

SP of a stool = Rs 630
Loss% = 10
$C P = {\frac{100}{(100 - L oss %)} \times S P} = {\frac{100}{(100 - 10)} \times 630} = \frac{100}{90} \times 630 = Rs 700$

Page No 160:

Question 1:

By selling a chair for Rs 1375 a man gains 10%. Find its cost price.

Answer:

SP of the chair = Rs 1375
Gain% = 10

$CP of the c hair = {\frac{100}{(100 + Gain %)} \times SP}$

$= {\frac{100}{(100 + 10)} \times 1375} = \frac{137500}{110} = Rs . 1250$

Page No 160:

Question 2:

If the selling price of 10 pens is equal to the cost price of 14 pens, find gain per cent.

Answer:

Let the cost of each pen be Rs. 1
CP of 10 pens = Rs. 10
SP of 10 pens = CP of 14 pens = Rs. 14
Gain = SP - CP = 14-10= Rs. 4
$Gain % = (\frac{Gain}{CP} \times 100) % = (\frac{4}{10} \times 100) % = 40 %$

Page No 160:

Question 3:

On selling a fan for Rs 2585 a man gains $\frac{1}{10}$ of its cost price. Find the cost price of tha fan.

Answer:

Let the cost price of the fan be Rs. x.
Gain = $Rs . \frac{x}{10}$
SP of the fan = $(x + \frac{x}{10}) = Rs . \frac{11}{10} x$
SP of the fan = $Rs . 2585$
∴ $\frac{11}{10} x = 2585$
⇒ $11 x = 25850$
⇒ $x = \frac{25850}{11} = 2350$

So, CP of the fan is Rs. 2350.

Page No 160:

Question 4:

A man buys lemons at 6 for Rs 10 and sells at 8 for Rs 15. Find his gain per cent.

Answer:

Cost price of six lemons = Rs. 10
Cost price of one lemon = $Rs . \frac{10}{6}$
Cost price of eight lemons = $8 \times \frac{10}{6} = Rs . \frac{80}{6} = Rs . 13.33$
Selling price of eight lemons = Rs. 15

$Gain = S P - C P = Rs . (15 - 13.33) = Rs . 1.67$

Gain% = $(\frac{Gain}{C . P .} \times 100)$ %
$= (\frac{1.67}{13.33} \times 100)$ %
$= 12.5$ %

Page No 160:

Question 5:

On selling a bat for Rs 486 a man loses 10%. Find the cost price of the bat.

Answer:

SP of the bat = Rs 486
Loss = 10%
CP of the bat = ${\frac{100}{(100 - Loss %)} \times S P}$
$= {\frac{100}{(100 - 10)} \times 486} = \frac{48600}{90} = Rs 540$

CP of the bat = Rs 540

Page No 160:

Question 6:

Mark (✓) against the correct answer
On selling a football for Rs 100, a man gains Rs 15. The cost price of the football is

(a) Rs 115
(b) Rs 85
(c) Rs 70
(d) Rs 130

Answer:

(b) Rs 85

SP of a football = Rs 100
Gain = Rs 15
Gain = SP - CP
⇒ 15 = 100 - CP
⇒ CP = Rs (100 - 15)
⇒ CP= Rs 85

Page No 160:

Question 7:

Mark (✓) against the correct answer
A vendor buys lemons at Rs 25 per dozen and sells at 5 for Rs 12. His gain per cent is

(a) 14.5%
(b) 15%
(c) 15.2%
(d) 16%

Answer:

(c) 15.2%

Cost price of 12 bananas = Rs. 25
Cost price of one banana = $Rs . \frac{25}{12}$
$Cost price of five banana s = Rs . 5 \times \frac{25}{12} = Rs . \frac{125}{12} = Rs . 10.42$

He sells five bananas at the cost (SP) of Rs. 12.
Gain = SP - CP

= $= Rs . (12 - 10.42) = Rs . 1.58$

$Gain % = (\frac{Gain}{C P} \times 100) % = (\frac{1.58}{10.4} \times 100) % = 15.2 %$

Page No 160:

Question 8:

Mark (✓) against the correct answer
On selling a jug for Rs 168, a man loses $\frac{1}{7}$ of his outlay. The cost price of the jug is

(a) Rs 144
(b) Rs 192
(c) Rs 196
(d) none of these

Answer:

(c) Rs. 196

Let the cost price of the jug be Rs. x.
Loss = $Rs . \frac{x}{7}$
SP of the jug = CP - Loss
$= Rs . (x - \frac{x}{7}) = Rs . \frac{6}{7} x$

SP of the jug = $R s 168$ (given)

∴ $\frac{6}{7} x = 168$
$\Rightarrow = \frac{168 \times 7}{6} \Rightarrow x = \frac{1176}{6} \Rightarrow x = 196$

∴ CP of the jug = $Rs . 196$

Page No 160:

Question 9:

Mark (✓) against the correct answer
If the cost price of 5 bananas be equal to the selling price of 3 bananas, then gain per cent is

(a) $33 \frac{1}{3} %$
(b) 15%
(c) $66 \frac{2}{3} %$
(d) 40%

Answer:

(c) $66 \frac{2}{3} %$

Let the cost price of each banana be Re 1.
Cost price of three bananas = Rs. 3
SP of three bananas = CP of five bananas = Rs. 5
Gain = SP - CP = $Rs . (5 - 3) = Rs . 2$

$Gain % = (\frac{Gain}{C P} \times 100) % = (\frac{2}{3} \times 100) % = (\frac{200}{3}) % = 66 \frac{2}{3} %$

Page No 160:

Question 10:

Fill in the blanks.

(i) Loss = (CP) − (......).
(ii) CP = $\frac{100 \times SP}{(. . . . . . + . . . . . .)}$ .
(iii) Profit or loss is always reckoned on ...... .
(iv) $\frac{100}{(100 - loss %)} \times SP = . . . . . . .$

Answer:

(i) Loss = (CP) - (SP)

(ii) CP = $\frac{100 \times S P}{(100 + Gain %)}$

(iii) Profit or loss is always reckoned on the cost price.
(iv) $\frac{100 \times SP}{(100 - loss %)}$ = CP

Page No 160:

Question 11:

Write 'T' for true and 'F' for false

(i) Loss is reckoned on selling price.
(ii) Gain is reckoned on cost price.
(iii) $CP = \frac{100 \times SP}{(100 - loss %)} .$
(iv) Loss = (CP) − (SP).

Answer:

(i) False
Gain or loss is always reckoned on the cost price.

(ii) True
(iii) True
(iv) True

View NCERT Solutions for all chapters of Class 7