RS Aggarwal 2018 Solutions for Class 7 Math Chapter 3 - Decimals

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Page No 39:

Question 1:

Convert each of the following into a fraction in its simplest form:

(i) .8
(ii) .75
(iii) .06
(iv) .285

Answer:

We have:

(i) $0.8 = \frac{8}{10} = \frac{8 \div 2}{10 \div 2} = \frac{4}{5}$

(ii) $0.75 = \frac{75}{100} = \frac{75 \div 25}{100 \div 25} = \frac{3}{4}$

(iii) $0.06 = \frac{6}{100} = \frac{6 \div 2}{100 \div 2} = \frac{3}{50}$

(iv) $0.285 = \frac{285}{1000} = \frac{285 \div 5}{1000 \div 5} = \frac{57}{200}$

Page No 39:

Question 2:

Convert each of the following as a mixed fraction:

(i) 5.6
(ii) 12.25
(iii) 6.004
(iv) 4.625

Answer:

We have:

(i) $5.6 = \frac{56}{10} = \frac{56 \div 2}{10 \div 2} = \frac{28}{5} = 5 \frac{3}{5}$

(ii) $12.25 = \frac{1225}{100} = \frac{1225 \div 25}{100 \div 25} = \frac{49}{4} = 12 \frac{1}{4}$

(iii) $6.004 = \frac{6004}{1000} = \frac{6004 \div 4}{1000 \div 4} = \frac{1501}{250} = 6 \frac{1}{250}$

(iv) $4.625 = \frac{4625}{1000} = \frac{4625 \div 125}{1000 \div 125} = \frac{37}{8} = 4 \frac{5}{8}$

Page No 39:

Question 3:

Convert each of the following into like decimals:

(i) $\frac{47}{10}$
(ii) $\frac{156}{100}$
(iii) $\frac{2516}{100}$
(iv) $\frac{3524}{1000}$
(v) $\frac{25}{8}$
(vi) $3 \frac{2}{5}$
(vii) $2 \frac{2}{25}$
(viii) $\frac{17}{20}$

Answer:

(i) $\frac{47}{10}$
    On dividing, we get:


    ∴ $\frac{47}{10}$ = 4.7

(ii) $\frac{156}{100}$
On dividing, we get:


∴ $\frac{156}{100}$ = 1.56

(iii) $\frac{2516}{100}$
On dividing, we get:

∴ $\frac{2516}{100}$ = 25.16

(iv) $\frac{3524}{1000}$

On dividing, we get:

∴ $\frac{3524}{1000}$ = 3.524

(v) $\frac{25}{8}$
On dividing, we get:

∴ $\frac{25}{8}$ = 3.125

(vi) $3 \frac{2}{5} = \frac{17}{5}$
On dividing, we get:

∴ $\frac{17}{5}$ = 3.4

(vii) $2 \frac{2}{25} = \frac{52}{25}$
        On dividing, we get:


∴ $\frac{52}{25}$ = 2.08

(viii) $\frac{17}{20}$

       On dividing, we get:



       ∴ $\frac{17}{20}$ = 0.85

Page No 39:

Question 4:

Convert each of the following into like decimals:

(i) 6.5, 16.03, 0.274, 119.4
(ii) 3.5, 0.67, 15.6, 4

Answer:

Converting the given decimals into like decimals, we have:
(i) 6.500, 16.030, 0.274 and 119.400
(ii) 3.50, 0.67, 15.60 and 4.00

Page No 39:

Question 5:

Fill in each of the place holders with the correct symbol > or <.

(i) 78.23 69.85
(ii) 3.406 3.46
(iii) 5.68 5.86
(iv) 14.05 14.005
(v) 1.85 1.805
(vi) 0.98 1.07

Answer:

We have,

(i) Comparing the whole number part, 78 > 69.
Thus, 78.23 > 69.85

(ii) Converting the decimals into like decimals, we get 3.406 and 3.460.
Comparing the whole number parts, 3 = 3
Comparing the tenths digit, 4 = 4
Comparing the hundredths digit, 6 > 0
Thus, 3.406 < 3.46

(iii) Comparing the whole number parts, 5 = 5
Comparing the tenths digit, 6 < 8
Thus, 5.68 < 5.86

(iv) Converting the decimals into like decimals, we get 14.050 and 14.005.
Comparing the whole number parts, 14 = 14
Comparing the tenths digit, 0 = 0
Comparing the hundredths digit, 5 > 0
Thus, 14.05 > 14.005

(v) Converting the decimals into like decimals, we get 1.850 and 1.805.
Comparing the whole number parts, 1 = 1
Comparing the tenths digit, 8 = 8
Comparing the hundredths digit, 5 > 0
Thus, 1.85 > 1.805

(vi) Comparing the whole number parts, 0 < 1
Thus, 0.98 < 1.07

Page No 39:

Question 6:

Arrange the following decimals in ascending order:

(i) 4.6, 7.4, 4.58, 7.32, 4.06
(ii) 0.5, 5.5, 5.05, 0.05, 5.55
(iii) 6.84, 6.48, 6.8, 6.4, 6.08
(iv) 2.2, 2.202, 2.02, 22.2, 2.002

Answer:

(i) Converting the given decimals into like decimals, we get:
     4.60, 7.40, 4.58, 7.32, 4.06
     Clearly, 4.06 < 4.58 < 4.60 < 7.32 < 7.40
     Hence, the given decimals in ascending order are 4.06, 4.58, 4.6, 7.32 and 7.4.

(ii) Converting the given decimals into like decimals, we get:
      0.50, 5.50, 5.05, 0.05, 5.55
      Clearly, 0.05 < 0.50 < 5.05< 5.50 < 5.55
      Hence, the given decimals in ascending order are 0.05, 0.5, 5.05, 5.5 and 5.55.

(iii) Converting the given decimals into like decimals, we get:
        6.84, 6.48, 6.80, 6.40, 6.08
        Clearly, 6.08 < 6.40 < 6.48 < 6.80< 6.84
        Hence, the given decimals in ascending order are 6.08, 6.4, 6.48, 6.8 and 6.84.

(iv) Converting the given decimals into like decimals, we get:
        2.200, 2.202, 2.020, 22.200, 2.002
        Clearly, 2.002 < 2.020 < 2.200 < 2.202 < 22.200
        Hence, the given decimals in ascending order are 2.002, 2.02, 2.2, 2.202 and 22.2.

Page No 39:

Question 7:

Arrange the following decimals in descending order:

(i) 7.4, 8.34, 74.4, 7.44, 0.74
(ii) 2.6, 2.26, 2.06, 2.007, 2.3

Answer:

(i) Converting the given decimals into like decimals, we get:
     7.40, 8.34, 74.40, 7.44, 0.74
     Clearly, 74.40 > 8.34 > 7.44 > 7.40 > 0.74
     Hence, the given decimals in descending order are 74.4, 8.34, 7.44, 7.4 and 0.74.

(ii) Converting the given decimals into like decimals, we get:
      2.600, 2.260, 2.060, 2.007, 2.300
      Clearly, 2.600 > 2.300 > 2.260 > 2.060 > 2.007
      Hence, the given decimals in descending order are 2.6, 2.3, 2.26, 2.06 and 2.007.

Page No 39:

Question 8:

Express 45 mm in cm, m and km.

Answer:

45 mm = $\frac{45}{10}$ cm = 4.5 cm

= 4.5 cm = $\frac{4.5}{100} m$ = 0.045 m

= 0.045 m = $\frac{0.045}{1000} km$ = 0.000045 km

∴ 45 mm = 4.5 cm = 0.045 m = 0.000045 km

Page No 39:

Question 9:

Express as rupees using decimals:

(i) 8 paise
(ii) 9 rupees 75 paise
(iii) 8 rupees 5 paise

Answer:

We have:
(i) 8 paise = Rs $\frac{8}{100}$ = Rs 0.08

(ii) 9 rupees 75 paise = Rs $(9 + \frac{75}{100}) = Rs (9 + 0.75)$ = Rs 9.75

(iii) 8 rupees 5 paise = $Rs (8 + \frac{5}{100}) = Rs (8 + 0.05)$ = Rs 8.05

Page No 39:

Question 10:

Express in km using decimals:

(i) 65 m
(ii) 284 m
(iii) 3 km 5 m

Answer:

We have:

(i) 65 m = $\frac{65}{1000}$ km = 0.065 km
∴ 65 m = 0.065 km

(ii) 284 m = $\frac{284}{1000}$ km = 0.284 km

(iii) 3 km 5 m = $(3 + \frac{5}{1000}) = (3 + 0.005) = 3.005 km$

Page No 41:

Question 1:

Add:

16, 8.7, 0.94, 6.8 and 7.77

Answer:

Converting the given decimals into like decimals, we get:
16.00, 8.70, 0.94, 6.80 and 7.77
Writing these decimals in column form and adding, we get:

Hence, the sum of the given decimals is 40.21

Page No 41:

Question 2:

Add:

18.6, 206.37, 8.008, 26.4 and 6.9

Answer:

Converting the given decimals into like decimals, we get:
18.600, 206.370, 8.008, 26.400 and 6.900
Writing these decimals in column form and adding, we get:

Hence, the sum of the given decimals is 266.278.

Page No 41:

Question 3:

Add:

63.5, 9.7, 0.8, 26.66 and 12.17

Answer:

Converting the given decimals into like decimals, we get:
63.50, 9.70, 0.80, 26.66 and 12.17
Writing these decimals in column form and adding, we get:

Hence, the sum of the given decimals is 112.83.

Page No 41:

Question 4:

Add:

17.4, 86.39, 9.435, 8.8 and 0.06

Answer:

Converting the given decimals into like decimals, we get:
17.400, 86.390, 9.435, 8.800 and 0.060
Writing these decimals in column form and adding, we get:

Hence, the sum of the given decimals is 122.085.

Page No 41:

Question 5:

26.9, 19.74, 231.769 and 0.048

Answer:

Converting the given decimals into like decimals, we get:
26.900, 19.740, 231.769 and 0.048
Writing these decimals in column form and adding, we get:

Hence, the sum of the given decimals is 278.457.

Page No 41:

Question 6:

Add:

23.8, 8.94, 0.078 and 214.6

Answer:

Converting the given decimals into like decimals, we get:
23.800, 8.940, 0.078 and 214.600
Writing these decimals in column form and adding, we get:

Hence, the sum of the given decimals is 247.418.

Page No 41:

Question 7:

Add:

6.606, 66.6, 666, 0.066, 0.66

Answer:

Converting the given decimals into like decimals, we get:
6.606, 66.600, 666.000, 0.066 and 0.660
Writing these decimals in column form and adding, we get:

Hence, the sum of the given decimals is 739.932.

Page No 41:

Question 8:

Add:

9.09, 0.909, 99.9, 9.99, 0.099

Answer:

Converting the given decimals into like decimals, we get:
9.090, 0.909, 99.900, 9.990 and 0.099
Writing these decimals in column form and adding, we get:

Hence, the sum of the given decimals is 119.988.

Page No 41:

Question 9:

Subtract:

14.79 from 72.43

Answer:

The given decimals are like decimals. Writing them in column form with the larger one at the top and subtracting them, we get:

∴ (72.43 − 14.79) = 57.64

Page No 41:

Question 10:

Subtract:

36.74 from 52.6

Answer:

Converting the given decimals into like decimals, we get:
36.74 and 52.60
Writing them in column form with the larger one at the top and subtracting them, we get:

∴ (52.60 − 36.74) = 15.86

Page No 41:

Question 11:

Subtract:

13.876 from 22

Answer:

Converting the given decimals into like decimals, we get:
13.876 and 22.000
Writing them in column form with the larger one at the top and subtracting them, we get:

∴ (22.000 − 13.876) = 8.124

Page No 41:

Question 12:

Subtract:

15.079 from 24.16

Answer:

Converting the given decimals into like decimals, we get:
15.079 and 24.160
Writing them in column form with the larger one at the top and subtracting them, we get:

∴ (24.160 − 15.079) = 9.081

Page No 41:

Question 13:

Subtract:

0.68 from 1.007

Answer:

Converting the given decimals into like decimals, we get:
0.680 and 1.007
Writing them in column form with the larger one at the top and subtracting them, we get:

∴ (1.007 − 0.680) = 0.327

Page No 41:

Question 14:

Subtract:

0.4678 from 5.05

Answer:

Converting the given decimals into like decimals, we get:
0.4678 and 5.0500
Writing them in column form with the larger one at the top and subtracting them, we get:

∴ (5.0500 − 0.4678) = 4.5822

Page No 41:

Question 15:

Subtract:

2.5307 from 8

Answer:

Converting the given decimals into like decimals, we get:
2.5307 and 8.0000
Writing them in column form with the larger one at the top and subtracting them, we get:

∴ (8.0000 − 2.5307) = 5.4693

Page No 41:

Question 16:

Subtract:

6.732 from 9.001

Answer:

Writing the given like decimals in column form with the larger one at the top and subtracting them, we get:

∴ (9.001 − 6.732) = 2.269

Page No 41:

Question 17:

Take out 5.746 from 9.1.

Answer:

Converting the given decimals into like decimals, we get:
5.746 and 9.100
Writing them in column form with the larger one at the top and subtracting them, we get:

∴ (9.100 − 5.746) = 3.354

Page No 41:

Question 18:

What is to be added to 63.58 to get 92?

Answer:

Converting the given decimals into like decimals, we get:
63.58 and 92.00
Thus, required number = (92.00 − 63.58) = 28.42
Hence, 28.42 should be added to 63.58 to get 92.

Page No 41:

Question 19:

What is to be subtracted from 8.1 to get 0.813?

Answer:

Converting the given decimals into like decimals, we get:
8.100 and 0.813
Thus, required number = (8.100 − 0.813) = 7.287
Hence, 7.287 should be subtracted from 8.1 to get 0.813.

Page No 41:

Question 20:

By how much should 32.67 be increased to get 60.1?

Answer:

Converting the given decimals into like decimals, we get:
32.67 and 60.10
Thus, required number = (60.10 − 32.67) = 27.43
Hence, 32.67 should be increased by 27.43 to get 60.1.

Page No 41:

Question 21:

By how much should 74.3 be decreased to get 26.87?

Answer:

Converting the given decimals into like decimals, we get:
74.30 and 26.87
Thus, required number = (74.30 − 26.87) = 47.43
Hence, 74.3 should be decreased by 47.43 to get 26.87.

Page No 41:

Question 22:

Rohit purchased a notebook for Rs 23.75, a pencil for Rs 2.85 and a pen for Rs 15.90. He gave a 50-rupee note to the shopkeeper. What amount did he get back?

Answer:

Total amount spent by Rohit on purchasing of the given articles = Rs (23.75 + 2.85 + 15.90)
= Rs 42.50
Money given to the shopkeeper = Rs 50
∴ Money returned by the shopkeeper = Rs (50 − 42.50)
= Rs 7.50
Thus, amount received by Rohit = Rs 7.50

Page No 43:

Question 1:

Find the product:

(i) 73.92 × 10
(ii) 7.54 × 10
(iii) 84.003 × 10
(iv) 0.83 × 10
(v) 0.7 × 10
(vi) 0.032 × 10

Answer:

We have the following:

(i) 73.92 × 10 = 739.2                 [Shifting the decimal point to the right by 1 place]
(ii) 7.54 × 10 = 75.4                    [Shifting the decimal point to the right by 1 place]
(iii) 84.003 × 10 = 840.03           [Shifting the decimal point to the right by 1 place]
(iv) 0.83 × 10 = 8.3                     [Shifting the decimal point to the right by 1 place]
(v) 0.7 × 10 = 7                           [Shifting the decimal point to the right by 1 place]
(vi) 0.032 × 10 = 0.32                 [Shifting the decimal point to the right by 1 place]

Page No 44:

Question 2:

Find the product:

(i) 2.397 × 100
(ii) 6.83 × 100
(iii) 2.9 × 100
(iv) 0.08 ×100
(v) 0.6 × 100
(vi) 0.003 × 100

Answer:

We have the following:

(i) 2.397 × 100 = 239.7           [Shifting the decimal point to the right by 2 places]
(ii) 6.83 × 100 = 683               [Shifting the decimal point to the right by 2 places]
(iii) 2.9 × 100 = 290                [Shifting the decimal point to the right by 2 places]
(iv) 0.08 ×100 = 8                   [Shifting the decimal point to the right by 2 places]
(v) 0.6 × 100 = 60                   [Shifting the decimal point to the right by 2 places]
(vi) 0.003 × 100 = 0.3             [Shifting the decimal point to the right by 2 places]

Page No 44:

Question 3:

Find the product:

(i) 6.7314 × 1000
(ii) 0.182 × 1000
(iii) 0.076 × 1000
(iv) 6.25 × 1000
(v) 4.8 × 1000
(vi) 0.06 × 1000

Answer:

We have:
(i) 6.7314 × 1000 = 6731.4            [Shifting the decimal point to the right by 3 places]
(ii) 0.182 × 1000 = 182                  [Shifting the decimal point to the right by 3 places]
(iii) 0.076 × 1000 = 76                   [Shifting the decimal point to the right by 3 places]
(iv) 6.25 × 1000 = 6250                  [Shifting decimal point to the right by 3 places]
(v) 4.8 × 1000 = 4800                     [Shifting the decimal point to the right by 3 places]
(vi) 0.06 × 1000 = 60                      [Shifting the decimal point to the right by 3 places]

Page No 44:

Question 4:

Find the product:

(i) 5.4 × 16
(ii) 3.65 × 19
(iii) 0.854 × 12
(iv) 36.73 × 48
(v) 4.125 × 86
(vi) 104.06 × 75
(vii) 6.032 × 124
(viii) 0.0146 × 69
(ix) 0.00125 × 327

Answer:

We have the following:

(i)   54 $\times$ 16 = 864
     ∴ 5.4 $\times$ 16 = 86.4                            [1 place of decimal]

(ii) 365 $\times$ 19 = 6935
       ∴ 3.65 $\times$ 19 = 69.35                      [2 places of decimal]

(iii)  854 $\times$ 12 = 10248
        ∴ 0.854 $\times$ 12 = 10.248                 [3 places of decimal]

(iv)  3673 $\times$ 48 = 176304
       ∴ 36.78 $\times$ 48 = 1763.04                [2 places of decimal]

(v) 4125 $\times$ 86 = 354750
      ∴ 4.125 $\times$ 86 = 354.750            [3 places of decimal]
                           = 354.75

(vi) 10406 $\times$ 75 = 780450
      ∴ 104.06 $\times$ 75 = 7804.50               [2 places of decimal]
                              = 7804.5

(vii)  6032 $\times$ 124 = 747968
        ∴ 6.032 $\times$ 124 = 747.968             [3 places of decimal]

(viii) 146 $\times$ 69 = 10074
∴ 0.0146 $\times$ 69 = 1.0074              [4 places of decimal]

(ix) 125 $\times$ 327 = 40875
       ∴ 0.00125 $\times$ 327 = 0.40875           [5 places of decimal]

Page No 44:

Question 5:

Find the product

(i) 7.6 × 2.4
(ii) 3.45 × 6.3
(iii) 0.54 × 0.27
(iv) 0.568 × 4.9
(v) 6.54 × 0.09
(vi) 3.87 × 1.25
(vii) 0.06 × 0.38
(viii) 0.623 × 0.75
(ix) 0.014 × 0.46
(x) 54.5 × 1.76
(xi) 0.045 × 2.4
(xii) 1.245 × 6.4

Answer:

(i) First, we will multiply 76 by 24.

∴ 76 $\times$ 24 = 1824
Sum of decimal places in the given numbers = (1 + 1) = 2
∴ 7.6 $\times$ 2.4 = 18.24     [2 places of decimal]

(ii) First, we will multiply 345 by 63.

∴ 345 $\times$ 63 = 21735
Sum of decimal places in the given numbers = (2 + 1) = 3
∴ 3.45 $\times$ 6.3 = 21.735     [3 places of decimal]

(iii) First, we will multiply 54 by 27.

∴ 54 $\times$ 27 = 1458
Sum of decimal places in the given numbers = (2 + 2) = 4
∴ 0.54 $\times$ 0.27 = 0.1458    [4 places of decimal]

(iv) First, we will multiply 568 by 49.

∴ 568 $\times$ 49 = 27832
Sum of decimal places in the given numbers = (3 + 1) = 4
∴ 0.568 $\times$ 4.9 = 2.7832    [4 places of decimal]

(v) First, we multiply 654 by 9.

∴ 654 $\times$ 9 = 5886
Sum of decimal places in the given numbers = (2 + 2) = 4
∴ 6.54 $\times$ 0.09 = 0.5886     [4 places of decimal]

(vi) First, we will multiply 387 by 125.

∴ 387 $\times$ 125 = 48375
Sum of decimal places in the given numbers = (2 + 2) = 4
∴ 3.87 $\times$ 1.25 = 4.8375    [4 places of decimal]

(vii) First, we will multiply 38 by 6.

∴ 38 $\times$ 6 = 228
Sum of decimal places in the given numbers = (2 + 2) = 4
∴ 0.06 $\times$ 0.38 = 0.0228    [4 places of decimal]

(viii) First, we will multiply 623 by 75.

∴ 623 $\times$ 75 = 46725
Sum of decimal places in the given numbers = (3 + 2) = 5
∴ 0.623 $\times$ 0.75 = 0.46725    [5 places of decimal]

(ix) First, we will multiply 14 by 46.

∴ 14 $\times$ 46 = 644
Sum of decimal places in the given numbers = (3 + 2) = 5
∴ 0.014 $\times$ 0.46 = 0.00644    [5 places of decimal]

(x) First, we will multiply 545 by 176.

∴ 545 $\times$ 176 = 95920
Sum of decimal places in the given numbers = (1 + 2) = 3
∴ 54.5 $\times$ 1.76 = 95.920 [3 places of decimal]
                       = 95.92

(xi) First, we will multiply 45 by 24.

∴ 45 $\times$ 24 = 1080
Sum of decimal places in the given numbers = (3 + 1) = 4
∴ 0.045 $\times$ 2.4 = 0.1080    [4 places of decimal]
                       = 0.108

(xii) First, we will multiply 1245 by 64.

∴ 1245 $\times$ 64 = 79680
Sum of decimal places in the given numbers = (3 + 1) = 4
∴ 1.245 $\times$ 6.4 = 7.9680   [4 places of decimal]
                       = 7.968

Page No 44:

Question 6:

Find the product:

(i) 13 × 1.3 × 0.13
(ii) 2.4 × 1.5 × 2.5
(iii) 0.8 × 3.5 × 0.05
(iv) 0.2 × 0.02 × 0.002
(v) 11.1 × 1.1 × 0.11
(vi) 2.1 × 0.21 × 0.021

Answer:

(i) First, we will find the product 13 ⨯ 1.3 ⨯ 0.13.
     Now, 13 ⨯ 13 ⨯ 13 = 169 x 13
= 2197

     Sum of decimal places in the given numbers = (1 + 2) = 3
     So, the product must have three decimal places.

∴ 13 ⨯ 1.3 ⨯ 0.13 = 2.197

(ii) First, we will find the product 2.4 ⨯ 1.5 ⨯ 2.5.
     Now, 24 ⨯ 15 ⨯ 25 = 360 x 25
                                   = 9000

     Sum of decimal places in the given numbers = (1 + 1 + 1) = 3
     So, the product must have three decimal places.

     ∴ 2.4 ⨯ 1.5 ⨯ 2.5 = 9.000
                                 = 9

(iii) First, we will find the product 0.8 ⨯ 3.5 ⨯ 0.05.
       Now, 8 ⨯ 35 ⨯ 5 = 280 ⨯ 5
                                 = 1400

       Sum of decimal places in the given numbers = (1 + 1 + 2) = 4
       So, the product must have four decimal places.

∴ 0.8 ⨯ 3.5 ⨯ 0.05 = 0.1400
                                     = 0.14

(iv) First, we will find the product 0.2 ⨯ 0.02 ⨯ 0.002.
       Now, 2 ⨯ 2 ⨯ 2 = 4 ⨯ 2
                                = 8
       Sum of decimal places in the given numbers = (1 + 2 + 3) = 6
       So, the product must have six decimal places.

∴ 0.2 ⨯ 0.02 ⨯ 0.002 = 0.000008

(v) First, we will find the product 11.1 ⨯ 1.1 ⨯ 0.11.
       Now, 111 ⨯ 11 ⨯ 11 = 1221 ⨯ 11
                                       = 13431

       Sum of decimal places in the given numbers = (1 + 1 + 2) = 4
       So, the product must have four decimal places.

       ∴ 11.1 ⨯ 1.1 ⨯ 0.11 = 1.3431

(vi) First, we will find the product 2.1 ⨯ 0.21 ⨯ 0.021.
       Now, 21 ⨯ 21 ⨯ 21 = 441 ⨯ 21
                                     = 9261

       Sum of decimal places in the given numbers = ( 1 + 2 + 3) = 6
       So, the product must have six decimal places.

       ∴ 2.1 ⨯ 0.21 ⨯ 0.021 = 0.009261

Page No 44:

Question 7:

Evaluate:

(i) (1.2)²
(ii) (0.7)²
(iii) (0.04)²
(iv) (0.11)²

Answer:

(i) (1.2)² = 1.2 $\times$ 1.2
     First, we will find the product 1.2 $\times$ 1.2.
     Now, 12 $\times$ 12 = 144
     Sum of decimal places in the given numbers = (1 + 1) = 2
     So, the product must have two decimal places.

     ∴ (1.2)² = 1.2 $\times$ 1.2 = 1.44

(ii) (0.7)² = 0.7 $\times$ 0.7
      First, we will find the product 0.7 $\times$ 0.7.
      Now, 7 $\times$ 7 = 49
      Sum of decimal places in the given numbers = (1 + 1) = 2
      So, the product must have two decimal places.
      ∴ (0.7)² = 0.7 $\times$ 0.7 = 0.49

(iii) (0.04)² = 0.04 $\times$ 0.04
       First, we will find the product 0.04 $\times$ 0.04.
       Now, 4 $\times$ 4 = 16
       Sum of decimal places in the given numbers = (2 + 2) = 4
       So, the product must have four decimal places.
       ∴ (0.04)² = 0.04 $\times$ 0.04 = 0.0016

(iv) (0.11)² = 0.11 $\times$ 0.11
       First, we will find the product 0.11 $\times$ 0.11.
       Now, 11 $\times$ 11 = 121
       Sum of decimal places in the given numbers = ( 2 + 2) = 4
       So, the product must have four decimal places.
∴ (0.11)² = 0.11 $\times$ 0.11 = 0.0121

Page No 44:

Question 8:

Evaluate:

(i) (0.3)³
(ii) (0.05)³
(iii) (1.5)³

Answer:

(i) (0.3)³ = 0.3 $\times$ 0.3 $\times$ 0.3
     First, we will find the product 3 $\times$ 3 $\times$ 3.
     Now, 3 $\times$ 3 $\times$ 3 = 27
     Sum of decimal places in the given numbers = (1 + 1 + 1) = 3
     So, the product must have three places of decimal.
     ∴ (0.3)³= 0.3 $\times$ 0.3 $\times$ 0.3 = 0.027

(ii) (0.05)³ = 0.05 $\times$ 0.05 $\times$ 0.05
     First, we will find the product 5 $\times$ 5 $\times$ 5.
     Now, 5 $\times$ 5 $\times$ 5 = 125
     Sum of decimal places in the given numbers = (2 + 2 + 2) = 6
     So, the product must have six decimal places.
     ∴ (0.05)³ = 0.05 $\times$ 0.05 $\times$ 0.05 = 0.000125

(iii) (1.5)³ = 1.5 $\times$ 1.5 $\times$ 1.5
       First, we will find the product 15 $\times$ 15 $\times$ 15.
       Now, 15 $\times$ 15 $\times$ 15 = 225 $\times$ 15 = 3375

       Sum of decimal places in the given numbers = (1 + 1 + 1) = 3
       So, the product must have three decimal places.
       ∴ (1.5)³ = 1.5 $\times$ 1.5 $\times$ 1.5 = 3.375

Page No 44:

Question 9:

A bus can cover 62.5 km in one hour. How much distance can it cover in 18 hours?

Answer:

Distance covered by the bus in 1 hour = 62.5 km
∴ Distance covered in 18 hours = (62.5 $\times$ 18) km
= 1125 km
Hence, the bus can cover a distance of 1125 km in 18 hours.

Page No 44:

Question 10:

A tin of oil weighs 16.8 kg. What is the weight of 45 such tins?

Answer:

Weight of 1 tin of oil = 16.8 kg
∴ Weight of 45 such tins = (16.8 $\times$ 45) kg
= 756 kg
Hence, the weight of 45 tins of oil is 756 kg.

Page No 44:

Question 11:

A bag of wheat weighs 97.8 kg. How much wheat is contained in 500 such bags?

Answer:

Weight of 1 bag of wheat = 97.8 kg
∴ Weight of 500 such bags = (97.8 x 500) kg
= 48900 kg
Hence, the weight of 500 bags of wheat is 48900 kg.

Page No 44:

Question 12:

Find the weight of 16 bags of sugar, each weighing 48.450 kg.

Answer:

Weight of 1 bag of sugar = 48.450 kg
∴ Weight of 16 bags of sugar = (48.450 ⨯ 16) kg
= 775.2 kg

Hence, the weight of 16 bags of sugar is 775.2 kg.

Page No 44:

Question 13:

A small bottle holds 0.845 kg of sauce. How much sauce will be there in 72 such bottles?

Answer:

Capacity of 1 sauce bottle = 0.845 kg
∴ Capacity of 72 such bottles = (0.845 $\times$ 72) kg
= 60.84 kg

Hence, the capacity of 72 bottles of sauce will be 60.84 kg.

Page No 44:

Question 14:

A bottle holds 925 g of jam. How many kg of jam will be there in 25 such bottles?

Answer:

Weight of 1 bottle of jam = 925 g =0.925 kg
∴ Weight of 25 such bottles = (0.925 $\times$ 25) kg
= 23.125 kg

∴ The weight of 25 bottles of jam will be 23.125 kg.

Page No 44:

Question 15:

If one drum can hold 16.850 litres of oil, how many litres can 48 such drums hold?

Answer:

Capacity of 1 drum of oil = 16.850 litres
∴ Capacity of 48 such drums = (16.850 x 48) litres
= 808.800 litres

Hence, the capacity of 48 drums of oil is 808.800 litres.

Page No 44:

Question 16:

1 kg of rice costs Rs 56.80. What is the cost of 16.25 kg of rice?

Answer:

Cost of 1 kg of rice =Rs 56.80
∴ Cost of 16.25 kg of rice = Rs (56.80 $\times$ 16.25)
= Rs 923

Hence, the cost of 16.25 kg of rice is Rs 923.

Page No 44:

Question 17:

1 metre of cloth costs Rs 108.50. What is the cost of 18.5 metres of this cloth?

Answer:

Cost of 1 m of cloth = Rs 108.50
∴ Cost of 18.5 m of cloth = Rs (108.50 x 18.5)
= Rs 2007.25

Hence, the cost of 18.5 m of cloth is Rs 2007.25.

Page No 44:

Question 18:

A car can cover a distance of 8.6 km on one litre of petrol. How far can it go on 36.5 litres of petrol?

Answer:

Distance covered by the car with 1 litre of petrol = 8.6 km
∴ Distance covered with 36.5 litres of petrol = (8.6 $\times$ 36.5) km
= 313.900 km
Hence, the distance covered by the car with 36.5 litres of petrol is 313.900 km.

Page No 44:

Question 19:

A taxi driver charges Rs 9.80 per km. How much will he charge for a journey of 106.5 km?

Answer:

Charges for 1 km = Rs 9.80
∴ Charges for 106.5 km = Rs (9.80 $\times$ 106.5)
= Rs 1043.70
Hence, the taxi driver will charge Rs 1043.70 for a journey of 106.5 km.

Page No 49:

Question 1:

Divide:

(i) 131.6 by 10
(ii) 32.56 by 10
(iii) 4.38 by 10
(iv) 0.34 by 10
(v) 0.08 by 10
(vi) 0.062 by 10

Answer:

We have the following:

(i) 131.6 ÷ 10 = $\frac{131.6}{10} = 13.16$                 [Shift the decimal point to the left by 1 place]

(ii) 32.56 ÷ 10 = $\frac{32.56}{10} = 3.256$                     [Shift the decimal point to the left by 1 place]

(iii) 4.38 ÷ 10 = $\frac{4.38}{10} = 0.438$                        [Shift the decimal point to the left by 1 place]

(iv) 0.34 ÷ 10 = $\frac{0.34}{10} = 0.034$                        [Shift the decimal point to the left by 1 place]

(v) 0.08 ÷ 10 = $\frac{0.08}{10} = 0.008$                         [Shift the decimal point to the left by 1 place]

(vi) 0.062 ÷ 10 = $\frac{0.062}{10} = 0.0062$                  [Shift the decimal point to the left by 1 place]

Page No 49:

Question 2:

Divide:

(i) 137.2 by 100
(ii) 23.4 by 100
(iii) 4.7 by 100
(iv) 0.3 by 100
(v) 0.58 by 100
(vi) 0.02 by 100

Answer:

We have the following:

(i) 137.2 ÷ 100 = $\frac{137.2}{100} = 1.372$                           [Shifting the decimal point to the left by 2 places]

(ii) 23.4 ÷ 100 = $\frac{23.4}{100} = 0.234$                               [Shifting the decimal point to the left by 2 places]

(iii) 4.7 ÷ 100 = $\frac{4.7}{100} = 0.047$                                [Shifting the decimal point to the left by 2 places]

(iv) 0.3 ÷ 100 = $\frac{0.3}{100} = 0.003$                                [Shifting the decimal point to the left by 2 places]

(v) 0.58 ÷ 100 = $\frac{0.58}{100} = 0.0058$                            [Shifting the decimal point to the left by 2 places]

(vi) 0.02 ÷ 100 = $\frac{0.02}{100} = 0.0002$                         [Shifting the decimal point to the left by 2 places]

Page No 49:

Question 3:

Divide:

(i) 1286.5 by 1000
(ii) 354.16 by 1000
(iii) 38.9 by 1000
(iv) 4.6 by 1000
(v) 0.8 by 1000
(vi) 2 by 1000

Answer:

We have the following:

(i) 1286.5 ÷ 1000 = $\frac{1286.5}{1000} = 1.2865$              [Shift the decimal point to the left by 3 places]

(ii) 354.16 ÷ 1000 = $\frac{354.16}{1000} = 0.35416$               [Shift the decimal point to the left by 3 places]

(iii) 38.9 ÷ 1000 = $\frac{38.9}{1000} = 0.0389$                       [Shift the decimal point to the left by 3 places]

(iv) 4.6 ÷ 1000 = $\frac{4.6}{1000} = 0.0046$                         [Shift the decimal point to the left by 3 places]

(v) 0.8 ÷ 1000 = $\frac{0.8}{1000} = 0.0008$                          [Shift the decimal point to the left by 3 places]

(vi) 2 ÷ 1000 = $\frac{2}{1000} = 0.002$                          [Shift the decimal point to the left by 3 places]

Page No 49:

Question 4:

Divide:

(i) 12 by 8
(ii) 63 by 15
(iii) 47 by 20
(iv) 101 by 25
(v) 31 by 40
(vi) 11 by 16

Answer:

(i) 12 ÷ 8 = $\frac{12}{8} = \frac{3}{2}$


∴ 12 ÷ 8 = 1.5

(ii) 63 ÷ 15 = $\frac{63}{15} = \frac{21}{5}$

   ∴ 63 ÷ 15 = 4.2

(iii) 47 ÷ 20 = $\frac{47}{20}$

        ∴ 47 ÷ 20 = 2.35

(iv) 101 ÷ 25 = $\frac{101}{25}$

       ∴ 101 ÷ 25 = 4.04

(v ) 31 ÷ 40


    ∴ 31 ÷ 40 = 0.775

(vi) 11 ÷ 16 = $\frac{11}{16}$


       ∴ 11 ÷ 16 = 0.6875

Page No 49:

Question 5:

Divide:

(i) 43.2 by 6
(ii) 60.48 by 12
(iii) 117.6 by 21
(iv) 217.44 by 18
(v) 2.575 by 25
(vi) 6.08 by 8
(vii) 0.765 by 9
(viii) 0.768 by 16
(ix) 0.175 by 25
(x) 0.3322 by 11
(xi) 2.13 by 15
(xii) 6.54 by 12
(xiii) 5.52 by 16
(xiv) 1.001 by 14
(xv) 0.477 by 18

Answer:

(i) We have:
      43.2 ÷ 6

       ∴ 43.2 ÷ 6 = 7.2
(ii) We have:
       60.48 ÷ 12

        ∴ 60.48 ÷ 12 = 5.04

(iii) We have:
        117.6 ÷ 21

      ∴ 117.6 ÷ 21 = 5.6

(iv) We have:
        217.44 ÷ 18

     ∴ 217.44 ÷ 18 = 12.08

(v) We have:
      2.575 ÷ 25

       ∴ 2.575 ÷ 25 = 0.103

(vi) We have:
       6.08 ÷ 8

      ∴ 6.08 ÷ 8 = 0.76

(vii) We have:
        0.765 ÷ 9

       ∴ 0.765 ÷ 9 = 0.085

(viii) We have:
          0.768 ÷ 16

      ∴ 0.768 ÷ 16 = 0.048
(ix) We have:
        0.175 ÷ 25

$= \frac{0.175}{25} = \frac{0.175 \times 1000}{25 \times 1000} = \frac{175}{25 \times 1000} = \frac{7}{1000} = 0.007$

(x) We have:
      0.3322 ÷ 11

     ∴ 0.3322 ÷ 11 = 0.0302

(xi) We have:
       2.13 ÷ 15

     ∴ 2.13 ÷ 15 = 0.142

(xii) We have:
         6.54 ÷ 12

      ∴ 6.54 ÷ 12 = 0.545

(xiii) We have:
         5.52 ÷ 16

     ∴ 5.52 ÷ 16 = 0.345

(xiv) We have:
         1.001 ÷ 14

    ∴ 1.001 ÷ 14 = 0.0715

(xv) We have:
       0.477 ÷ 18

        ∴ 0.477 ÷ 18 = 0.0265

Page No 49:

Question 6:

Divide:

(i) 16.46 ÷ 20
(ii) 403.8 ÷ 30
(iii) 19.2 ÷ 80
(iv) 156.8 ÷ 200
(v) 12.8 ÷ 500
(vi) 18.08 ÷ 400

Answer:

(i) 16.46 ÷ 20 = $\frac{16.46}{20} = \frac{16.46 \times 100}{20 \times 100} = \frac{1646}{2 \times 1000} = \frac{823}{1000} = 0.823$

(ii) 403.8 ÷ 30 = $\frac{403.8}{30} = \frac{403.8 \times 10}{30 \times 10} = \frac{4038}{3 \times 100} = \frac{1346}{100} = 13.46$

(iii) 19.2 ÷ 80 = $\frac{19.2}{80} = \frac{19.2 \times 10}{80 \times 10} = \frac{192}{800} = \frac{192}{8 \times 100} = \frac{24}{100} = 0.24$

(iv) 156.8 ÷ 200 = $\frac{156.8}{200} = \frac{156.8 \times 10}{200 \times 10} = \frac{1568}{2000} = \frac{784}{1000} = 0.784$

(v) 12.8 ÷ 500 = $\frac{12.8}{500} = \frac{12.8 \times 10}{500 \times 10} = \frac{128}{5000} = \frac{25.6}{1000} = 0.0256$

(vi) 18.08 ÷ 400 = $\frac{18.08}{400} = \frac{18.08 \times 100}{400 \times 100} = \frac{1808}{40000} = \frac{452}{10000} = 0.0452$

Page No 49:

Question 7:

Divide:

(i) 3.28 by 0.8
(ii) 0.288 by 0.9
(iii) 25.395 by 1.5
(iv) 2.0484 by 0.18
(v) 0.228 by 0.38
(vi) 0.8085 by 0.35
(vii) 21.976 by 1.64
(viii) 11.04 by 1.6
(ix) 6.612 by 11.6
(x) 0.076 by 0.19
(xi) 148 by 0.074
(xii) 16.578 by 5.4
(xiii) 28 by 0.56
(xiv) 204 by 0.17
(xv) 3 by 80

Answer:

(i) 3.28 ÷ 0.8 = $\frac{3.28}{0.8} = \frac{3.28 \times 10}{0.8 \times 10} = \frac{32.8}{8}$
Now, we have:


       ∴ $\frac{3.28}{0.8} = \frac{32.8}{8} = 4.1$

(ii)  0.288 ÷ 0.9 = $\frac{0.288}{0.9} = \frac{0.288 \times 10}{0.9 \times 10} = \frac{2.88}{9}$
Now, we have:


      ∴ $\frac{0.288}{0.9} = \frac{2.88}{9} = 0.32$

(iii)  25.395 ÷ 1.5 = $\frac{25.395}{1.5} = \frac{25.395 \times 10}{1.5 \times 10} = \frac{253.95}{15}$
Now, we have:


       ∴ $\frac{25.395}{1.5} = \frac{253.95}{15} = 16.93$

(iv) 2.0484 ÷ 0.18 = $\frac{2.0484}{0.18} = \frac{2.0484 \times 100}{0.18 \times 100} = \frac{204.84}{18}$
Now, we have:


     ∴ $\frac{2.0484}{0.18} = \frac{204.84}{18} = 11.38$

(v) 0.228 ÷ 0.38 = $\frac{0.228}{0.38} = \frac{0.228 \times 100}{0.38 \times 100} = \frac{22.8}{38}$
Now, we have:


     ∴ $\frac{0.228}{0.38} = \frac{22.8}{38} = 0.6$

(vi) 0.8085 ÷ 0.35 = $\frac{0.8085}{0.35} = \frac{0.8085 \times 100}{0.35 \times 100} = \frac{80.85}{35}$
Now, we have:


      ∴ $\frac{0.8085}{0.35} = \frac{80.85}{35} = 2.31$

(vii) 21.976 ÷ 1.64 = $\frac{21.976}{1.64} = \frac{21.976 \times 100}{1.64 \times 100} = \frac{2197.6}{164}$
Now, we have:

        ∴ $\frac{21.976}{1.64} = \frac{2197.6}{164} = 13.4$

(viii) 11.04 ÷ 1.6 = $\frac{11.04}{1.6} = \frac{11.04 \times 10}{1.6 \times 10} = \frac{110.4}{16}$
Now, we have:


       ∴ $\frac{11.04}{1.6} = \frac{110.4}{16} = 6.9$

(ix)  6.612 ÷ 11.6 = $\frac{6.612}{11.6} = \frac{6.612 \times 10}{11.6 \times 10} = \frac{66.12}{116}$
Now, we have:

       ∴ $\frac{6.612}{11.6} = \frac{66.12}{116} = 0.57$

(x) 0.076 ÷ 0.19 = $\frac{0.076}{0.19} = \frac{0.076 \times 100}{0.19 \times 100} = \frac{7.6}{19}$
Now, we have:

    ∴ $\frac{0.076}{0.19} = \frac{7.6}{19} = 0.4$

(xi) 48 ÷ 0.074

$= \frac{148}{0.074} = \frac{148 \times 1000}{0.074 \times 1000} = \frac{148000}{74} = 2 \times 1000 = 2000$

(xii)  16.578 ÷ 5.4 = $\frac{16.578}{5.4} = \frac{16.578 \times 10}{5.4 \times 10} = \frac{165.78}{54}$
Now, we have:


        ∴ $\frac{16.578}{5.4} = \frac{165.78}{54} = 3.07$

(xiii)  28 ÷ 0.56

$= \frac{28}{0.56} = \frac{28 \times 100}{0.56 \times 100} = \frac{2800}{56} = \frac{1 \times 100}{2} = 50$

(xiv) 204 ÷ 0.17

$= \frac{204}{0.17} = \frac{204 \times 100}{0.17 \times 100} = \frac{20400}{17} = 12 \times 100 = 1200$

(xv) 3 ÷ 80 = $\frac{3}{80}$

Now, we have:


       ∴ $\frac{3}{80}$ = 0.0375

Page No 50:

Question 8:

The total cost of 24 chairs is Rs 9255.60. Find the cost of each chair.

Answer:

Cost of 24 chairs = Rs 9255.60
∴ Cost of one chair = Rs $(\frac{9255.60}{24})$
= Rs $(\frac{9255.60 \times 10}{24 \times 10})$
= Rs $(\frac{92556}{240})$
= Rs 385.65

Hence, the cost of one chair is Rs 385.65.

Page No 50:

Question 9:

1.8 m of cloth is required for a shirt. How many such shirts can be made from a piece of cloth 45 m long?

Answer:

Cloth required for 1 shirt = 1.8 m
∴ Number of shirts that can be made from 45 m of cloth = $\frac{45}{1.8}$ = $\frac{15}{0.6}$ = $\frac{5}{0.2}$ = $\frac{50}{2}$ = 25

Hence, 25 shirts can be made from a piece of cloth of length 45 m.

Page No 50:

Question 10:

A car covers a distance of 22.8 km in 2.4 litres of petrol. How much distance will it cover in 1 litre of petrol?

Answer:

Distance covered by the car with 2.4 litres of petrol = 22.8 km
∴ Distance covered with 1 litre of petrol = $(\frac{22.8}{2.4})$ km
= $(\frac{228}{24})$ km = $(\frac{228 \div 12}{24 \div 12})$ km = $(\frac{19}{2})$ km = $9 \frac{1}{2}$ km

Hence, the distance covered by the car with 1 litre of petrol is $9 \frac{1}{2}$ km.

Page No 50:

Question 11:

A tin holds 16.5 litres of oil. How many such tins will be required to hold 478.5 litres of oil?

Answer:

Capacity of 1 tin of oil = 16.5 litres
∴ Number of tins required to hold 478.5 litres of oil = $(\frac{478.5}{16.5}) = (\frac{4785}{165}) = (\frac{4785 \div 15}{165 \div 15}) = \frac{319}{11} = 29$
Hence, 29 oil tins will be required to hold 478.5 litres of oil.

Page No 50:

Question 12:

The weight of 37 bags of sugar is 3644.5 kg. If all the bags weigh equally, what is the weight of each bag?

Answer:

Weight of 37 bags of sugar = 3644.5 kg
∴ Weight of 1 bag of sugar = $(\frac{3644.5}{37})$ = 98.5 kg

Hence, each bag of sugar weighs 98.5 kg.

Page No 50:

Question 13:

If 69 buckets of equal capacity can be filled with 586.5 litres of water, what is the capacity of eacch bucket?

Answer:

Capacity of 69 buckets of water = 586.5 litres
∴ Capacity of one such bucket = $(\frac{586.5}{69})$ litres = 8.5 litres.

Hence, the capacity of each water bucket is 8.5 litres.

Page No 50:

Question 14:

Monica cuts 46 m of cloth into peices of 1.15 m each. How many pieces does she get?

Answer:

Length of one piece of cloth = 1.15 m
∴ Number of pieces she gets from 46 m of cloth = $(\frac{46}{1.15})$
= $(\frac{46 \times 100}{1.15 \times 100})$ = $(\frac{4600}{115})$ = 40

Hence, Monica has 40 pieces of cloth each of length 1.15 m.

Page No 50:

Question 15:

Mr Soni bought some bags of cement, each weighing 49.8 kg. If the total weight of all the bags is 1792.8 kg, how many bags did he buy?

Answer:

Total weight of all the bags of cement = 1792.8 kg
Weight of each bag = 49.8 kg
Number of bags = $(\frac{Total weight}{Weight of each bag})$
= $(\frac{1792.8}{49.8}) = (\frac{17928}{498}) = 36$

Hence, Mr. Soni bought 36 bags of cement.

Page No 50:

Question 16:

How many pieces of plywood, each 0.35 cm thick, are required to make a pile 1.89 m high?

Answer:

Thickness of the pile of plywood pieces = 1.89 m = 189 cm
Thickness of one piece of plywood = 0.35 cm
∴ Required number of plywood pieces = $(\frac{189}{0.35}) = (\frac{189 \times 100}{0.35 \times 100}) = (\frac{18900}{35}) = 540$

Hence, 540 pieces of plywood are required to make a pile of height 1.89 m.

Page No 50:

Question 17:

The product of two decimals is 261.36. If one of them is 17.6, find the other.

Answer:

Product of the given decimals = 261.36
One decimal = 17.6
The other decimal = 261.36 ÷ 17.6
= $(\frac{261.36}{17.6}) = (\frac{261.36 \times 10}{17.6 \times 10}) = (\frac{2613.6}{176})$
= 14.85

Hence, the other decimal is 14.85.

Page No 50:

Question 1:

Mark (✓) against the correct answer
.06 = ?

(a) $\frac{3}{5}$
(b) $\frac{3}{50}$
(c) $\frac{3}{500}$
(d) none of these

Answer:

(b) $\frac{3}{50}$

0.06 = $\frac{6}{100} = \frac{3}{50}$

Page No 50:

Question 2:

Mark (✓) against the correct answer
1.04 = ?

(a) $1 \frac{1}{5}$
(b) $1 \frac{2}{5}$
(c) $1 \frac{1}{25}$
(d) none of these

Answer:

Page No 50:

Question 3:

Mark (✓) against the correct answer
$2 \frac{2}{25} = ?$

(a) 2.8
(b) 2.08
(c) 2.008
(d) none of these

Answer:

(b) 2.08

$2 \frac{2}{25} = \frac{52}{25}$

On dividing, we get:

∴ $2 \frac{2}{25} = \frac{52}{25}$ = 2.08

Page No 50:

Question 4:

Mark (✓) against the correct answer
6 cm = ?

(a) 0.006 km
(b) 0.0006 km
(c) 0.00006 km
(d) none of these

Answer:

Page No 50:

Question 5:

Mark (✓) against the correct answer
70 g = ?

(a) 0.7 kg
(b) 0.07 kg
(c) 0.007 kg
(d) none of these

Answer:

(b) 0.07 kg

70 g = $\frac{70}{1000}$ kg = $\frac{7}{100}$ kg

= 0.07 kg

∴ 70 g = 0.07 kg

Page No 50:

Question 6:

Mark (✓) against the correct answer
5 kg 6 g = ?

(a) 5.0006 kg
(b) 5.06 kg
(c) 5.006 kg
(d) 5.6 kg

Answer:

Page No 50:

Question 7:

Mark (✓) against the correct answer
2 km 5 m = ?

(a) 2.5 km
(b) 2.05 km
(c) 2.005 km
(d) 2.0005 km

Answer:

Page No 50:

Question 8:

Mark (✓) against the correct answer
(1.007 − 0.7) = ?

(a) 1
(b) 0.37
(c) 0.307
(d) none of these

Answer:

(c) 0.307

Converting the given decimals into like decimals, we get:
1.007 and 0.700
Writing them in column form with the larger one at the top and subtracting, we get:

Hence, the required number is 0.307.

Page No 50:

Question 9:

Mark (✓) against the correct answer
What should be subtracted from .1 to get .03?

(a) .7
(b) .07
(c) .007
(d) none of these

Answer:

(b) .07

We have:
0.1 − x = 0.03
⇒ x = 0.1 − 0.03

Converting the given decimals into like decimals, we get:
0.10 and 0.03

Writing them in column form with the larger one at the top and subtracting, we get:

∴ x = 0.07
Hence, the required number is 0.07.

Page No 51:

Question 10:

Mark (✓) against the correct answer
What should be added to 3.07 to get 3.5?

(a) .57
(b) .34
(c) .43
(d) .02

Answer:

(c) .43
We have:
3.07 + x = 3.5
⇒ x = 3.5 − 3.07
Converting the given decimals into like decimals, we get:
3.07 and 3.50
Writing them in column form with the larger one at the top and subtracting, we get:

∴ x = 0.43

Hence, 0.43 should be added to 3.07 to get 3.5.

Page No 51:

Question 11:

Mark (✓) against the correct answer
0.23 × 0.3 = ?

(a) 0.69
(b) 6.9
(c) 0.069
(d) none of these

Answer:

(c) 0.069
First, we will multiply 23 by 3.
i.e., 23 $\times$ 3 = 69
Sum of decimal places in the given decimals = (2 + 1) = 3
∴ 0.23 $\times$ 0.3 = 0.069 ( 3 places of decimal)

Page No 51:

Question 12:

Mark (✓) against the correct answer
0.02 × 30 = ?

(a) 6
(b) 0.6
(c) 0.06
(d) none of these

Answer:

(b) 0.6
We have:
2 $\times$ 30 = 60
∴ 0.02 $\times$ 30 = 0.60 (2 places of decimal)
= 0.6

Page No 51:

Question 13:

Mark (✓) against the correct answer
0.25 × 0.8 = ?

(a) 0.02
(b) 0.2
(c) 0.002
(d) 2

Answer:

(b) 0.2
First, we will multiply 25 by 8.
∴ 25 $\times$ 8 = 200
Sum of decimal places in the given decimals = (2 + 1) = 3
∴ 0.25 $\times$ 0.8 = 0.200 [3 places of decimal]
= 0.2

Page No 51:

Question 14:

Mark (✓) against the correct answer
0.4 × 0.4 × 0.4 = ?

(a) 6.4
(b) .64
(c) .064
(d) none of these

Answer:

(c) .064

First, we will find the product 4 $\times$ 4 $\times$ 4 = 64
Sum of decimal places in the given decimals = (1 + 1 + 1) = 3
∴ 0.4 × 0.4 × 0.4 = 0.064 ( 3 places of decimal)

Page No 51:

Question 15:

Mark (✓) against the correct answer
1.1 × .1 ×.01 = ?

(a) .011
(b) .0011
(c) .11
(d) none of these

Answer:

(b) .0011

First, we will find the product 11 $\times$ 1 $\times$ 1.
Sum of decimal places in the given decimals = (1 + 1 + 2) = 4
∴ 1.1 $\times$ 0.1 $\times$ 0.01 = 0.0011 (4 places of decimal)

Page No 51:

Question 16:

Mark (✓) against the correct answer
2.08 ÷ (.16) = ?

(a) 13
(b) .13
(c) 1.3
(d) none of these

Answer:

(a) 13

2.08 ÷ 0.16 = $\frac{2.08}{0.16}$ = $\frac{2.08 \times 100}{0.16 \times 100}$ = $\frac{208}{16} = 13$

Page No 51:

Question 17:

Mark (✓) against the correct answer
1.02 ÷ 6 = ?

(a) 1.7
(b) 0.17
(c) 0.017
(d) none of these

Answer:

(b) 0.17

1.02 ÷ 6 = $\frac{1.02}{6} = \frac{1.02 \times 100}{6 \times 100} = \frac{102}{6 \times 100} = \frac{17}{100} = 0.17$

Page No 51:

Question 18:

Mark (✓) against the correct answer
30.94 ÷ 0.7 = ?

(a) 44.2
(b) 4.42
(c) 442
(d) 0.442

Answer:

(a) 44.2

30.94 ÷ 0.7 = $\frac{30.94}{0.7} = \frac{30.94 \times 100}{0.7 \times 100} = \frac{3094}{70} = 44.2$

Page No 51:

Question 19:

Mark (✓) against the correct answer
2.73 ÷ 1.3 = ?

(a) 21
(b) 2.1
(c) 0.21
(d) none of these

Answer:

(b) 2.1

2.73 ÷ 1.3 = $\frac{2.73}{1.3} = \frac{2.73 \times 100}{1.3 \times 100} = \frac{273}{13 \times 10} = \frac{21}{10} = 2.1$

Page No 51:

Question 20:

Mark (✓) against the correct answer
89.1 ÷ 2.2 = ?

(a) 40.5
(b) 4.05
(c) 41
(d) 41.5

Answer:

(a) 40.5

89.1 ÷ 2.2 = $\frac{89.1}{2.2} = \frac{89.1 \times 10}{2.2 \times 10} = \frac{891}{22} = 40.5$

Page No 51:

Question 21:

Mark (✓) against the correct answer
0.5 × 0.05 = ?

(a) 0.25
(b) 2.5
(c) 0.025
(d) none of these

Answer:

(c) 0.025
First, we will multiply 5 by 5.
i.e., 5 $\times$ 5 = 25
Sum of decimal places in the given decimals = (1 + 2) = 3
∴ 0.5 × 0.05 = 0.025 (3 places of decimal)

Page No 53:

Question 1:

If the cost of a pen is Rs 32.50, find the cost of 24 such pens.

Answer:

Cost of 1 pen = Rs 32.50
∴ Cost of 24 such pens = Rs (32.50 $\times$ 24)
= Rs 780
Hence, the cost of 24 pens is Rs 780.

Page No 53:

Question 2:

A bus can cover 64.5 km in an hour. How much distance can it cover in 18 hours?

Answer:

Distance covered by the bus in 1 h = 64.5 km
∴ Distance covered in 18 h = (64.5 $\times$ 18) km
= 1161 km

Hence, the bus can cover a distance of 1161 km in 18 h.

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Question 3:

Find the product 0.68 × 6.5 × 0.04.

Answer:

First, we will find the product 68 $\times$ 65 $\times$ 4.
Now, 68 $\times$ 65 $\times$ 4 = 4420 $\times$ 4 = 17680
Sum of decimal places in the given decimals = (2 + 1 + 2) = 5
So, the product have five decimal places.

∴ 0.68 $\times$ 6.5 $\times$ 0.04 = 0.17680
= 0.1768

Page No 53:

Question 4:

Each bag of cement weighs 48.5 kg. How many such bags will weigh 2231 kg?

Answer:

Total weight of all the bags = 2231 kg
Weight of each bag = 48.5 kg

Number of bags = $\frac{Total weight}{Weight of each bag}$

= $(\frac{2231}{48.5})$ kg

= $(\frac{2231 \times 10}{48.5 \times 10}) = \frac{22310}{485} = 46$

Hence, 46 bags of cement will weigh 2231 kg.

Page No 53:

Question 5:

Divide:

(i) 0.196 by 1.4
(ii) 39.168 by 1.2
(iii) 0.228 by 0.38

Answer:

(i) 0.196 ÷ 1.4 = $\frac{0.196}{1.4} = \frac{0.196 \times 10}{1.4 \times 10} = \frac{1.96}{14} = 0.14$



(ii) 39.168 ÷ 1.2 = $\frac{39.168}{1.2} = \frac{39.168 \times 10}{1.2 \times 10} = \frac{391.68}{12} = 32.64$



(iii) 0.228 ÷ 0.38 = $\frac{0.228}{0.38} = \frac{0.228 \times 100}{0.38 \times 100} = \frac{22.8}{38} = 0.6$

Page No 53:

Question 6:

The product of two decimals is 1.824. If one of them is 0.64, find the other.

Answer:

Product of the given decimals = 1.824
One decimal = 0.64
The other decimal = 1.824 ÷ 0.64
= $\frac{1.824}{0.64} = (\frac{1.824 \times 100}{0.64 \times 100}) = \frac{182.4}{64} = 2.85$

Hence, the other decimal is 2.85.

Page No 53:

Question 7:

How many pieces of plywood, each of 0.45 cm thick, are required to make a pile 2.43 m high?

Answer:

Thickness of the pile of plywoods = 2.43 m = 2.43 $\times$ 100 cm = 243 cm
Thickness of one piece of plywood = 0.45 cm
∴ Required number of pieces of plywood = $\frac{243}{0.45} = \frac{243 \times 100}{0.45 \times 100} = \frac{24300}{45} = 540$

Hence, the required number of pieces of plywood is 540.

Page No 53:

Question 8:

Each side of a polygon is 3.8 cm in length and its perimeter is 22.8 cm. How many sides does the polygon have?

Answer:

Let the number of sides of the polygon be n.
Length of each side of the polygon = 3.8 cm
∴ Perimeter of the polygon = (3.8 $\times$ n) cm
But it is given that its perimeter is 22.8 cm.
∴ (3.8 $\times$ n) cm = 22.8 cm
⇒ n = $(\frac{22.8}{3.8})$ = $\frac{228}{38}$ = 6

Hence, the given polygon has six sides.

Page No 53:

Question 9:

Mark (✓) against the correct answer
$2 \frac{1}{25} = ?$

(a) 2.4
(b) 2.04
(c) 2.004
(d) none of these

Answer:

(b) 2.04

$2 \frac{1}{25} = \frac{51}{25} = 2.04$

Page No 53:

Question 10:

Mark (✓) against the correct answer
1.008 = ?

(a) $1 \frac{2}{25}$
(b) $1 \frac{1}{125}$
(c) $1 \frac{2}{125}$
(d) none of these

Answer:

(b) $1 \frac{1}{125}$

1.008 = $\frac{1.008 \times 1000}{1 \times 1000} = \frac{1008}{1000} = \frac{1008 \div 4}{1000 \div 4} = \frac{126}{125} = 1 \frac{1}{125}$

Page No 53:

Question 11:

Mark (✓) against the correct answer
2 kg 5 g = ?

(a) 2.5 kg
(b) 2.05 kg
(c) 2.005 kg
(d) none of these

Answer:

Page No 53:

Question 12:

Mark (✓) against the correct answer
0.12 ÷ .15 = ?

(a) 0.8
(b) 0.08
(c) 0.008
(d) none of these

Answer:

(b) 0.08

We have:
0.012 ÷ 0.15 = $\frac{0.012}{0.15} = \frac{0.012 \times 100}{0.15 \times 100} = \frac{1.2}{15} = 0.08$

Page No 53:

Question 13:

Mark (✓) against the correct answer
1.1 × .1 × .01 = ?

(a) .11
(b) .011
(c) .0011
(d) none of these

Answer:

(c) .0011
First, we will find the product 11 $\times$ 1 $\times$ 1.
i.e., 11 $\times$ 1 $\times$ 1 = 11 $\times$ 1 = 11
Sum of decimal places in the given decimals = (1 + 1 + 2) = 4

∴ 1.1 $\times$ 0.1 $\times$ 0.01 = 0.0011 [4 places of decimal]

Page No 53:

Question 14:

Mark (✓) against the correct answer
4.669 ÷ 2.3 = ?

(a) 2.3
(b) 2.03
(c) 2.003
(d) none of these

Answer:

(b) 2.03

4.669 ÷ 2.3 = $(\frac{4.669}{2.3}) = (\frac{4.669 \times 10}{2.3 \times 10}) = (\frac{46.69}{23}) = 2.03$

Page No 53:

Question 15:

Mark (✓) against the correct answer
What should be added to 2.06 to get 3.1?

(a) 1.4
(b) 1.24
(c) 1.04
(d) none of these

Answer:

Option (c) is correct.
Let the number added be x.
We have:
2.06 + x = 3.1
⇒ x = 3.1 − 2.06

Converting the given decimals into like decimals, we get:
2.06 and 3.10
Thus, required number = (3.10 − 2.06) = 1.04

Hence, 1.04 should be added to 2.06 to get 3.1.

Page No 53:

Question 16:

Mark (✓) against the correct answer
What should be subtracted from .1 to get .04?

(a) 0.6
(b) 0.06
(c) 0.006
(d) none of these

Answer:

(b) 0.06
We have:
0.1 − x = 0.04
⇒ x = 0.1 − 0.04
Converting the given decimals into like decimals, we get:
0.10 and 0.04
Thus, required number = (0.10 − 0.04) = 0.06
Hence, 0.06 should be subtracted from 0.1 to get 0.04.

Page No 53:

Question 17:

Fill in the blanks.

(i) 1.001 ÷ 14 = ......
(ii) 204 ÷ 0.17 = ......
(iii) 0.47 × 5.3 = ......
(iv) 0.023 × 0.03 = ......
(v) (0.7)² = ......
(vi) (0.05)³ = ......

Answer:

(i) 1.001 ÷ 14 = 0.0715

     Explanation: $\frac{1.001}{14} = 0.0715$


(ii) 204 ÷ 0.17 = 1200

      Explanation: $\frac{204}{0.17} = \frac{204 \times 100}{0.17 \times 100} = \frac{204 \times 100}{17} = 12 \times 100 = 1200$

(iii) 0.47 × 5.3 = 2.491

       Explanation: First, we will multiply 47 by 53.

        ∴ 47 $\times$ 53 = 2491
        Sum of decimal places in the given decimals = (2 + 1) = 3
        ∴ 0.47 × 5.3 = 2.491

(iv) (0.7)² = 0.49
        Explanation: (0.7)² = 0.7 × 0.7
        First, we will find the product 0.7 × 0.7.
        Now, 7 × 7 = 49
        Sum of decimal places in the given decimals = (1 + 1) = 2
        So, the product must have two decimal places.
        ∴ (0.7)² = 0.7 × 0.7 = 0.49

(v) (0.05)³ = 0.000125
      Explanation: First, we will find the product 0.05 × 0.05 × 0.05.
      Now, 5 × 5 × 5 = 125
      Sum of decimal places in the given decimals = (2 + 2 + 2) = 6
      So, the product must have six decimal places.
      ∴ (0.05)³ = 0.05 × 0.05 × 0.05 = 0.000125

Page No 53:

Question 18:

Write 'T' for true and 'F' for false

(i) 0.5 × 0.05 = 0.25
(ii) 0.25 × 0.8 = 0.2
(iii) 0.35 ÷ 0.7 = 0.5
(iv) .4 × .4 × .4 = 0.64
(v) 6 cm = 0.06 m

Answer:

(i) T
We have:
0.5 × 0.05
Now, 5 × 5 = 25
Sum of decimal places in the given decimals = ( 1 + 2) = 3
∴ 0.5 × 0.05 = 0.025

(ii) T
We have:
0.25 × 0.8
Now, 25 × 8 = 200
Sum of decimal places in the given decimals = (2 +1) = 3
∴ 0.25 × 0.8 =0.200 = 0.2

(iii) T
We have:
0.35 ÷ 0.7 = $\frac{0.35}{0.7} = \frac{0.35 \times 10}{0.7 \times 10} = \frac{3.5}{7} = 0.5$

(iv) F
We have:
0.4 × 0.4 × 0.4
Now, 4 × 4 × 4 = 64
Sum of decimal places in the given decimals = (1 +1 +1) = 3
∴ 0.4 × 0.4 × 0.4 = 0.064

(v) T
6 cm = $(\frac{6}{100})$ m = 0.06 m

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